HNO3 Lewis Structure, Characteristics: 47 Complete Quick Facts

image 252

This article should contain the HNO3 lewis structure and its different important facts. Let’s discuss the HNO3 lewis structure.

In the HNO3 lewis structure, the molecule is consist of N, H, and three O atoms. All the atoms in the HNO3 lewis structure make a covalent bond. The N is the HNO3 lewis structure is sp2 hybridized while O is sp3 hybridized. There is one -OH group and two ketonic groups are present. Due to the presence of that -the OH group makes the molecule acidic. The electronegativity of O and N is so high that make that H is more acidic.

HNO3 or Nitric acid is one of the strongest inorganic acids. The aqua regia is made from this acid. The structure of the HNO3 is different because here two central are different hybridization. Around the N it is trigonal planar and around the O it is tetrahedral.

Some important facts about HNO3

The physical state of nitric acid is liquid. The color of the nitric acid is colorless but when it is stored for a long time its color changed to yellowish due to the decomposition of oxide of nitrogen. The boiling point and the melting point of Nitric acid are 356 K and 231 K respectively. The molar mass of this acid is 63.012 g/mol. The odor of nitric acid is acidic and very suffocating. The density of this acid is 1.51 g/cm3. Fuming nitric acid has vapor pressure and the value is 48 mmHg at 200C.

It can be produced by the reaction of water and nitrogen dioxide.

4 NO2 + 2 H2O → 2 HNO3 + NO + NO2 + H2O

The net reaction is,

3 NO2 + H2O → 2 HNO3 + NO

Nitrogen dioxide bubble goes through the hydrogen peroxide improving the yield of the product.

2 NO2 + H2O2 → 2 HNO3

In the laboratory, nitric acid can be prepared by the thermal decomposition of copper nitrate to produce nitrogen dioxide and that nitrogen dioxide then reacted to water to get nitric acid.

2 Cu(NO3)2 → 2 CuO + 4 NO2 + O2

2 NO2 + H2O → HNO2 + HNO3

The above process is called the Ostwald process.

Nitric acid can behave as a strong oxidizing agent.  To incorporate the nitro group in any organic synthesis nitric acid is used widely.

1.    How to draw the HNO3 lewis structure?

The HNO3 lewis structure is quite different from the other covalent molecule because it has two central atoms one is N and the other is an O atom. N and O both are p block elements, so they have to follow the octet rule in the drawing of the HNO3 lewis structure. Let us consider the HNO3 lewis structure.

Step 1 – In the first step of the HNO3 lewis structure, we should count the valence electrons for every atom present in it. The electronic configuration of H is 1s1. So it has only one electron and this electron is used for its valence electron and via this single electron, H can form a bond. We know O is the group 6thelement and p block element so its last orbital should be p orbital and the electronic configuration of O is [He]2s22p4. So it has six electrons in its valence shell which can be used for bond formation.

Now for N, the electronic configuration is [He]2s22p3, so it has five electrons in its valence shell and the maximum number of bonds N can form is four. Now we add all the valence electrons in the HNO3 lewis structure and the total valence electrons for the HNO3 lewis structure is, 1+5+(6*3) = 24 electrons. There are three O atoms present and each O contains six valence electrons.

Step 2 – Now it is a most confusing step, that here we select the central atom, here N and O both are present at the central position and the electronegativity difference between both is very less. In the HNO3 lewis structure, all the atoms are not connected through N or O atoms, but the central atom should connect all the atoms.

That’s why here N and one O are considered central atoms and for this reason, we have to calculate the hybridization for two atoms separately and the values of hybridization of two atoms are different. Two atoms are experiences different environments.

Step 3 – In the HNO3 lewis structure, all the atoms are from the s and p block, so they should follow the octet rule. For the s block element, they try to complete only their s orbital because s is their valence orbital. the total number of electrons accumulated by the s orbital is 2.  For p orbital, the total electrons accumulated is 6.

Now, according to the octet rule, the electrons needed for the HNO3 lewis structure are 2+(4*8) = 34 electrons. But the valence electrons in the HNO3 lewis structure is, 24, so the shortage of electrons is 34-24 = 10 electrons. These 10 electrons should be accumulated in the number of suitable bonds. So the bonds needed 10/2 = 5 bonds. So there is a minimum of five bonds are needed. To assign the five bonds we need to add a double bond between N and O.

Step 4 – In this step, we should connect every atom in the HNO3 lewis structure via the required number of bonds. There is one bond between terminal H and O, one bond between O of -OH group and N. then other three bonds are used between N and two O atoms, and there is a double bond between one O and N atoms.

Step 5 – In this last step, we add lone pairs and multiple bonds to complete the valency of atoms.  O has six electrons in its valence shell and it forms two bonds, one with H and one with N, so it has four unpaired electrons which exist as two pairs of lone pairs. Other O atoms which form a double bond with N, it has the same four electrons in their valence shell and they exist as two pairs of lone pairs. The last O which makes a single bond with N forms a dative bond and six electrons exist after one bond formation so it gets a negative charge and two pairs of lone pairs.

2.    HNO3 lewis structure shape

The shape of the molecule is dependent on the electron count and based on the central atom, but in the HNO3 lewis structure, there are two central atoms one is N and the other is O. for N the shape of the molecule is planar but concerning O the shape of the molecule is tetrahedral. The electron density is different for two atoms and the shape of the HNO3 lewis structure.

image 253
HNO3 Shape

The HNO3 lewis structure in the gaseous form is planar. The same structure is also for a solid-state. The N-O bond distance in the nitro group is equal. The third N-O bond distance is longer and corresponds to a single bond. We know Nitro is a variable structure and there is a double bond character shown between two O and N atoms. The nitro group is tilted away from the H atoms by 20.

If we consider the VSEPR(Valence Shell Electrons Pair Theory), then we should count the electrons and consider the structure. But here the structure is different for different atoms. For the -OH oxygen their electron count is 8 including two lone pairs, so according to the VSEPR, it adopts a tetrahedral shape. But for the nitro group electron count is 6 so it adopts trigonal planar structure, where three o atoms are present in three vertices.

3.    HNO3 valence electrons

For calculating the total valence electrons for the HNO3 lewis structure, we should count individual valence electrons for each atom. There are three O atoms, one N and one h atom are present. The environment of three N atoms is different and therefore their valence electrons are also different.

image 254
HNO3 Valence Electrons

From the electronic configuration of N it is evident that there are five electrons are present at the valence shell in N. O is group 6thelement so it has six electrons in its valence shell which are ready for bond formation. But O forms only one bond with N and the rest of the two electrons exist as lone pairs. H has only one electron and this one electron is the valence electron for the H atom.

So the total number of valence electrons of the HNO3 lewis structure is 1+5+(6*3) = 24 electrons.

4.    HNO3 lewis structure lone pairs

In the HNO3 lewis structure, only lone pairs are available on the O atoms, N forms a dative bond with O in the nitro group then it has lone pairs otherwise not.

For counting the lone pairs, we have to check the available electrons in the valence shell of every atom after bond formation. H has only one electron, so H can’t contain lone pair. Now O has six electrons in its valence shell and after two sigma bond formation, it has the remaining four electrons. These four electrons exist as two pairs of lone pairs over O in the -OH groups.

image 255
HNO3 Lone Pairs

For the nitro groups, there are two O atoms present in the HNO3 lewis structure, One O is formed a double bond with N to complete the octet, so it has four electrons and again the same case arises. This O atom has two pairs of lone pairs. Now the other O atoms form a variable bond with N, there is not possible for two double bonds for N, because N cannot show pentavalent, so there is only one possible way that O makes a single bond with N or forms a dative bond.

A dative bond is a coordination covalent bond. The electron density is reside more towards the O site. That O also carries a negative charge and contains three pairs of lone pairs. Accounting for N is contain a positive charge.  

So the total number of lone pairs over the HNO3 lewis structure is 2+2+3=7 pairs of lone pairs, otherwise, six pairs of lone pairs if they do not form a dative bond.

5.      HNO3 lewis structure formal charge

From the HNO3 lewis structure, we can say that there is a charge present over N and O in the nitro group. By calculating the formal charge, the charge over every atom should be predicted. It is a hypothetical concept accounting for the same electronegativity of each atom in the HNO3 lewis structure.

The formula we can use to calculate the formal charge, F.C. = Nv – Nl.p. -1/2 Nb.p.

Where Nv is the number of electrons in the valence shell or outermost orbital, Nl.p is the number of electrons in the lone pair, and Nb.p  is the total number of electrons that are involved in the bond formation only.

The environment of three O atoms should be different so, we have to calculate the formal charge individually for all the atoms.

The formal charge over the H atom is, 1-0-(2/2) = 0

The formal charge over the O atom in -OH group = 6-4-(4/2) = 0

The formal charge over the N atom is, 5-1-(8/2) = 0

The formal charge over the O in the nitro group is, 6-4-(4/2) = 0

From the formal charge calculation, we cannot say that there is a dative bond between N and O in the nitro group. Overall the molecule is neutral.

6.    HNO3 lewis structure angle

The bond angle of the HNO3 lewis structure is different due to two different central atoms and two shapes of the molecule being present. The hybridization of two atoms is different and the environment is also different. So, in the HNO3 lewis structure, there is two bond angles are observed concerning N and O atoms.

image 256
HNO3 Bond Angle

For the Nitro group in the HNO3 lewis structure, there is only three atoms are present surrounding the central N atom, and there are no lone pairs over the N atom. According to the VSEPR theory, if the molecule AX3 is without lone pair over the central atom, then the bond angle should be 1200. But here the lone pairs of three O atoms are present.

So if the bond angle goes 1200, then there is massive lone pairs-lone pair repulsion occurs. So to minimize this kind of repulsion, N changed its bond angle to 1120. This value is also for the presence of three electronegative atoms and the s character of the hybridization value increases.

Now for the other O atom, there is one H and one N atom are present surrounding that O atom. There are also two pairs of lone pairs present. So this shape is similar to a water molecule, like a V shape, so the bond angle is nearly 1040, because of lone pairs repulsion and the presence of one electronegative atom N.

7.    HNO3 lewis structure octet rule

In the HNO3 lewis structure, there are s and p block elements present, so they have to follow the octet rule. The octet rule for s block elements is completing the s orbital via two electrons and for p block elements they complete their octet via eight electrons. Because p orbital can accumulate a maximum number of six electrons.

image 257
HNO3 Octet

In the HNO3 lewis structure, we should check each atom to complete its octet. The H atom has only one electron in its s orbital and it needs one more electron to complete its octet. Via the bond formation with the O atom, H and O share one electron each, and therefore H can complete its octet via the one electron from the O site.

Now for the O of -OH group, it has six electrons in its valence shell, as it is the group 6th element. So it required two more electrons in its valence shell to complete its octet. Now this O makes a bond with H and N atoms sharing two electrons. So it completes its octet by gaining two electrons from N and O, which are shared in the bond formation.

Now N has five electrons in its valence shell and it needs three more electrons in its valence shell to complete its octet. So it makes a bond with three O atoms and shares three electrons with them. Now N can complete its octet too via gaining those three electrons from three O atoms which are shared in the bond formation.

Two O atoms of the nitro group make a double bond at a time with the N atom and hence they can complete their octet too, via sharing two-electron in the double bond.

8.    HNO3 lewis structure resonance

In the HNO3 lewis structure resonance will be observed because there more electron clouds are present within the molecule, which can be delocalized over the different skeleton forms of the HNO3 lewis structure. The molecule shows a positive and negative charge within it and there is more number of lone pairs present, so they can be delocalized, because the octet of the N and ketonic O is not complete somehow.

image 258
HNO3 Resonating Structure

all the above three structures are different skeleton forms of HNO3 lewis structure or we can say that they area resonating structure. Among the three, structure I and structure II are similar, the negative charge dispersed over the two O atoms in the nitro group. These two structure is most contributing because all three structure contains the same number of covalent bond, but in these two structure the most electronegative atom O gets a negative charge and the less electronegative atom N gets a positive charge.

In structure III, the number of covalent bonds is the same but here N gets a positive charge is ok but O also gets a positive charge which is a destabilization factor. O is a more electronegative atom and the positive charge over it is a destabilization factor.

9.    HNO3 hybridization

The hybridization of the HNO3 lewis structure is different because it has two central atoms and we should predict the hybridization of two central atoms individually. The energy of 1s orbital of H and 2p orbital of O is not equivalent so they undergo hybridization to form equivalent orbital. Similarly, the N atom also undergoes hybridization from a hybrid orbital with three O atoms.

We calculate the hybridization of the HNO3 lewis structure  by using the following formula,

H = 0.5(V+M-C+A), where H= hybridization value, V is the number of valence electrons in the central atom, M = monovalent atoms surrounded, C=no. of cation, A=no. of the anion.

When we find the hybridization of N in the HNO3 lewis structure, there are three electrons for N and three O atoms are present at the surrounding position.

So, the hybridization of central N in the HNO3 lewis structure is ½(3+3+0+0) = 3 (sp2)

For the O atoms, the valence electrons are 6 and one N and one H atom are present.

So the hybridization of O in the HNO3 lewis structure is, ½(6+2+0+0) =4 (sp3)

Structure           Hybridization value     State of hybridization of central atom            Bond angle
Linear      2 sp /sd / pd            1800
Planner trigonal   3 sp2                   1200
Tetrahedral     4 sd3/ sp3                 109.50
Trigonal bipyramidal 5 sp3d/dsp3            900 (axial), 1200(equatorial)
Octahedral         6 sp3d2/ d2sp3      900
Pentagonal bipyramidal 7 sp3d3/d3sp3                   900,720

  

From the above table of hybridization, we can conclude that if the hybridization value is 4 then the central atoms is sp3 hybridized and if the number of orbitals are involved in hybridization is three then the atoms is sp2 hybridized.

Let’s understand the hybridization of N and O atoms separately.

image 259
Hybridization of N

It is evident from the hybridization diagram that we cannot consider the π bond in the hybridization. We consider only the sigma bond with O atoms, N forms a three-sigma bond with three O atoms undergoing sp2 hybridization. S orbital cannot participate in multiple bond formation, so we consider p orbital electron for forming a double bond.

image 260
Hybridization of O

From the hybridization diagram, we can tell that the lone pairs over the O atoms are also involved in the hybridization. For this reason, the shape around that O atom is tetrahedral and this also interns the value of the bond angle is near 109.50.

10. HNO3 solubility

In the HNO3 lewis structure, we can say that there is charge separation observed and this makes the molecule slightly polar and ionic, so it can soluble in a different polar solvent. HNO3 is a very good solvent for different metals.  It forms aqua regia, which is a good solvent for the soluble gold metal. HNO3 is soluble in the following solvents,

  • Benzene
  • Ethanol
  • Water
  • CCl4

11. Is HNO3 soluble in water?

In the HNO3 lewis structure, we see some polarity in this molecule, so it is soluble in a polar solvent. HNO3 is not soluble in water directly, it is miscible in water, the density of water and HNO3 is different but it has a polar character and is ionized in water and gets miscible in an aqueous solution.

12. Is HNO3 polar or nonpolar?

The presence of different atoms and the shape of the HNO3 lewis structure make the molecule polar. Although the electronegativity of N and O is almost close the electronegativity of ketonic Oxygen and alcoholic Oh is different. The shape of the molecule concerning N is planar but concerning O it is tetrahedral and due to its unsymmetric shape it makes the molecule polar. Due to the unsymmetric structure, the dipole moment of the molecule is not canceled out and the molecule has some resultant dipole moment.

image 261
HNO3 Dipole-Moment

The direction of the dipole moment is from N to O, as N gets a positive charge and the electropositivity is increased here and O gets a negative charge, and the electronegativity increases, and for this reason, the difference between electronegativity is higher and dipole moment works. from the structure, we can say the dipole moment is not canceled out or not exactly opposite to each other. So it has a valid dipole-moment value and makes the HNO3 lewis structure polar.

13. Is HNO3 an electrolyte?

Yes HNO3 is an electrolyte it dissolves in water and makes the aqueous solution ionic.

14. Is HNO3 a strong electrolyte?

HNO3 is a strong electrolyte, cause when it gets solvated in an aqueous solution is it ionized in H+ and nitrates ions. The mobility of the H+ ion is very high and for this reason, the HNO3 lewis structure is a strong electrolyte.

15. is HNO3 acidic or basic?

HNO3 is strongly acidic, when it is dissolved in water it released H+ ions easily and makes a stronger acidic.

16. Is HNO3 a strong acid?

HNO3 is a strong acid, it can release H+ ion easily because there is an electronegative O atom is present and for the electronegativity, it pulls electron density toward itself and making O-H bonds weaker and H+ easily cleaved, if a molecule release H+ easily then the acidic nature of this molecule is very high and making a stronger acid.

17. Is HNO3 an arrhenius acid?

If a molecule gives H+ ion then it is called Arrhenius acid and HNO3 easily releases an H+ ion, so HNO3 is an Arrhenius acid.

18. Is HNO3 a lewis acid?

HNO3 can acts as lewis acid because it can accept electron density in N atom because it is positively charged.

19. Is HNO3 stronger than HNO2?

HNO3 is a stronger acid than HNO2 because the conjugate base of HNO3 is NO3- which is more stabilized due to conjugation as compared to the conjugate base of HNO2, which is NO2-. So more stable the conjugate base stronger the acid is.

20. Is HNO3 stronger than H2SO4?

HNO3 is less strong than H2SO4, as H2SO4 is dibasic acid and also the conjugate base of H2SO4 is SO42-, which is a more stable conjugate base due to better overlap between O and S as compared to the conjugate base of HNO3, which is NO3-. SO HNO3 is a weaker acid than H2SO4.

21. Is HNO3 a conjugate acid?

No HNO3 is itself an acid and it is not a conjugate acid of another molecule.

22. Is HNO3 a conjugate base?

HNO3 is an acid, so it has a conjugate base and the conjugate base of HNO3 is NO3-, which is more stable and makes the HNO3 stronger acid.

23. Is HNO3 diprotic?

There is one hydrogen atom present and it can be donated, so HNO3 is monoprotic, not diprotic.

24. Is HNO3 binary or ternary?

HNO3 is a ternary oxoacid.

25. Is HNO3 a buffer?

When HNO3 reacts with a weak base then it can form a buffer of strong acid, otherwise, it is an acid.

26. Is HNO3 a salt?

HNO3 is an acid and when it reacts with a strong base then it forms salt and water molecule.

27. Is HNO3 conductive?

HNO3 is a conductive agent when it is soluble in water it can carry electricity.

28. Is HNO3 corrosive?

HNO3 is highly corrosive.

29. Is HNO3 hydrogen bonding?

There is no H bonding observed in the HNO3 structure.

30. Is HNO3 linear?

HNO3 is not linear it is planar and tetrahedral in shape.

31. Is HNO3 paramagnetic or diamagnetic?

HNO3 has only one unpaired electron over the N atom and it is paramagnetic.

32. Is HNO3 amphoteric?

HNO3 is a strong acid and donates H+ ions only so it is not amphoteric.

33. Is HNO3 a dehydrating agent?

HNO3 is a dehydrating agent, it can remove water molecules.

34. Is HNO3 gas?

The physical state of HNO3 is liquid.

35. Is HNO3 electrophile?

The nitronium ion in HNO3 acts as an electrophile.

36. Is HNO3 hygroscopic?

The dilute HNO3 is hygroscopic but the concentrated form is not.

37. Does HNO3 have a charge?

HNO3 is not a charged molecule but there is a negative charge dispersed between ketonic groups in HNO3.

38. Is HNO3 heavier than air?

The density of HNO3 is much higher than in air.

39. Is HNO3 liquid or aqueous?

The physical state of HNO3 is liquid.

40. Is HNO3 monobasic?

HNO3 has one replacable H+ ion is present so it is monobasic acid.

41. Is HNO3 acid metal?

No HNO3 is not a metallic compound.

42. Is HNO3 an oxidizing agent?

In HNO3 the oxidation number of N is high and it can be decreased so it behaves as a stronger oxidizing agent.

43. Is HNO3 radical

No, HNO3 is not radical, it can be ionized.

44. Is HNO3 a reagent?

Yes in organic synthesis it uses as a nitro group incorporated reagent.

45. Is HNO3 triatomic?

Yes HNO3 is triatomic as it contains N, O, and H atoms.

46. Is HNO3 volatile?

Yes, it is more volatile than H2SO4.

47. why HNO3 is yellow?

When HNO3 lasted for a long time, then oxide of N is deposited and for this reason, the color of HNO3 is yellow.

Conclusion

HNO3 is a monobasic strong acid in liquid form. It is used as a reagent in different chemical syntheses.

Also Read:

Gold Structure, Characteristics:31 Complete Quick Facts

image 241

In this article, we discuss a rare transition metal gold structure and its 31st characteristics. Let’s talk about the expensive transition metal gold and its important facts.

Gold is a common chemical name its Latin name is Aurum and denoted by Au. Gold is d block transition group 11th element. It is a 5d element and due to transition metal gold structure shows metallic property and it obeys the crystal field theory. In gold structure, there is 6s orbital is present and due to the 6s orbital, it shows abnormal behavior which comes from relativistic contraction.

The electronic configuration of gold structure is [Xe]4f145d106s1, so the most stable oxidation form of gold is Au(III) because in that form it has complete f orbital and gains the most stable form. Gold can form different organometallic molecules as its bonding is quite similar to 3d elements.

Some important facts about gold

Gold is present in the earth’s crust so, it is extracted mainly cyanide process. The gold ore goes through dilute sodium cyanide solution to make the alkaline with lime water presence of air for oxidation purposes.

4Au + 8NaCN + 2H2O +O2 =  4Na[Au(CN)2] + 4NaOH

The solution is then filtered and gold is deposited from the filtrate by zinc shavings.

Zn +2Na[Au(CN)2] = 2Au + Na2[Zn(CN)2]

The zinc is dissolved out by dilute sulfuric acid and then it dried residue of gold is melted under the borax.

The crude gold is not pure, it contains copper, silver, and sometimes lead also. The lead part is removed by the process called cupellation. The copper part is removed by oxidative fusion with borax and nitrate. The silver part may be removed by boiling with concentrated sulfuric acid up to when silver is deposited.

The best method to extract gold from crude is electrolytic refining using a solution of HAuCl4 and crude gold deposit at an anode.

Amalgamation is also a method to separate the native gold from alluvial sand. In this method, we separate the mercury part from the alluvial sand to get pure gold.

The melting point and boiling point of gold are 1337.33 K and 3243 K respectively. Due to heavy metals, the energy required for breaking the interstitial bond is high. The color of gold is metallic yellow. Its ΔH atomization is 380 KJ/mol. The density of gold is 19.32 g/mol so we can see that it is a much heavier element.

The electrical resistivity at 200C is 2.35 ohm-cm. the electronegativity is 2.4 at the Pauling scale so it is seen that gold has an affinity toward electronegativity, as Au is stable due to a complete 6s orbital. The first, second, and third ionization energy of a gold structure is 890, 1973, and 2895 kJ/mol as electrons are released from s, d orbitals.

1.    What is the gold structure?

The gold structure is FCC (face-centered cubic), in the solid-state which is also known for its characteristic color. Even the metallic yellow color of the gold structure arises due to absorption in the near UV region.

gold structure
Lattice Structure of Gold

The color of the gold structure is for the excitation of electrons from the d band to the s-p conduction band which is absorbed in the blue region of color. In the FCC structure, net number of atoms = 8*1/8 +6*1/2 =1+3 =4.

In the FCC structure, we know the , so % of occupied space = (4*4/3πr3)/a3 *100

So, for FCC % of occupied space is 74.05%, so the % of void space is 25.95 and it is proved that FCC is the most tightly packed cube system.

2.    Is gold a transition metal?

Gold is group 11th element and belongs to the d block 5d element, so gold is a transition metal. Transition metals are those which have partially filled or filled d electrons in any oxidation state. From the electronic configuration of gold, it is evident that it has filled 5d orbitals, and up to +1 oxidation state, its d orbital is filled.

As gold is a transition element then it shows transition metal properties like CFT. The most stable oxidation state of the gold structure in bond formation is +2. The +2 oxidation state of the gold structure is the d9 system and shows different CFT properties.

In the gold structure, Crystal field theory gold is splitting in square planner geometry. Because gold has filled d electron and f electrons also, for those electrons the effective nuclear charge of Gold structure is highly increased and the interaction between gold and other ligands also increases in such a way that gold structure split in a square planner manner. Actually, the CFT value is increasing from 3d-4d-5d orbitals.

image 241
CFT of Au(II)

There are five subsets in d orbitals, they are dxy, dyz, dxz, dx2y2, and dz2. These five sets are categorized in two different forms according to their energy. First, three are called t2g, and later two are called eg. the eg set of orbitals are directly involved in the bond formation with ligands, so eg has higher energy than t2g.

The electronic configuration of the gold structure is, [Xe]4f145d106s1, so in Au(II) two electrons lacking from the gold structure, and gold releases one electron from the  6s orbital and another one from the 5d orbital. So now in 5d orbitals, there are nine electrons in Au(II) system.

Those nine electrons are arranged in the five subsets, so the last subset of dx2y2 gets only one electron and the other gets paired. Now in the crystal field theory, the energy difference between t2g and eg is called the 10Dq value, by this value, we can predict the stability of the gold structure.

After full splitting, the energy of dxy will energize in such a way that it crosses the barycentre and reaches dx2y2. So, now the energy difference between  dx2y2 and dxy is equal to the 10Dq value.

The energy of each t2g orbital is -0.4Δ0 and the energy of each orbital of eg is -0.6Δ0. only these two orbitals are contributed to the crystal field stabilization energy because other orbitals do not contribute toward the 10Dq value. There is one electron in dx2y2 orbital and two electrons in dxy orbital. So, the net crystal field stabilization energy of gold structure in its +2 oxidation state is, 1*(-0.6Δ0) + 2*(-0.4Δ0) = -.2 Δ0. The negative sign indicates the stabilization of the gold structure.

Gold structure always forms a low spin complex with any kind of ligands. Because the effective nuclear charge is higher for gold structure due to the presence of d and f electrons and for this reason metal- ligands interaction will be high and therefore the Δ0 value also increases and the complex formation occurs with a low spin of the metal center.

Au(II) complexes are a d9 system having 2-fold ground state degeneracy, hence it is subject to extensive tetragonal distortion according to the Jahn teller theorem and by s-d mixing it will be elongated- the complex becomes a square planner. In this square planner geometry, the Δ0 value is very high and it is, and for this reason, the sole electron from the dx2-y2 orbital may be readily lost – leading to the formation of Au(III) complex – the process leads to a decrease in energy in splitting diagram.

The electron lost from one Au(II) complex molecule may be readily accepted by the neighboring complex Au(II) molecule, the latter is reduced to a corresponding Au(I) complex. This process is also favored since there will be an additional stabilization of the d10 configuration which is exchange energy. Thus the net reaction is the disproportionation of Au(II) complex from Au(I) and Au(III).

3.    Is gold a compound?

Gold is a transition metal and a group 11th element, but it can form different compounds because it can show different oxidation states.

Au(III) compound

In gold structure, Au(III) is the most common oxidation state of golf, in this oxidation state it can form different binary compounds and complexes.

Au2O3.H2O is brown-colored amorphous precipitated by the reaction of alkali from the solution which contains AuCl4. The nature of the complex is amphoteric, which can dissolve in excess alkali or acid into an anionic complex.

Au(OH)3 + NaOH = Na[Au(OH)4]

Au(OH)3 + 4HNO3 = H[Au(NO3)4] + 3H2O

From the hydrated compounds, an anhydrous oxide is may be obtained by carefully heating with P4O10. It can be decomposed above the temperature of 1600C to Au2O and gold. The crystal structure of the AuO4 complex is square planar sharing with oxygen.

Another molecule Fulminating gold is an olive-green color that is explosive powder. The molecule is obtained by the digestion of Au2O3 or any hydrate reaction with ammonia. this dry powder can explode with fulminates on heating and the possible composition is HN=Au-NH2. 1.5H2O.

The sulfur-containing gold molecule is Au2S3 is cannot be obtained from the aqueous solution because it is decomposed by the water. It is prepared another method by passing through H2S gas over the dry LiAuCl4.2H2O at a very low temperature.

2liAuCl4 + 3H2S = Au2S3 + 2LiCl + 6HCl

That LiCl can be separated by the extraction with an a basic solution and the black powder is dried at moderate temperature.

The fluoride of gold, specifically Au(III) with fluorides is prepared by the reaction of elemental fluorine on Au2Cl6 at a very high temperature like 3000C.

The reaction goes as sequences like,

image 242
Au(III) Complex Formation

AuF3 is a crystal of orange color and it can decompose at 5000 to gold and elemental fluorine. The crystal structure is a square planar shape with cis fluorine atoms in the helical chain. The terminal Au-F bond distance is lower than the bridge Au-F bond.

Au2Cl6 molecule is red in color and it can be directly synthesized by refluxing HAuCl4 with thionyl chloride.

2H3O+AuCl4 + 2SOCl2 = Au2Cl6 + 2SO2 + 6HCl

The structure of the dimeric molecule is planar and it is a diamagnetic complex in the solid as well as vapor phase also.

image 243
Dimeric Structure of AuCl3

Au2Cl6 can dissolve in hydrochloric acid to form chloroauric acid. The evaporation of HAuCl4 gives a yellow-colored crystal of H3O+AuCl4.3H2O. NaAuCl4.2H2O and KAuCl4 both gold (III) salts are water-soluble.

Au(II) compound

In the gold structure, Au(II) is an unfavorable oxidation state as compared to Au(I) and Au(III). Au(II) complexes are very rare. There are many examples of Au(II) complexes but they are mixed oxidation states of the gold structure.

In dinuclear compounds, we can find the Au-Au bonds in gold structure which may be formed by the oxidation addition of the Au(I) complex.

image 244
Au(II) Complex

Here the main driving force of the Au(II) complex is the bidentate phosphine ligands hold two gold atoms in close range in rigid conformation.

Au(I) compound

Only a halogenated molecule is observed for Au(I) state. But sometimes a violet-grey colored molecule named Au2O has obtained by the process of dehydrating AuOH, but the authentication of this molecule is not confirmed.

Au2S appears dark brown in color and is precipitated by the saturation of a solution of Kau(CN)2 with hydrogen sulfide gas, followed by the addition of hydrochloric acid. This is insoluble in water and in dilute acids too. But it can dissolve in the aqua regia and aqueous KCN. It is also soluble in excess sodium sulfide solution.

4.     Is gold inorganic or organic?

Gold is an element and it is not formed via hydrocarbon. In the gold structure, we can see that there are d electrons present. Which makes gold a transition metal. Metal cannot be an organic molecule.

When gold forms different kinds of molecules in the gold structure they are forming via electrostatic interaction of different oxidation states of the gold structure. So, all the gold compounds are inorganic. Gold is a 5d element, so the effective nuclear charge is very high and there is no possibility of hybridization of gold structure. Gold has a higher coordination number according to its respective oxidation state.

So, the molecule of gold is not covalent, although gold can form different organometallic clusters by the reaction with different π-acidic ligands, the nature of the complex is low spin in the gold structure. The electronegativity of gold structure is so high and the electron affinity also for gold is very high, so it can be ionized when a gold molecule is formed.

So, gold is an inorganic substance when it forms chloride or any other salts.

5.    Is gold an element?

The elemental form of gold is Au. It is a d-block element, especially a heavier metal. The elemental form does not change when it shows a different oxidation state the respective charge is placed above the element.

The atomic number of gold is 79 which means it is the 79th element in the periodic table.

6.    Is gold an isotope?

Two or more species of the same elements having the same atomic number but differing in atomic mass is called the isotope of the first element. Isotopes have the same or nearly the same chemical behavior but their physical property may be different.

The mass number of gold is generally 197 and the isotope having 195 mass number is the stable isotope of Au. Apart from them, gold has 36 radioactive isotopes, but radioactive isotopes have a short life span. 195Au has the highest half-life among the other isotopes of gold. The half-life of that isotope of gold is 186 days.

Half-life is the time for elements how much time required for its half of the portion will be dissociated. If we consider 100% of the isotopes then after 186 days it remains only 50% of it, the rest 50% are dissociated and it takes 186 days for the dissociation.

Isotopes are born for some nuclear fission and nuclear fusion process. Sometimes α and β decoys are also responsible for the formation of isotopes. Gold is a heavier element and it can dissociate with different small elements by accepting suitable energy, so it has more number of isotopes. The higher the number of atomic mass higher will be the number of isotopes, but in the case of hydrogen it has three isotopes but the mass number is 1 for hydrogen. So exceptional cases are always present.

The nature of α and β decoys can decide that how many isotopes are radioactive or how many are stable. Gold is a 5d element and it is a later element in the periodic table and near to radioactive elements, so it has many more radioactive isotopes.

7.    Is gold on the periodic table?

Every metal or every element in chemistry should have a particular position in the periodic table. Gold is present in the 11th group 6th period and d block element.

Gold is a transition metal and it is a 5d element which means it has a d orbital and the valence electrons should be contained in the d orbital. As it is a 6th-period element so there is an involvement of 6s orbital for gold structure. The electronic configuration of the gold structure is, [Xe]4f145d106s1.

Due to the involvement of the 6s orbital its shows relativistic contraction and for this reason its shows different abnormal behavior. Due to the presence of d and f orbital, it has a poor screening effect.

The outermost electrons of an atom experience two types of forces- nuclear attraction force and repulsion with the inner electrons. It is due to the second force that the outermost electrons cannot experience the total nuclear charge but only apportion of it known as an effective nuclear charge. In fact, the inner electrons practically behave as a screen between the nucleus and the outermost electron- the phenomenon refers to as the screening effect.

The greater the penetrating power of an orbital better will be the extent of screening of the orbital electron density. Since the order of orbital penetratively hence s>p>d>f. hence the order of screening is also be s>p>d>f.

In fact, it is due to the greater diffuseness of the electron density in that d and f orbitals they exhibit a poor screening effect.

With the screening effect and relativistic contraction of several properties of the gold are altered.

Down the group from Copper to silver the principal quantum number increases but the configurations are similar. Thus as expected the ionization energy decreases with an increase in principle quantum number. In the case of gold it is due to the extensive relativistic contraction of the 6s orbital that the nuclear attraction for the outermost 6s electrons increases.

Also, it is due to the relativistic contraction of 6s and 4f orbitals being subject to relativistic expansion- screening by the 4f orbitals becomes even poorer  – effective nuclear charge increases to a large extent. Thus the relativistic contraction of 6s orbital couple with f contraction accounts for the extremely high nuclear attraction for 6s electrons.

This factor highly predominates over the effect of an increase in principle quantum number from Ag to Au. Thus ionization energy of gold structure much much higher than Ag.

From the electronic configuration of gold, it is evident it is due to the presence of 14 4f electrons the effective nuclear charge of gold structure increases to such an extent that its electron affinity becomes extremely high.

For Au, the electron will be accepted in the 6s orbital. Since the 6s orbital is subject to relativistic contraction. Its energy decreases and becomes so low as compared to that of 6p that the 6p orbital practically behave as post valence orbital.

Thus, the configuration of Au is practically the filled one comparable to those of noble gases- hence the name noble liquid configuration. Thus, to attain the noble liquid configuration gold will accept an electron readily – the electron affinity of gold is extremely high.

CsAu is a stable molecule and it is an example of the abnormal behavior of gold in the periodic table.

Cs is an alkali metal having only one electron in the outermost shell. Also, it is due to the larger size of cs the nuclear attraction for the outermost electron is extremely low. Thus first ionization of Cs is low. Cs can readily lose an electron (undergoes ionization) – the electron lost can be readily gained by Au since the electron affinity of Au is extremely high due to the above reasons.

Aurophilicity

The au atoms have been found to have weak interactions with the neighboring Au atoms- Aurophilic interaction. The major cause for this interaction is that each of the Au atoms has an inherent tendency to accept an electron, in order to assume the noble liquid configuration. Thus in an effort to attain the noble liquid configuration, each Au atom will try to draw electron density with neighboring Au atoms – thereby leading to interaction (Aurophilic interaction) between them, and the phenomenon is referred to as Aurophilicity.

8.    Is gold polar or nonpolar?

It is very difficult to say for an element is polar or nonpolar in nature. Polarity arises due to the resultant dipole-moment value. Again, for a molecule, if the electronegativity difference is so high then we can say the molecule will be polar.

In the gold structure, there is no factor present which makes the gold polar or maybe non-polar. The electronegativity of gold is very high, but there must be some elements present so we can compare the difference. In the elemental state, this comparison is not allowed. When gold is making a molecule in its most stable oxidation state in the +3 oxidation state, it generally formed halogenated molecules.

Halogens are most electronegative so there is a chance of higher electronegativity difference and the shape of the molecule is asymmetric because there is an odd number of atoms that will be present as gold is in a +3 oxidation state. So there may be a chance of getting some resultant dipole-moment and making the molecule polar.

But in elemental form gold structure is non-polar. When gold behaves as an anion the size of that anions are very large and it can be polarizable by any cation and then it may be polar.

9.    Is gold diatomic?

In the elemental state, the gold structure is exhibited as Au, so it is monoatomic in nature. All the metal atoms are monoatomic.

Metal atoms are mostly electropositive and due to higher electropositivity if they exist as the diatomic form then there will be extensive repulsion between two same electrostatic forces. Again, one metal can easily release the electron but that electron accepted by another one is very difficult. Because most the metal has lower electron affinity.

But in the case of gold structure, the electron affinity is higher so it can readily accept the electron from other gold and form a noble liquid configuration. That’s the reason there is aurophilicity observed for the gold structure. Due to aurophilic interaction, there is small interaction occurs but they cannot exist as diatomic form due to their larger size.

10. Is gold magnetic?

Pure gold does not stick to the magnet but if there is some allow present in it then it can be stuck to the magnet. The magnetic property of gold is considered by the electrons in the valence shell.

All the metals are magnetic in nature mat be diamagnetic or paramagnetic depending upon the different oxidation states also.

11. Is gold diamagnetic?

The electronic configuration of the gold structure is [Xe]4f145d106s1. So from the electronic configuration, we can say that there is one unpaired electron present in the 6s orbital of the gold structure. So, in neutral state gold is diamagnetic in nature.

For any metal or atoms, if all the electrons are paired in the form then it is called paramagnetic and if at least one unpaired electron is present then it is called diamagnetic.

For a neutral gold structure, there is only one unpaired electron is present so it is diamagnetic. But the most stable oxidation state is +1 for gold structure. In Au(I) form all the electrons in the 5d and 4f orbitals are paired in form, so in that state gold is paramagnetic.

Again, in the +3 oxidation state, two electrons were removed from 5d orbitals, and according to Hund’s rule, there are two subsets containing two unpaired electrons and making gold diamagnetic.

We can calculate the magnetic value of a diatomic substance by using the number of unpaired electrons.

12. Is gold soluble?

Gold is soluble in the following reagents,

  • aqua regia
  • the mixture of nascent chlorine
  • solutions of nitrates, sulfates e.g. bisulfate of soda
  • strong acid like hydrochloric acid

13. Is gold water-soluble?

any transition metal is insoluble in water, so gold also insoluble in water. Actually, it does not react with oxygen, air, or any kind of liquid except aqua-regia. So, there is no chance for gold to be soluble in water.

14. Is gold conductive?

Any metal is a good conductor of heat and electricity. So gold is also a good conductor of heat as well as electricity.

15. Is gold electrically conductive?

Gold is an electrically conductive agent. Because gold is a metal and for every metal, there is the difference between the conduction band and valence band is very low. Electrons from the conduction band to the valence band are easily transferred and required lower energy for this reason the mobility of ions increases and for this reason, they can conduct electricity in a faster way.

When gold is in an ionic form that is when it exists in a +1 or +3 oxidation state then the electrical conductivity also increases and for this reason it can be disproportionate to the lower oxidation state.

16. Is gold a mineral?

Minerals are those which is naturally occurring in the crystalline solid forms, they are created by the humans or animals’ dead bodies and form a crystal structure. On the other hand, earth metals are those found in the earth’s crust in crystalline form. So basically gold is a mineral and metal both. But gold is not an ore.

17. Is gold malleable?

yes, gold is extremely malleable. Among all the metals only gold is malleable. It can be beaten out into sheets of about 5*10-5 mm thickness. For this malleability, it is used in ornaments. Different types of ornaments are formed by using this property. Among all the versions 18 carat is the least malleable version of gold and the highest is 24 carat. It depends upon how many impurities should be added.

18. Is gold brittle?

Yes, gold is brittle and one gram of gold is beaten to make 24 mm sheets.

19. Is gold ductile?

All the metal has the property of ductility. Gold is a transition metal so yes gold is ductile. From one ounce of gold to 80 km of gold, wire making is possible.

20. Is gold dense?

Yes, gold is a very denser element. The density of gold is 19.32 g/mol that why it is called heavy metal.

21. Is gold heavier than silver?

Yes, gold is much heavier than silver. The density of gold is almost twice the density of silver.

22. Is gold stronger than iron?

The unalloyed and pure iron is much stronger than gold.

23. Is gold lighter than water?

Gold is metal and obviously, it is not lighter than water. It is almost 19 times heavier than water.

24. Is gold hard or soft?

Pure gold is very hard but when it is mixed with impurity or alloy then it becomes soft.

25. Is gold endothermic or exothermic?

The process of solidifying gold is exothermic.

26. Is gold hydrophobic?

On the gold surface, there is some impurities are present like carbon and for this reason, gold is hydrophoure but clean gold is hydrophilic.

27. Is gold transparent?

The density of gold is very high and for this reason gold is opaque, it is not transparent.

28. Is gold crystalline or amorphous?

The gold structure is a face-centered cubic structure, so it is crystalline solid.

29. Is gold radioactive?

Gold has 41 isotopes only one is stable and the rest of all are radioactive.

30. Is gold reactive?

The gold structure is one of the noblest in the periodic table and it is generally an unreactive element.

31. Is gold stable or unstable?

Gold has radioactive isotopes and those isotopes are very reactive but the normal isotope is stable.

Conclusion

Gold is a very malleable and stable element.  For its 6s and 4f orbital, it shows abnormal behavior. The brittleness of gold is very high that’s why it is used for making ornaments. The medicinal chemistry of gold is well known. Different kind of drug is made from gold.

Read more about following Structure & Characteristics

ZnO
ZnS
Fe3O4
NaClO2
Lithium
Krypton
Neon
Peptide Bond
NaHSO4
KMnO4
NaH2PO4
FeO
Fe2S3
Hyaluronic Acid
Disulfide Bond
Alanine Amino Acid
Glycolic Acid
Heptane
Glycine
ZnSO4
Glutamic Acid
Graphite
Hexanoic Acid

Gasoline structure, Characteristics : 25 Facts To Know

image 223

In this article, we learn about a natural fuel like gasoline and its structure, property, and many more facts.

Gasoline structure is a hydrocarbon compound, so it is an organic molecule. The general formula of gasoline is CnH2n+2. So, gasoline is an alkane molecule. Petrol is one example of gasoline. Gasoline structure is as similar to alkane structure. Higher-order alkane mainly from pentane to decane or so on are liquids and the mixture of them is used as gasoline.

Gasoline is an extremely flammable molecule. It has a low flash point of -230 C. like all other liquid hydrocarbons gasoline burns in a limited range of its vapor phase. It is highly volatile so it is dangerous if its source of ignition is present.

Some important facts about gasoline

The molecular weight of gasoline is initially 108 g/mol. It depends upon the higher-order alkanes which should involve. The color of the gasoline structure is mainly colorless to pale brown or pink, it also depends on which alkane is involved in the composition.

Initially, the boiling point is 390C after 105 distillation the boiling point becomes 600C, after 50% and 90% distillation the boiling point increases to 1100 C and 1700C respectively. Finally, the boiling point will be 2040C.

The density of the gasoline structure is 0.7 g/cm3. The odor is gasoline odor and the physical state of the gasoline structure is liquid.

Now we discuss the composition by the percentage of gasoline structure,

components                 percentage composition                       Other possible Components

n-alkanes                                                                                           Octane enhancers

C5                                3.0                                           N,N-dialkylphenylenediamines            

C6                                11.6                                         methyl t-butyl ether (MTBE)    

C7                                1.2                                                       t-butyl alcohol (TBA)

C9                                0.7                                                       ethanol

C10-C13                         0.8                                                       methanol

Total of n-alkanes       17.3                                                     antioxidants

                                                                                    2.6-dialkyl and 2,4,6-trialkylphenols

Branched alkanes

C4                                2.2                               butylated methyl, ethyl and dimethyl phenols

C5                                15.1                             triethylene tetramine di(monononylphenolate)

C6                                8.0                                           metal deactivators

C7                                1.9                                           N,N-disalicylidene-1,2-ethanediamine

C8                                1.8                                           N,N-disalicylidene-propanediamine

C9                                2.1                               N,N-disalicylidene-cyclohexanediamine

C10-C13                         1.0                               disalicylidene-N-methyl-dipropylene-triamine

Total of branched       32.0                                         ignition controllers

                                                                                    tri-O-cresylphophate (TOCp)

Cycloalkanes                                                               icing inhibitors

C6                                3.0                                           isopropyl alcohol                     

C7                                1.4                                           detergents/dispersants

C8                                0.6                                           alkylamine phosphates

Total of cycloalkanes    5.0                                           poly-isobutene amines

                                                                                    long-chain alkyl phenols

olefins                                                                          long chain alcohols

C6                                1.8                                           long chain carboxylic acids

Total of olefins 1.8                                                          long chain amines

Aromatics                                                                   Corrosion inhibitors

Benezene                     3.2                                           carboxylic acid

Toluene                       4.8                                           phosphoric acid

Xylenes                       6.6                                           sulfonic acid

Ethylbenzene               1.4

C3-benzenes                 4.2

C4-benzenes                 7.6

Others                          2.7

Total aromatics            30.5

1.    What is a gasoline structure?

Gasoline is the combination of different higher-order alkanes. So, the gasoline structure is also mixed with different compounds. Mainly C8H18.

gasoline structure
Gasoline Structure

Sometimes the gasoline structure will be 2,2,4-trimethylpentane, so here also 8 carbon atoms are present. So, the general gasoline formula can be C8H18. We know C-C single bond rotation is possible due to lower barrier energy, so they can rearrange by rotating the bond and forming different structures, they are chain isomers.

2.    How to draw a Gasoline structure?

Gasoline structure is nothing but an octave structure. So first we try to draw the method of octane structure. By drawing the octane structure we can draw the gasoline structure which has the molecular formula C8H18.

image 224
Octane Skeleton

To draw the gasoline structure or any alkanes we should keep some points in our mind.

Step 1– First we draw the number of C atoms, which mentions in the following manner,

  1. Meth
  2. Eth
  3. Prop
  4. But
  5. Pen
  6. Hex
  7. hept
  8. Oct and so on.

Step 2- Gasoline structure is made by alkane, so here only a single bond is allowed. Now we connect all the c atoms via single bonds only.

Step 3 – Now the valency of carbon atoms is satisfied by adding a respective number of H atoms. If there is any functional group is present then it should be placed at the respective position.

Step 4– now we numbering all C atoms from the left side and kept in mind that the functional group gets the least number or begins the number.

3.    Is gasoline covalent or ionic?

From the gasoline structure, it is evident that there is no ionic part is found in the gasoline structure. Gasoline structure is the skeleton of C and H atoms and both are not ionic in nature. So, the gasoline structure is not ionic.

Gasoline is nothing but a hydrocarbon, which is a special alkane. There are only H and C atoms are present, C and H both do not have ionic potential to polarize the other part or they cannot be ionizable to form an ionic bond, so the gasoline structure is a purely covalent molecule.

4.    Is gasoline a hydrocarbon?

Yes, the gasoline structure is a hydrocarbon. The molecules which form from H and C atoms are only called hydrocarbons. All the organic molecules are hydrocarbons.

Not always hydrocarbon contains only C and H atoms, they should contain other hetero atoms like O, N, S, etc along with H and C. actually, if a skeleton of a molecule is made by C and H then the molecule is called as a hydrocarbon. The gasoline structure is C8H18 which is an alkane molecule named octane. The skeleton of the gasoline structure is made of only C and H atoms, so gasoline is a hydrocarbon.

5.    Is gasoline acidic or basic?

It says very difficultly for a hydrocarbon to be acidic or basic because there is an option for pH. After all, most all hydrocarbons are insoluble in water. pH is applicable when a molecule is soluble in water and the aqueous solution gives the pH value.

The gasoline structure is made of hydrocarbon it is an alkane. There is no electronegative atom present in the molecule. The electronegativity of H and C atoms are similar so there is no factor present to make the molecule either acidic or basic. So, we cannot predict the acidic or basic nature of gasoline.

6.    Is gasoline made from oil?

If there is no mention of oil, then we can say that gasoline is not made from oil. Because oil is a combination fatty acid and there is no mechanism to form gasoline from the acid molecule. Because gasoline is an alkane.

The gasoline structure is only a hydrocarbon, so there is no chance to produce the alkane from oil. Actually, gasoline is formed from crude oil which is extracted from the earth’s crust, but from normal oil, we cannot synthesize the gasoline structure.

7.    Is gasoline made from crude oil?

Gasoline is made from crude oil and other petroleum liquids. These petroleum or crude oil go through three processes to get gasoline structure they are

  • Distillation
  • Conversion
  • Blending

Distillation – In this method, the crude oil is heated and then separated. This process is done in the crude towers or vacuum towers. Modern separation techniques are involved in piping crude oil through hot blast furnaces. The resulting liquids and vapors are discharged into units called distillation units. All the refineries where gasoline is made from crude oil have atmospheric distillation units. But the more complex refineries used vacuum distillation units.

Gasoline is one of the light fractions which is liquefied in the refinery gases, then vaporized and rises to the top of the tower, where they condensed and again back to liquid.

Conversion In this method company adds different kinds of chemicals, catalyst and it gets pressure and heat to the oil in the vessels that are called hydro-cookers or fluidized catalytic crackers. In this process, large hydrocarbons will be cracked into small ones.

After distillation, higher-value products such as gasoline can be processed further into lighter. Here fractions are transformed from the distillation units to streams which are intermediate components, that eventually become finishing the products.

There are two processes in conversion one is alkylation and the other is reforming.

In alkylation, gasoline components are made by combining some of the gaseous byproducts which are formed during the cracking process.

The reforming process uses heat and moderate pressure and also the uses of catalysts to turn Naptha, which is a light and relatively low vale fraction, into gasoline components which is high octane value.

Blending – this process is done to get various types of products that are usable as engine fuel. Here octane level, vapor pressure ratings, and other special considerations will be done to determine the gasoline blend.

The higher-order chains from octane C8H18 to C15 are blended from gasoline. All of them can be vaporized at a temperature that is below the boiling point of water and for this reason, if gasoline is spilled on the ground it evaporates very fast. After that kerosene, diesel, and then lubricant oil is synthesized.

8.    Is gasoline a pure substance?

From the components of gasoline structure, we can say that gasoline is not a pure substance, it is mixed of different kinds of hydrocarbons.

Gasoline is a mixture of n-alkanes like octane is the main substance but it is the composition of n-alkanes, branched alkanes, cycloalkanes, and some part of aromatics compound. So, there are different types of hydrocarbons are present in the gasoline structure, so gasoline is not a pure substance.

When is produced from crude oil, then the raw gasoline is not extracted because the crude oil goes through a different process, and in that process, there is a chance of adding different chemical compounds and catalysts. So, gasoline structure is always a mixed substance.

9.    Is gasoline polar?

The criteria of a molecule being polar are, that a molecule has some resultant dipole-moment, the electronegativity difference between two atoms is more than 0.4D, and the counter atoms have a tendency to polarize other atoms and other atoms should be polarizable.

We know gasoline structure is nothing but hydrocarbons, more specifically alkanes. In the alkane, there are only C and H atoms are present along with a single bond character. Single bond always sp3 hybridized, so the electronegativity of the nucleus is very poor. Again, the electronegativity of C and H is also low and almost equivalent. So, the electronegativity difference is almost zero for C and H atoms.

The gasoline structure is mainly octane. If we consider the structure of octane, we can see that the structure is symmetric in nature, so the dipole moment of octane acts opposite to each other and then cancel out the dipole-moment value. So, the net resultant dipole-moment value for gasoline structure is zero and thus making the molecule non-polar.

Generally, most of all hydrocarbons are non-polar unless there is present any electronegative atoms or functional group like -OH, then there is the possibility of making the molecule polar otherwise not. But here in gasoline structure, no such case is available so the gasoline structure is non-polar.

10. Is gasoline a renewable resource?

If the resource we can use again and again through the recycling process then is called a renewable resource, but if the resource we cannot use after one time then it is called a non-renewable resource. Any kind of fuel is an example of a non-renewable resource.

If we observe the gasoline structure, we can see there is a combination of C and H atoms making a hydrocarbon chain. When gasoline is used as fuel, then its combustion in the air, and during the combustion, C is transferred to carbon dioxide and the process of carbon dioxide to reverse back C is very difficult and it is done in the laboratory. That carbon dioxides are mixed in the open air and cannot get back into their form.

Actually, nonrenewable resources come from the earth’s crust. It is then extracted in solid, liquid, and gaseous form and then convert into suitable products which are related to energy substances e.g. nonrenewable resources including crude oil, natural gas, coal, and uranium. The fossil fuel is extracted into crude oil from the earth’s crust and converted into gasoline. These fossil fuel liquids are also refined for petrochemical products to produce plastics and polyurethane to respective solvents.

The main difference between renewable and non-renewable resources is, that non-renewable resources are limited and can be diminished over time but renewable energy is not.

11. Is gasoline a fossil fuel?

Yes, gasoline is one kind of fossil fuel. Some fossil fuels are refined into some derivates like kerosene and gasoline before burning them.

All the fossil fuels are non-renewable but all the non-renewable resources are not fossil fuels. e.g. crude oil, natural gas, and coal all are considered fossil fuels but uranium is not a fossil fuel uranium is found in the earth’s crust and its amount is also limited. Uranium is a radioactive metal so it cannot form in the same process as fossil fuels.

Crude oil or petroleum is the fossil fuel for gasoline. These fossil fuels can be formed by the sedimentation of rocks, when any organisms have died then they can turn into fossil fuels over billions of years, or the human body or any living being contained phosphate in their body after dying these phosphates turn into hydrocarbon like fossils. Fossil fuels are also hydrocarbons from which we can extract different crude oil or fuels.

12. Is gasoline a natural gas?

Natural gas is composed of methane and ethane whereas in gasoline structure the main skeleton is octane. Both gasoline and natural gas are extracted from the earth’s crust but the compositions are different and both are used as fuel. Both are fossil fuels but their nature and composition are different. So, gasoline is not natural gas.

13. Is gasoline blue?

The color of the gasoline structure is colorless or pale brown or sometimes pink, it depends on the composition of the hydrocarbons. We know gasoline is nothing but a hydrocarbon or alkane, an alkane, there is no such HOMO-LUMO gasp where the energy difference is high or low so the corresponding color will be visible. Mainly conjugated hydrocarbons show different colors due to electronic transaction

The color of kerosene is blue, because of the adding blue dye in it to identify the kerosene from petrol or diesel, but the low-quality kerosene is blue, and high-quality kerosene is white.

14. Is gasoline clear?

Gasoline is not dry, it is a liquid type of appearance so it is a clear substance. Sometimes gasoline will be dried for making different substances.

15. Is gasoline conductive?

The gasoline structure is made from hydrocarbon more specifically octane. Hydrocarbon is a bad conductor of electricity. Because they do not ionize and the mobility of their ions is very poor. So, gasoline is not a conductive agent, it can produce heat by burning itself because it is a good flammable agent.

16. is gasoline corrosive?

Gasoline is not corrosive to metals, even if it is not corrosive to human beings also. But inhaled gasoline vapor causes toxicity.

17. Is gasoline denser than water?

In the gasoline structure, we see there is an octane molecules present and the density of octane is much higher than water as it contains eight C atoms. So, gasoline is denser than water although both are liquids and due to different densities they are non-miserable.

18. Is gasoline elastic or inelastic?

Gasoline is a relatively inelastic product. From the density, it can be said that it is not elastic in nature.

19. Is gasoline heavier than air?

Gasoline structure is made from octane and the density of octane is much heavier than air, so gasoline is heavier than air.

20. Is gasoline heavier than diesel?

Diesel contains approximately 75% of aliphatic higher order hydrocarbons like C10H20–C15H28 and about 25% aromatic hydrocarbons with higher molecular weight like styrene, where gasoline structure is made from octane, so the diesel is heavier than gasoline.

21. Is gasoline hydrophobic?

Gasoline structure is the skeleton of hydrocarbons, and all the hydrocarbons are less affinity to water so, gasoline is hydrophobic in nature.

22. Is gasoline odorless?

There is benzene is also present in the gasoline structure, so it has a distinctive odor due to the presence of benzene as a component.

23. Is gasoline soluble in water?

Hydrocarbon is the main composition of gasoline structure, that’s why it is nonpolar and less soluble or insoluble in polar solvents like water. Also, it has a different density than water so it is insoluble in water and the hydrophobic part is also large.

24. Is gasoline volatile?

In the gasoline structure, there is a mixture of relatively volatile hydrocarbons like cycloalkanes, alkanes, and aromatics, so it is partially volatile in nature.

25. Is gasoline viscous?

Gasoline has a 0.006 centipoise viscosity value, so we can say that the gasoline structure is a lower viscous molecule.

Conclusion

Gasoline is a highly flammable substance and it catches fire easily. It is a non-renewable resource and non-renewable resources are the primary source of energy.

GaCl3 Lewis Structure, Characteristics: 19 Facts You Should Know

image 219

In this article, we discuss trichloride of group 13th element. Let’s discuss GaCl3 lewis structure and different important facts.

GaCl3 or gallium trichloride is an example of trihalide of group 13th element. Ga is very stable in its +3 oxidation state because at that state its electronic configuration will be d10. Ga is the main group metal so it has an affinity to bind with electronegative atoms like Cl. Due to electron deficiency, GaCl3 is exist as a dimer form in solid-state, Ga2Cl6 like Al2Cl6.  In the dimer form, it will form a 3c-4e bond.

GaCl3 has a high boiling point and very low melting point. GaCl3 is sp2 hybridized. Ga has filled d electrons so 4s and 4p orbitals participate in the hybridization or any kind of bond formation. The low oxidation state of Ga can permit to involved in complex formation for the GaCl3.

1.    How to draw GaCl3 lewis structure?

For a p block element or any kind of element that can form a molecule, it is necessary to draw their lewis structure to observe the bond structure, bonding, method, etc. Let us consider drawing the GaCl3 lewis structure.

GaCl3 lewis structure
GaCl3 Lewis Structure

Step 1- The first step is counting the valence electrons of every atom in the molecule and added together. So first we calculate the valence electrons in the GaCl3 lewis structure. Ga is p block group 13th element. The electronic configuration of Ga is [Ar]3d104s24p1. So, it has a vacant d orbital and three valence electrons in the 4 s and 4 p orbitals. Again, Cl is also a p block element but it belongs to the halogen family group 17th element. The configuration of Cl is [Ne]3s23p5. So, it has seven electrons in its valence shell. So total valence electrons in the GaCl3 lewis structure is 3+(7*3)=24 electrons.

Step 2 – in the 2nd step, we have to decide on the central atom of any molecule. In the GaCl3 lewis structure, Ga is a p block metal so it shows a positive charge, so its electronegativity is very low and for this reason, Ga will be chosen as the central atom in the GaCl3 lewis structure. Three Cl atoms are present on the three sides of the central Ga atoms.

Step 3 – In this step, we have to calculate how many numbers of bonds are required according to the Octet rule. According to the octet rule every p block elements try to complete its valence shell by eight electrons. So, for the  GaCl3 lewis structure electrons needed according to the octet rule will be, 8*4 =32 electrons. In the solid-state, GaCl3 exists as a dimer, so in the dimer, the electrons needed will double from the monomer. So, the electrons needed will be 32*2 = 64 electrons.

But the valence electrons for the GaCl3 monomer will be 24 and for the dimer, it will be 24*2 =48 electrons. In the dimer, there will be a metal-metal double bond and there are four electrons will be needed.  So, in the GaCl3 dimer required bonds apart from metal-metal bonds will be, 1/2(64-4-48) = 6 bonds, and in the GaCl3 monomer the required bonds will be 3 bonds.

Step-4 In the fourth step we added all the atoms by the required number of bonds. In the GaCl3 lewis structure, there will be a minimum of three bonds are there so, Ga and three Cl atoms are attached via three single bonds.

Step-5 In this step we try to fulfill the octet of every atom in the GaCl3 lewis structure. After adding the three bonds the octet of Ga is completed via the formation of a dimer. But for the Cl, six electrons exist in their valence shell and for completing the octet they exist as lone pairs over the Cl atoms.

2.    GaCl3 lewis structure shape?

The shape of the molecule depends on the hybridization, mode of bonding, and presence of surrounding atoms. There are three surrounding atoms for Ga in GaCl3 lewis structure, so the acceptable shape is planar trigonal.

image 217
GaCl3 Shape

Ga is a p block element and has only three electrons in its valence shell and they are forming a bond with three Cl atoms. There are no other electrons are present in the valence shell of Ga in the GaCl3 lewis structure. GaCl3 is an AX3 type of molecule without lone pairs of central atoms, so according to the VSEPR theory, it should adopt planar trigonal geometry. Again, from hybridization, we can say that if the central atom is sp2 hybridized so the shape of the molecule will be planar trigonal.

3.    GaCl3 lewis structure angle?

For a planar trigonal molecule, a bond angle is expected to be 1200. If there is no deviation factor present, like lone pairs -bond pair repulsion, the large size of surrounding atoms, etc. In the GaCl3 the Cl-Ga-Cl bond angle is 1200.

image 218
GaCl3 Bond Angle

In the GaCl3 lewis structure, Cl-Ga-Cl is around 1200. So, it is evident from the structure of GaCl3 that it is planar trigonal and there is no lone pair-bond pair repulsion. Actually, in the GaCl3 lewis structure, there is no deviation factor is present, so the bond angle is ideally 1200.

4.    GaCl3 valence electrons

The number of valence electrons for GaCl3 lewis structure is calculated for Ga and three Cl atoms individually. Ga and Cl both are p block elements, so we only count the electrons in the p orbitals, because those electrons are the valence electrons for GaCl3.

image 219
GaCl3 Valence Electrons

In the GaC3 lewis structure, Ga and Cl have three and seven electrons in their valence shell respectively. The electronic configuration of Ga and Cl are[Ar]3d104s24pand  [Ne]3s23p5 respectively. So, the total valence electrons in the GaCl3 lewis structure are, 3+(7*3)=24

5.    GaCl3 lewis structure lone pairs

In the GaCl3lewis structure, only cl atoms have the lone pairs, not central Ga. All the valence electrons of Ga are involved in the bond formation.

image 220
GaCl3 Lone Pairs

From the electronic configuration, it is evident that there are only three electrons in the valence shell for Ga and all the electrons are involved in the bond formation and no electrons are there in the valence shell of Ga. So, Ga is lack of lone pair.

But Cl has seven electrons in its valence orbitals so, it has seven valence electrons and only one electron is involved in the bond formation and the rest of the six electrons exist as three pairs of lone pairs. So, there are only Cl atoms containing lone pairs in the GaCl3 lewis structure.

So, the total lone pairs in the gaCl3 lewis structure are 3*3 = 9 pairs of lone pairs.

6.      GaCl3 lewis structure formal charge

GaCl3 lewis structure is partially charged or neutral is predicted from its formal charge value. Accounting for the same electronegativity for Ga and Cl we should calculate the formal charge of the molecule.

It is a theoretical concept, so formal charge has a specific formula, and the formula is,

F.C. = Nv – Nl.p. -1/2 Nb.p.

The formal charge over Ga is, 3-0-(6/2) = 0

The formal charge over Cl is, 7-6-(2/2) = 0

So, the GaCl3 lewis structure is neutral from its formal charge value.

7.    GaCl3 lewis structure octet rule

In the GaCl3 lewis structure, only Cl has completed its octet by completing the valence shell with eight electrons, and Ga is not completed its octet.

image 221
Dimer of GaCl3

Cl has seven electrons in its valence shell and it shares one bond via two electrons with Ga and completed its octet to make a single bond. But in the case of Ga, there are three electrons in the valence shell and Ga makes three bonds with shre three more electrons, so there are six electrons in the valence shell of Ga and it is not complete its octet. That’s why Ga can accept more electrons to fulfill its electron deficiency and makes dimer to complete the octet.

When it forms a dimer then both Ga atoms in dimer form complete their octet via bridging the cl atoms. This model can be explained via 3c-4e bonding.

8.    GaCl3 lewis structure resonance

There are no such electron clouds present over the Ga atoms for delocalization in different skeleton forms. That’s why the GaCl3 lewis structure does not show any resonating structure.

9.    GaCl3 hybridization

From the shape of the molecule and involvement of the orbital, we can say that GaCl3 lewis structure is sp2 hybridized.

We can calculate the GaCl3 hybridization by using the following formula,

H = 0.5(V+M-C+A)

In the GaCl3 lewis structure, the central Ga atom is, ½(3+3+0+0) =3 (sp2 hybridized).

If the central atom of a molecule is involved in three orbitals in hybridization then it will be sp2 hybridized.

Let us understand the hybridization of GaCl3 lewis structure,

image 222
GaCl3 Hybridization

From the box diagram of the GaCl3 lewis structure, it is evident that central Ga is sp2 hybridized where only 4s and 4p orbitals are involved and there are vacant p orbitals in Ga, so the GaCl3 monomer does not complete its octet.

10.    GaCl3 solubility

GaCl3 is soluble in the following solvents,

  • Water
  • Benzene
  • CCl4
  • CS2

11.    Is GaCl3 soluble in water?

As discussed, the previous GaCl3 is very much soluble in water, as it vacant p orbital so there the lone pairs of oxygen atom can be attacked and for this reason, it can produce an adduct and result is soluble in water. GaCl3 is very moisture sensitive.

12.    Is GaCl3 a strong electrolyte?

Yes, GaCl3 is a very strong electrolyte, in an aqueous solute, the ion can readily be ionized to Ga3+ and 3Cl, both ions are good conductors of electricity and both are soluble in water, making the solution a good conductor of electricity.

13.    Is GaCl3 polar or nonpolar?

GaCl3 is dissolved in water, so it is a sign that GaCl3 is a polar molecule. The electronegativity difference between GA and Cl is huge which makes the molecule polar. Again, due to the asymmetric shape, the mackerel has some resultant dipole moment.

14.    Is GaCl3 acidic or basic?

GaCl3 is acidic, rather it is a very strong Lewis acid.

15. Is GaCl3 a lewis acid or base?

In the GaCl3 lewis structure, there is a vacant p orbital present for Ga, this p orbital is energetically accessible and it can take electrons or lone pairs from a suitable lewis base and acts as stronger lewis acid, But in the dimer from the vacant p orbital is filled upon bond formation so, the dimer is not a good lewis acid.

16. Is GaCl3 paramagnetic or diamagnetic?

After the bond formation all the valence electrons of GaCL3 and even for Ga(III_ all the d electrons are paired up. So, Gacl3 or Ga(III) is diamagnetic in nature.

17. Is GaCl3 linear?

No, GaCl3 is not linear, the GaCL3 lewis structure shape is trigonal planar and it is evident from the bond angle and its hybridization value too.

18. GaCl3 bond angle

The GaCl3 lewis structure shape is trigonal planar and the hybridization value is sp2, so the bond angle is 1200.

19. GaCl3 boiling point

The boiling point of GaCl3 is very high because in the solid state two Ga centers are linked strongly and the solid is liquified. In the liquid state since Ga-Ga bonds are extremely strong at the very high temperature required to break those bonds, Thus, it has a very high boiling point.

Conclusion

In the GaCl3 lewis structure, Ga is sp2 hybridized but there is electron deficiency in the Ga center and to fulfill, the deficiency GaCl3 is exist as a dimer form via 3c-4e bonding.

Also Read:

FeCl2 Lewis Structure, Characteristics: 9 Facts You Should Know

image 205

In this article, we should discuss the FeCl2 lewis structure. Let’s talk about the FeCl2 lewis structure and 9 different characteristics fact.

FeCl2 is often known as ferrous chloride. The ferrous term is coming for Fe in a +2 oxidation state. In the FeCl2 Fe is in a +2 oxidation state. The electronic configuration of Fe(II) is d6. Being a FeCl2 is a coordination compound, Cl is not only a counter ion here it also acts as a ligand. The geometry of the FeCl2 lewis structure is the bent shape, although in the crystal form it adopts an octahedral shape.

As Cl is a soft filed ligand, the electronic paired up is not formed in the d orbital. So, Fe(II) is a d6 high spin system here. Only one subset is paired due to six electrons present in five subsets. FeCl2 lewis structure can be ionized to ferrous and chloride ions.

Some important facts about FeCl2

FeCl2 is a white solid crystalline molecule. It is a paramagnetic solid due to the presence of four unpaired electrons in the d orbital. The color of its tetrahydrate form is greenish, due to its octahedral shape and the Laporte transition occurs. But in anhydrate form is white.

Anhydrates form can be prepared by the reaction of steel waste with hydrochloric acid.

Fe + 2 HCl → FeCl2 + H2

The melting point and boiling points of FeCl2 are950 k and 1296 K respectively.

1.    How to draw FeCl2 lewis structure?

Drawing the FeCl2 lewis structure is not an easy task. As FeCl2 is a coordination compound rather than a covalent molecule. So here d electrons will be involved in the bond formation and it is not easy to manage d electrons for drawing the lewis structure because d electrons follow the 18 electrons rule rather an octet rule. So, we try to draw the FeCl2 lewis structure easily in the following manners.

Step 1– At first, we should count the valence electrons for Fe as well as Cl. The valence electrons of Fe are d electrons and p electrons for Cl atoms and added together. In the FeCl32 lewis structure, the valence electrons for Fe are 6 as it is in a +2 oxidation state, and all the electrons belong from its d orbital only, for three Cl atoms is 7*2 = 14. So, the total valence electrons are 6+14 = 20.

Step 2 – Fecl2 will follow the 18 electron rule because it is a coordination compound.it is similar to the octet rule of a coordination molecule. The electrons that will be needed for the FeCl2 lewis structure will be 8 + (2*8) = 24 because the octet rule required 8 electrons in the valence shell for every atom. We get the available valence electrons are 20 from the previous calculation for FeCl2. Now the required electrons will be (24-20) = 4 electrons and the minimum number of bonds required that all the three atoms should be connected in this molecule is 4/2 = 2 bonds.

Step 3- Now time for deciding on the central atom in the FeCl2 lewis structure. Fe is here central atom as it is electropositive because it is a transition metal, whereas Cl is from the halogen family and it is a more electronegative atom.

Step 4 – Connect two Cl atoms with the central Fe via the minimum number of required single bonds i.e. two. So, Fe makes two single bonds with two Cl atoms from its d orbital electrons in the FeCl2 lewis structure.

Step -5 After the bond formation we have to check the number of lone pairs available over the molecule. So, we check which atoms in the FeCl2 lewis structure contain lone pairs. In the FeCl2 lewis structure, Fe is +2 oxidation state, so it is a d6 system and it has no lone pairs in its d orbital. So, we check the lone pairs over Cl atoms. Cl is group 17th element and from the halogen family. So, after bond formation, it has three pairs of lone pairs. So, the lone pairs are assigned only over the Cl atoms.

All the octet is complete after the bond formation and lone pairs are assigned, so no need to add any kind of multiple bonds in the FeCl2 lewis structure.

2.    FeCl2 hybridization

The bonding method of coordination compound or metallic compound is different. They do not follow the rule of the Valence Bond Theory (VBT). They will follow CFT i.e. Crystal Filed Theory. Hybridization is a corollary of VBT. So, it is difficult to determine the hybridization of FeCl2 lewis structure.

So, we predict the hybridization of FeCl2 lewis structure from its shape. The shape is bent and two surrounding atoms are present and no involvement of lone pairs, so there will be two orbitals are involved in the hybridization and the hybridization will be sp.

In the hybridization, FeCl2 does not involve its d electrons, because they are not it’s outermost orbital and due to the presence of weak field ligand Cl, only the outer orbital will contribute, they are 3s and 4p orbital. So, it is another example of an outer orbital complex like FeCl3.

If we use the typical formula for the calculation of hybridization, H = 0.5(V+M-C+A),

H = ½(2+2+0+0) =2 (sp), Fe has two electrons apart from six electrons in its d orbital and two Cl atoms are present. From VSEPR theory if the number of orbitals mixed in hybridization is 2 then the central atom is sp2 hybridized.

Let us draw and understand the hybridization of the FeCl2 lewis structure.

image 205
FeCl2 Hybridization

From the box diagram of Fe(II), we can say that only 4s and 4p orbitals are involved in the bond formation for the FeCl2 lews structure. So, the hybridization is sp. 4s and 4p orbitals are outer orbital for Fe, so it is an outer orbital complex. When it forms tetrahydrates, then four water molecules bind with four unpaired electrons in the d orbital and makes an octahedral complex.

1.    Is FeCl2 ionic or covalent?

The coordination compound is somewhat covalent. But in the FeCl2 lewis structure, Fe and Cl two ions can be separated due to large ionic differences and also show ionic character. In the aqueous solution, it can be ionized easily, and Fe(II) easily polarize chloride anions.  So FeCl2 is ionic besides covalent character.

2.    Is FeCl2 soluble in water?

Any polar molecule will be soluble in a polar solvent (like dissolve like). Water is a polar protic solvent and it can form an H bond also. FeCl2 is a polar molecule because the charge difference between Fe and Cl is so high and due to its bent shape, it makes polar. So, naturally, FeCl2 is soluble in water.

3.      Is FeCl2 aqueous?

After soluble in water any molecule, then that form is called an aqueous form of that particular molecule. As discussed previously that the FeCl2 lewis structure is soluble in water, so after soluble, the whole solution is called an aqueous solution of FeCl2. So FeCl2 can make an aqueous solution easily after being soluble in water.

In the aqueous solution, FeCl2 can easily be ionized to separate the two ionic forms.

FeCl2(aq) = Fe2+ (aq) + 2Cl(aq)

4.    Is FeCl2 a salt?

The reaction between acid and base always gives us salt and water. So, if a molecule is produced after the reaction between an acid and basic molecule then it is called salt. Salt is the combination of counter cation of a basic molecule and counter anion of acidic molecules.

If we reacted ferrous hydroxide with hydrochloric acid we should get FeCl2 as a salt along with water as a side product.

Fe(OH)2 + 2HCl = FeCl2 + 2H2O

So basically, salt is the neutralization part of an acid and base after reaction and salt does not have any acidic as well as basic property in it. So FeCl2 is salt.

5.    Is FeCl2 a strong electrolyte?

A substance that dissolves in water or any other polar solvent to produce ions and a solution that conducts electricity is called electrolytes. In the aqueous solution of FeCl2, we already see that FeCl2 is fully ionized in that solution to form ferrous and chloride ions. Those ions are very good conductors of electricity. So, if we passed the current in the aqueous solution of FeCl2, then it can carry the current in a very good way. So FeCl2 is a strong electrolyte.

image 210
Image source Wikimedia

6.    Is FeCl2 a precipitate?

If a compound is insoluble in water then it can be precipitated down the reaction vessel. But FeCl2 is soluble in water so there is no chance for FeCl2 to exist as a precipitate. The precipitate can also form due to the reaction of two compounds and in an aqueous solution, the product will be insoluble in water.

7.    Does FeCl2 react with HCl?

When we reacted Fe with HCl the FeCl2 is formed instead of FeCl3. Because FeCl2 is a thermodynamically more stable product. It is a displacement reaction and metal can easily displace the H2 from HCl, so FeCl2 is formed instead of FeCl3.

Conclusion

FeCl2 is also a coordination compound and it can form tetrahydrates adopting octahedral geometry. Cl is weak filed ligand so the system is sigh spin and Fe is +2 oxidation state. So, the electronic configuration will be d6 high spin. FeCl2 is soluble in water and a strong electrolyte.

Also Read:

FeCl3 Lewis Structure, Characteristics:13 Facts You Should Know

image 156

Let us talk about FeCl3 lewis structure and 13 important characteristic features of FeCl3 in this article.

FeCl3 is the chemical formula of ferric chloride. The Central Fe is in a +3 oxidation state here. So, the Fe is named ferric. Cl is not here present as a counter ion also it acts as a ligand here, cause FeCl3 is a coordination compound rather than a covalent molecule. So, it has different coordination properties along with covalent properties. The molecular shape is trigonal planar but in coordination chemistry, it adopts octahedral geometry, the vacant site is filled with a water molecule causing ferric chloride to exist as a crystal form.

Cl here acts as a weak filed ligand, so no electrons in d orbital exist as paired form. It is a high spin complex. Fe(III) is a d5 system and all the electrons exist single spin only with no paired form. FeCl3 molecule can be fully ionized by charge separation of ferric and chloride.

1.    How to draw FeCl3 lewis structure?

Drawing of lewis structure of coordination compound is very difficult because it does not follow the general rule of the covalent molecule. Because this is a coordination molecule and it has some coordination property in it. Lewis dot structure can give us a proper picture of the molecular shape, valence electrons, etc. A few steps are there in the drawing of the lewis dot structure.

Step 1– At first, we count the valence d electrons for Fe and p electrons for Cl atoms and added together. In the FeCl3 lewis structure, the valence electrons for Fe are 5 as it is in a +3 oxidation state, and all the electrons from its d orbital only, for three Cl atoms is 7*3 = 21. So, the total valence electrons are 5+21 = 26.

Step 2 – Being a coordination compound FeCl3 will follow the 18 electron rule it is like the octet rule of a coordination molecule. The electrons that will be needed for the FeCl3 lewis dot structure will be 8 + (3*8) = 32 because the octet rule required 8 electrons in the valence shell for every atom. The available valence electrons are 26 from the previous calculation we get. Now the required electrons will be (32-26) = 6 electrons and the minimum number of bonds required that all the four atoms can be connected in this molecule is 6/2 = 3 bonds.

Step 3– Now time for choosing the central atom. Fe is here central atom as it is electropositive metal and its size is comparatively large. Because Fe is a transition metal and metal shows electro positivity where Cl is from the halogen group and it has more electronegativity.

Step 4 – Connect all the atoms with the central atom Fe via the minimum number of required single bonds i.e. three. So, Fe makes three single bonds with three Cl atoms from its d orbital electrons.

Step 5– Now calculate the number of lone pairs and their position of them. Fe is a group d element and it is +3 oxidation state in FeCl3 so it is a d5 system, and all the five electrons are present at the five subsets of the d orbital so it has no lone pairs. Cl belongs to the halogen family also it is group 17th element and it has seven electrons in its valence shell and only one electron is involved in the bond formation so, the rest six electrons are assigned as three pairs of lone pairs. Three Cl atoms contain three pairs of lone pairs.

2.    FeCl3 lewis structure shape

The shape of any coordination molecule depends on the coordination number of the central metal atom. The structure may be varying cause some metal center can expand their coordination number. But in the covalent molecule, it depends on the VSEPR theory.

image 157
FeCl3 Shape

In FeCl3 lewis structure, Fe is +3 oxidation state, so it has 5 d electrons and this is the valence electrons for Fe(III). Now three Cl atoms, each contribute one electron, and all three contribute three electrons. Now total electrons count for the FeCl3 lewis structure will be 5+3 =8 electrons. According to the VSEPR (Valence Shell Electrons Pair Theory), the molecule AX3 adopts tetrahedral geometry having lone pair over the central atom if the electrons count will be 8. Again, from coordination chemistry, the molecule will be tetrahedral if the coordination number will be 4.

But here the scenario is different. Neither the coordination number of Fe(III) is 4 nor does it contain any lone pairs. So, the shape is decided by the surrounding atoms and there are three surrounding atoms present and the best acceptable shape will be trigonal planar.

3.    FeCl3 valence electrons

Although FeCl3 is a coordination compound it has also valence electrons. Fe and Cl separately have a certain number of valence electrons. There will be some electrons present in the outermost orbital or valence orbital of Fe and Cl atoms.

image 158
FeCl3 Valence Electrons

Iron is a 4th-period element. It is also a d block element which means the outermost orbital of Fe is the d orbital. In the FeCl3 lewis structure, Fe is +3 oxidation state, so its electronic configuration becomes 3d5. So, it has five electrons in its d orbital. D has five subsets and Cl is a weak field ligand. So, every subset contains one unpaired electron. So, iron has five valence electrons.

Now for Cl, it belongs to the halogen family that is group 17th element. So, naturally, it has seven electrons in the valence shell. Three Cl atoms have 3*7 =21 valence electrons.

So, the total number of valence electrons in the FeCl3 lewis structure is 5+21=26 electrons.

4.    FeCl3 lewis structure formal charge

Each molecule has a formal charge may be the value will be zero for a neutral covalent molecule but there is some value over a particular ion if that ion possesses ionic character. Even in coordination molecule also shows the formal charge.

The formula we can use to calculate the formal charge of any covalent or coordination molecule is,

F.C. = Nv – Nl.p. -1/2 Nb.p.

Where Nv is the number of electrons in the valence shell or outermost orbital, Nl.p is the number of electrons in the lone pair, and Nb.p  is the total number of electrons that are involved in the bond formation only.

Remind that we always consider the same electronegativity for atoms to calculate the formal charge of a molecule.

In the FeCl3 lewis structure, we have to calculate the formal charge separately for Fe and Cl.

The formal charge over Fe is, 6-0-(6/2) =+3

Iron has a 3d6 system in transition metal cause 4s electrons we cannot consider due to strong ionization energy.

The formal charge over Cl is, 7-6-(2/2) = 0

This result implies that Fe is in a +3 oxidation state which means it has a +3 charge over it and the formal charge also Fe is +3 here.

So, we can conclude that formal charge also predicts the ionic nature or amount of charge of every single atom in a particular molecule.

5.    FeCl3 lewis structure angle

In a covalent molecule bond angle depends on the VSEPR theory or hybridization value but in coordination com pound bond angle depends on the coordination number of a central metal atom or several ligands present in it.

image 159
FeCl3 Bond Angle

In the FeCl3 lewis structure, there are three ligands present surrounding the Fe center. So, the geometry according to one metal center and three surrounding ligands will be trigonal planar is perfect. All the ligands have the same and equivalent so no need to adjust their position by changing the bond angle. We know that the bond angle of a trigonal planar geometry shape is 1200.

So here the Cl-Fe-Cl bond angle is expected to be 1200. The lone pairs over Cl are not a problematic situation here so no need for the deviation of bond angle. Again, Cl is weak filed ligand, so Fe is high spin here and the geometry and bond angle are solely decided from the ligand site only and the bond angle is 1200.

6.    FeCl3 lewis structure octet rule

Every atom will follow the octet rule and try to complete its valence shell after the bond formation in a covalent molecule. But in coordination compound will follow the 18 electrons rule. It is like the octet rule of the organometallic complex.

image 160
FeCl3 Octet

In the FeCl3 lewis structure, Cl is halogen so it has completed its octet by accepting one electron in its valence shell as it has already seven electrons in it. During the bond formation with Fe, one electron from Cl and one d electron from Fe site share to form a covalent or coordination bond. Thus, the Cl atom completes its octet.

But in the case of Fe, it is a d block transition element, so it should follow the 18 electron rule rather than an octet. In FeCl3 lewis structure, Fe is in a +3 oxidation state so it has 5 d electrons in its valence shell and accepts 3 more electrons from three Cl atoms via sharing to complete its octet. Fe has 26 electrons and deducted from 18 electrons rule it ahs 8 electrons and this is how it can complete its octet.

7.    FeCl3 lewis structure lone pairs

In the FeCl3 lewis structure, there are only present lone pairs over 3 Cl atoms only. Fe does not contain any lone pair. The valence electrons of Fe are 4s orbital and after bond formation, the electrons of d orbital did not participate in the valence shell.

image 161
FeCl3 Lone Pairs

Being halogen Cl belongs to group 17th. So, it has seven electrons in the outermost 3s and 3p orbitals. But after the bond formation, there are six electrons present and they exist as three pairs of lone pairs (one in 3s orbital and the other two in 3p orbital).

But in the case of Fe, the outermost orbital is 4s, but in Fe(III) the valence shell is 3d, where five electrons are present in five different subsets. After the bond formation with three Cl atoms rests two electrons do not pair up because of the higher exchange energy of the 3d orbital, so Fe does not contain lone pairs.

8.      FeCl3 lewis structure resonance

For resonance, we need the electron-rich center or any atom which contains more electrons clouds that can be delocalized in different skeletons of that particular molecule. Both are absent in the case of FeCl3 lewis structure.

In the FeCl3 lewis structure, Fe is d block metal so it possesses a positive charge, so it is lack electron density. Again, Cl is more electronegative so it cannot release the electron density from it. So there is no resonance occurs in the FeCl3 lewis structure.

9.    FeCl3 hybridization

For any coordination molecule, it is very difficult to find out its state of hybridization. Because they are violated valence bond theory. So, we cannot find out the hybridization of such a compound.

But if we consider its shape so it can say that as it adopts trigonal planar structure then it should be sp2 hybridized. But Fe is a 3d element so it does not has 3s orbital form bond formation. So, we consider the 4s and 4p orbital here.

If we use the typical formula for the calculation of hybridization, H = 0.5(V+M-C+A),

H = ½(3+3+0+0) =3 (sp2), Fe has three electrons apart from five electrons from the d orbital and three Cl atoms are present. From VSEPR theory if the number of orbitals mixed in hybridization is 3 then it is sp2 hybridized.

As 4s and 4p orbitals are involved here so it is called the outer orbital complex.

Lets us draw and understand the hybridization of the FeCl3 lewis structure.

image 162
FeCl3 Hybridization

So, from the box diagram, we can say that the s and p orbitals which are involved in the hybridization are 4s and 4p, and outer electrons only contribute so the complex is the outer orbital complex.

10.    FeCl3 solubility

Fecle3 is soluble in the following solution,

  • Water
  • Ethanol
  • Methanol
  • Acetone
  • diethyl ether

11.    Is FeCl3 ionic?

Yes, FeCl3 is an ionic molecule, as it is a coordination compound but it can be ionized as Fe3+ and Cl. So FeCl3 lewis structure is an ionic molecule.

12.    Is FeCl3 acidic or basic?

FeCl3 is a good Lewis acid. In the FeCl3 lewis structure, we can see that Fe is +3 oxidation state and it has five electrons in the d orbital and the highest number of electrons accumulated by the d orbital is 10. So, it can accept electrons in its d orbital so it acts as lewis acid.

13.    Is Fecl3 polar or nonpolar?

FeCl3 is a polar molecule. Most of the ionic molecules will be polar and FeCl3 is ionic so it has polarity. The electronegativity difference between Fe and Cl is very high so there is a dipole moment generated and it makes polar.

14.    Is FeCl3 tetrahedral?

No, FeCl3 is not tetrahedral, because there are no lone pairs on the  Fe center. It is a trigonal plannar shape.

15.      Is FeCl3 linear?

No, FeCl3 is not linear it is a trigonal planar shape. In the lattice crystal, it is octahedral.

Conclusion

FeCl3 is a coordination compound rather than a covalent molecule. It has coordination property and Cl is not a counter ion here it is a weak filed ligand thus it makes the bond with a higher oxidation state of Fe like Fe(III).

Also Read:

5 Neutral Oxide Example: Facts That You Should Know

image 152

Neutral Oxide Example contains this article. The oxides are neither acidic nor basic known as neutral oxides. In this article let’s talk about more details about neutral oxides example.

Oxides are the binary oxygen compound of any other atom. It may be binary or tertiary or any other depending on the valency of the other atom. Generally, oxides are of two types, one is metallic oxide and the other is non-metallic oxides. Oxides are forming with metal ions are called metal oxides and form with non-metallic species called non-metallic oxides. But there are other categories of oxides that is acidic oxides, basic oxides, neutral oxides, and amphoteric oxides.

Acidic oxides – Oxides that react with water to produce acid are called acidic oxides. Generally, non-metallic oxides are acidic oxides.

e.g. CO2. H20 +CO2 = H2CO3

Basic oxides – Oxides that form based upon reaction with water are called basic oxides. Metallic oxides are an example of basic oxides.

e.g. CaO, CaO + 2H2O = Ca(OH)2 + H2

Amphoteric oxides – Amphoteric oxides are those which can produce acid as well as a base they can react with both acid and base to produce water and salt.

e.g. Al2O3 , Al2O3 + 6HCl = 2AlCl3 + 3H2O

                   Al2O3 + 2NaOH + 3H2O = 2Na[Al(OH)4]

Neutral oxidesNeutral oxides are neither acidic nor basic or it cannot reacts with acid or base called neutral oxides.

e.g. CO, NO, etc.

In this article, we discuss only neutral oxide examples and detailed facts.

The list of neutral oxide examples are,

1.    Carbon monoxide (CO)

Carbons monoxide is a neutral oxide example. It is a mono oxide of Carbon. Incomplete combustion of carbon in presence of oxygen produces carbon monoxide. It is very toxic to a living being, it can form bonds with Fe(II) in hemoglobin and produce toxicity.

Apart from that carbon monoxide is a very strong field ligand in organometallic chemistry. In carbon monoxide, there is a partial triple bond character shown, so the electron density of carbon is dragged away from it to the Oxygen site. So, it can behave as a good electrophile. It can form a bond with metal with excess d electrons or metal having a low oxidation state.

During ligation, the HOMO of CO containing a pair of electrons donates electrons density to the suitably dz2 orbital of the metal (sigma donation). In addition, the vacant π* (LUMO of CO) is involved in π-acceptance from suitably filled dxz or dyz of the metal. It is due to sigma donation and π-acceptance that they occur between the metal and C in the metal carbonyl complexes- thereby accounting for their stabilization.

neutral oxide example
Ϭ Donation of CO

It is due to the Ϭ donation from CO a net positive charge develops at the C center and this favor the π-acceptance. Also, it is due to the π-acceptance that a positive charge density develops at the metal center and this intern favors the Ϭ donation. Thus, the Ϭ donation and π-acceptance re-enforce each other and this phenomenon refers to as the synergistic effect.

image 153
π-Acceptance of CO

2.    Nitric Oxide (NO)

Nitric Oxide is another neutral oxide example. It is a mono oxide of nitrogen. It is less toxic than carbon monoxide. Nitric oxide also can bind with metal with higher d electrons and behaves as a strong field ligand.

In organometallic chemistry, it can behave as a strong filed ligand and can bind with metal having excess d electron or low oxidation state. The binding mode of NO is two types. When it binds with metal in the form of NO+ then it can behave as a 3 electrons donor system. NO+ is stronger than CO and forms a stronger π bond with the metal center. When it binds as NO+ then it binds at linear geometry with metal.

When it binds as NO- then it will be 1 electron donor system and binds at bent geometry, because there will be no double bond formation occur and the single bond can be rotated. Due to two different types of binding modes, it can be called redox non-innocent ligand.

Note- If No behaves as NO+ in a complex it is a case of linear nitrosyl since NO+ is isoelectronic with CO and CN and hence will form a similar type of complex.

image 154
Different Mode of Binding of Nitrosyl

When NO behaves as a NO it is a Ϭ donor ligand only and hence M-N bond is a single bond. Under this condition, M-N-O will be around 1800. Since this process will not be entropically favored. If the nitrosyl is substantially bent then it will be able to assume a larger number of confirmations – thereby stabilizing the structure.

3.    Nitrous Oxide (N2O)

Nitrous Oxide is also a neutral oxide example. It is used as a laughing gas and has a slightly sweet odor. The geometry of nitrous oxide is linear with an N-N-O bond angle will be 1800.

The coordination chemistry of Nitrous oxide is very much limited and it is a very poor ligand and it can bind only some selective metals only. In Nitrous oxide, the N center acts as the donor center cause the whole electron density is present over it.

4.    Water (H2O)

Water is the best neutral oxide example. Actually, it can react with both acid as well as a base but it can not behaves as acidic or basic because it is a neutral molecule. The lone pairs over O are the reaction center here. The lone pairs can be coordinated with a metal center and it can also behave as a ligand.

In coordination chemistry, water can behave as a weak field ligand. The lone pairs over the O center can be coordinated with the metal center. It is a ϭ donor and π donor ligand. So, it can form a bond with the metal center having lower d electrons.

5.    Manganese dioxide (MnO2)

Manganese dioxide is another neutral oxide example. The oxidation state of Mn in MnO2 is +4. So, the oxidation number is lower so here MnO2 is a neutral oxide. If the oxidation state of Mn is higher in any oxide then it can behave as acidic oxide.

There is no such coordination chemistry about MnO2. MnO2 is one neutral oxide of a metal oxide. Generally, metal oxides are basic in nature. It is used in different titration processes. It is used in the titration of KCl to estimate the quantitative value.

Conclusion

From the above discussion of neutral oxide example, we can say that they cannot participate in acid-base reaction but they can be used as ligand also or in titration to estimate another element mainly they are stable oxides so they need not react any other species.

NH3 Lewis Dot Structure: Drawings, Hybridization, Shape, Charges, Pair, And Detailed Facts

image 147

Here in this article, we discuss only the NH3 lewis dot structure, its hybridization, shape, and molecular fact in detail, and the NH3Cl+ lewis dot structure.

In the NH3 lewis dot structure, N formed three sigma bonds with three H atoms. In this structure, N has three bond pairs and one lone pair. The lone pair is also involved in the hybridization and present one of the hybrid orbitals in sp3 hybridization. Though the molecule is sp3 hybridization so it is expected that the bond angle should be 109.50 but here H-N-H bond angle is 1070. So here lone pair-bond pair repulsion will be observed.

As it is sp3 hybridized so the shape of the molecule will be tetrahedral but it adopts trigonal pyramidal geometry. All the N-H bond lengths are equal and the value is 100.8 pm. In CFT, NH3 can behave as a good ligand and it can bind with a higher or lower oxidation state of metal.

Some facts about NH3

NH3 is a colorless gas in a physical state and has a distinct pungent smell. Scientist Haber 1st synthesized ammonia from nitrogen and hydrogen gas. It is very lighter than air, the density of ammonia is half of normal air. The molar mass of the ammonia molecule is 17.031 g/mol.

The melting point and boiling point of the ammonia molecule are 195.42 K and 239.81 K respectively. The vapor pressure of the gaseous ammonia molecule is 857.3 KPa.

In the Haber process, ammonia can be synthesized in industry.

2N2 + 3H2 = 2NH3

In different fertilizers, ammonia can be used, and it is a good source of nitrogen as well.

How to draw NH3 lewis dot structure?

To draw the lewis dot or lewis structure of a molecule is a very challenging as well as an important task. Because this lewis dot structure of a molecule can give us the proper basic information about the molecules like shape, bond angle, hybridization, valence electrons, etc. Before starting to draw the NH3 lewis dot structure there are a few many rules we have to follow.

Step 1– we should count all valence electrons for all the individual atoms in the molecule and add them together. In the NH3 lewis dot structure, there are Four atoms present, one N and three H atoms. The valence electrons for N are 5 and for three H atoms are 3. So, the total valence electrons are 5+3 = 8.

Step 2 – According to the octet rule, the electrons that will be needed for the NH3 lewis dot structure will be 8 + (3*2) = 14. The available valence electrons are 8. Now the required electrons will be (14-8) = 6 electrons and the minimum number of bonds required in this molecule is 6/2 = 3 bonds.

Step 3– Now we have to select the central atom. N is here central atom based on electronegativity and the size of the atom.

Step 4 – joining all the atoms with the central atom via the required number of single bonds i.e. three. So, N makes three single bonds with three H atoms.

Step 5– Now assigned the lone pairs over the respective atom. Here only N contains lone pairs, so the lone pairs are assigned over N only. Now if necessary, to require multiple bonds then only add multiple bonds but here octet is complete. So, no need to add multiple bonds or add any charge over the molecule.

NH3 lewis structure shape

In the NH3 lewis dot structure, 8 electrons will be involved in the whole bond formation. So, we can say that the electrons count for this molecule is 8, and according to the VSEPR theory, it adopts a tetrahedral shape.

image 148
NH3 Shape

According to the VSEPR (Valence Shell Electrons Pair Repulsion) theory if the electrons count for a molecule is 8 then it adopts tetrahedral geometry. But the condition is that the central atom has no lone pairs. In the NH3 lewis dot structure, central N has lone pairs, so it does not adopt tetrahedral geometry, rather it adopts trigonal pyramidal shape.

N is present at the central position and three H are at the three vertices of this geometry to maintain the structure.

NH3 formal charge

A molecule whether partially charged or not can be calculated by the formal charge. The formal charge is a hypothetical concept by which we can determine the charging property of the molecule.

It is a theoretical concept, so formal charge has a specific formula, and the formula is,

F.C. = Nv – Nl.p. -1/2 Nb.p.

Where Nv is the number of electrons in the valence shell or outermost orbital, Nl.p is the number of electrons in the lone pair, and Nb.p  is the total number of electrons that are involved in the bond formation only.

There is an assumption for calculating formal charge that all the atoms have the same electronegativity.

In the NH3 lewis dot structure, there are N and H two different substituents present so we have to calculate the formal charge for both individually.

The formal charge over the N atom is, 5-2-(6/2) = 0

The formal charge over the H atoms is, 2-0-(2/2) = 0

From the calculation of formal charge, we can conclude that the NH3 molecule is neutral and no charge appears in it.

NH3 lone pairs

After bond formation, if there are pairs of electrons present in the valence shell of an atom are called lone pairs. Lone pairs are valence electrons but do not participate in the bond formation with other subsequent. NH3 has lone pair also.

image 149
NH3 Lone Pair

To find out the lone pairs we have to check the electronic configuration of every atom in the NH3 lewis dot structure.

In NH3 lewis dot structure, H and N are only present so we have to check their electronic configuration.

H has only 1 electron in its s orbital and this is its valence electron. The lone pair needs at least two electrons but H has only 1 electron and that electron is involved in the bond formation. Naturally, H has no lone pair.

Except for H, there is another atom present N. N is the group 15th element in the periodic table. From its electronic configuration, we know that there are five electrons in its valence shell, so in N there may be a possibility of having lone pair. N formed three single bonds with three H atoms and used its three electrons from the valence shell.

So, now N has two electrons in its valence shell and there is no chance for further bond formation and those two electrons exist as lone pair in the NH3 lewis dot structure. So, the lone pair in the NH3 molecule is actually from the N site. These lone pairs are present in the hybrid orbital of the NH3 molecule and for this lone pair, the structure, and shape of the molecule differ.

So, in the NH3 molecule, lone pairs carry a significant role.

NH3 bond angle

The bond angle of a tetrahedral molecule is always 109.50 but in an NH3 molecule, the H-N-H bond angle will be 1070. So, there will be some deviation factor present in the NH3 lewis dot structure.

image 150
NH3 Bond Angle

In the NH3 lewis dot structure, there is lone pair present in the hybrid orbital of N and three H atoms are also present there. Due to the small size of N, there is lone pair-bond pair repulsion that occurs in the NH3 molecule. To minimize the repulsion N decreases the bond angle to 1070.

Though it is a tetrahedral molecule its electronic shape is trigonal pyramidal and therefore its bond angle will be 1200. But due to lone pair-bond pair repulsion, it adjusted to 1070.

NH3 hybridization

N is from group 15th element whereas H is group 1st element. So, the energy of the orbital is different and not compatible with bond formation. So, they must undergo hybridization to form a new hybrid orbital of equivalent energy. Here N undergoes sp3 hybridization.

To calculate the hybridization, we use a specific formula, H = 0.5(V+M-C+A), where H= hybridization value of the central atom, V is the number of valence electrons in the central atom, M = monovalent atoms, C=no. of cation, A=no. of the anion.

In the NH3 lewis dot structure, the central atom N has five valence electrons including lone pair, and three H atoms are present in the surrounding.

So, the hybridization of central N in the NH3 molecule is, ½(5+3+0+0) =4 (sp3)

Structure  Hybridization value   State of hybridization of central atom   Bond angle
Linear              2 sp /sd / pd        1800
Planner trigonal       3 sp2               1200
Tetrahedral        4 sd3/ sp3      109.50
Trigonal bipyramidal 5 sp3d/dsp3   900 (axial), 1200(equatorial)
Octahedral   6 sp3d2/ d2sp3         900
Pentagonal bipyramidal   7 sp3d3/d3sp3        900,720

                     From the hybridization chart we can say that if the number of orbitals included in hybridization is equal to four then the central atom will be sp3 hybridized.

image 151
NH3 Hybridization

From the box diagram of the NH3 molecule, it is evident that the lone pair is also involved in the hybridization. The lone pair is present in the s orbital of the N atom. It is no longer present in the 3s orbital it is present sp3 hybrid orbital so it can be donated easily. That’s why NH3 can behave as a strong lewis base.

Conclusion

In the NH3 lewis dot structure, molecule is tetrahedral by geometrical shape but electron geometry is trigonal pyramidal. The bond angle is 1070 instead of 109.50. the molecule is polar due to an asymmetric structure. It can behave as a strong lewis base due to easily donation of lone pairs present in one of a hybrid orbital.

SCl6 Lewis Structure: Drawings, Hybridization, Shape, Charges, Pair, And Detailed Facts

scl6

This article contains about SCl6 lewis structure, its hybridization, shape, and many more important facts in detail.

SCl6 is a hexacoordinated halogenated molecule of sulfur. But it has octahedral geometry. The bond angle of the SCl6 lewis structure is 900. All the bond angles and S-Cl bond lengths are equal. It is sp3d2 hybridized. Involving the d orbital in the hybridization causes more energizes the system.

Central S is surrounded by six Cl atoms at its six sites in an octahedral geometry. S has no lone pairs in this molecule all the valence electrons are involved in the bond formation, and only Cl atoms have the lone pairs.

Some detailed facts about SCl6

Actually, in reality, SCl6 does not exist but SF6 can. The reason behind this is F is a more electronegative atom and due to its electronegativity, the energy of the d orbital of S decreases and can be involved in the bond formation via sp3d2 hybridization.

But Cl is less electronegative than f and it cannot lower the energy of the d orbital of S and due to the large size of Cl, there is steric repulsion between six Cl atoms.

If we thought of SCl6 theoretically then we can find its bond angle, hybridization, and shape also. But it cannot be synthesized in the laboratory. So, we cannot get the physical date of the SCl6 lewis structure.

How to draw the SCl6 lewis structure?

Lewis structure is often known as the lewis dot structure, and it is very important to draw the lewis structure of any molecule to predict the basic property of this molecule. There are a few steps we should follow to draw the SCl6 lewis structure.

SCl6 lewis structure
SCl6 Lewis Structure

To draw the SCl6 lewis structure, we need the total number of valence electrons present in this molecule. We count the valence electrons for S and Cl and then adding together. Now it’s time for identifying the central atom based on less electronegativity. S is less electronegative than Cl so, so S is the central atom here and six Cl are present in six corners of the S atom.

The valence electrons involved in the SCl6 lewis structure are 6+(7*6) =48 electrons and the electrons required according to the lewis dot formula are 7*8 =56 electrons, so bonding electrons will be 56-48 = 8 electrons, and the required bond 8/2 = 4 bonds. But here we need 6 bonds so it is an example of the violation of the octet rule. The extra two electrons from two bonds are from the d orbital of S.

Now add all the atoms via single bonds and the number of single bonds is six. No need to add any multiple bonds.

SCl6 lewis structure shape

The total valence electrons in the SCL6 lewis structure involved in bond formation will be 6 for S and 6 Cl atoms each contributing 1 electron, so the total electrons participating in bond formation in the SCl6 lewis structure will be 6+ (6*1) = 12, and according to VSEPR theory if the valence electron count for a molecule is 12 then the structure of the molecule is octahedral.

image 141
SCl6 Shape

In the SCl6 lewis structure, S is present at the central position whereas all six Cl atoms are present at the six corners of the octahedral moiety. For this arrangement all the S-Cl bond length is equal and all the bond angle is equal to 900. The molecule adopts a symmetrical shape.

SCl6 valence electrons

From the SCl6 lewis structure, we can calculate the number of valence electrons for the SCl6 molecule. Valence electrons are called those electrons which are present at the outermost orbitals of an atom, they can form a bond with another atom.

image 142
SCl6 Valence Electrons

In the SCl6 lewis structure, two types of atoms are present S and Cl, so we need to find out the valence electrons for S and Cl atoms. S belongs to group 16th  element from the O family, so it has the same electronic configuration as O so, it has also six electrons in its valence shell like O.

Again, Cl is from the halogen family, and all the halogens belong to group 17th which means it has seven electrons in its valence shell, so Cl has also seven electrons in its valence electrons. There are six Cl atoms are present in the SCl6 lewis structure. So, the total valence electrons for six Cl atoms are 7*6 = 42 electrons.

Now for the SCl6 lewis structure, the total number of valence electrons will be 6+ 42 =48 electrons.

SCl6 lewis structure formal charges

For any neutral molecule, it is important to find out its formal charge by accounting same electronegativity of every atom in this molecule. In the SCl6 lewis structure, find out the formal charge for S and Cl separately.

The formula we can use to calculate the formal charge, F.C. = Nv – Nl.p. -1/2 Nb.p.

Nv = number of electrons in the outermost orbital

Nl.p. = number of electrons in the lone pairs of subsequent atoms

Nl.p. = number of electrons are involved in the direct bond formation

In this molecule, all the six Cl atoms are equivalent so we need to calculate the formal charge for only one Cl atom and the central S atom.

The formal charge over the S atom is, 6-0-(12/2) = 0

The formal charge over the Cl atom is, 7-6-(2/2) = 0

So, the formal of either S or Cl is zero and this is also reflected in the result that the SCl6 molecule is neutral.

SCl6 lewis structure lone pairs

In the SCL6 lewis structure, only Cl atoms contain lone pairs in their valence shell which are not participating in the bond formation. S is a lack of lone pairs.

image 143
SCl6 Lone Pairs

S is from the O family so it has six electrons in its valence shell and the SCl6 lewis structure, there are six bonds of S with six Cl atoms. So, S has no electron in its valence shell after bond formation and it is lack lone pairs.

Cl is a halogen and belongs to group 17th and for this reason, it has only seven electrons in its outer shell. Every Cl atoms make a sigma bond with S, so they share only one electron with S. except for that one electron the rest of the six electrons are present in the outermost orbital of Cl. Those six electrons appear as three pairs of lone pairs.

SCl6 lewis structure octet rule

According to the octet rule, every atom in a molecule tries to fulfill its valence shell by accepting a suitable number of electrons or via sharing electrons in bond formation and also gaining the same electronic configuration of their nearest noble gas. In the SCl6 lewis structure, S and Cl both try to complete the octet.

image 144
SCl6 Octet

In the SCl6 lewis structure, Cl has three pairs of lone pairs and shares one electron with S in a single bond, to complete its octet via gaining eight electrons in its valence electrons.

But in the case of S, there are six electrons in its valence shell and all the electrons are shared with electrons of six Cl atoms. So, there are twelve electrons for S which is a violation of the octet rule and that’s another reason for the not exitance of SCl6.

SCl6 lewis structure bond angle

According to VSEPR (Valence Shell Electrons Pair Repulsion) theory, a molecule that has 12 electron counts generally adopts octahedral geometry and the bond angle in the octahedral is equally distributed and is 900 which is equivalent for all the atoms. All the bond angles will equal the SCl6 lewis structure.

image 145
SCl6 Bond Angle

In the lewis structure, the Cl-S-Cl bond angle will be 900. All the equatorial and axial bond angles will be the same. It adopts octahedral geometry with central atom S and all six Cl atoms are the six corners with bond angle 900. According to bent’s rule, the bond angle can be calculated and it is 900. In the hybridization, we can discuss its detail.

SCl6 lewis structure resonance

SCl6 lewis structure does not exist in reality so it does not have any resonating structure from the delocalization of electrons clouds in different skeleton forms.

Actually, in the SCl6 lewis structure, there is an electronegativity difference between central S and surroundings Cl atoms is very lower, so the electrons delocalization process does not occur there. Again, there are no extra electron clouds that can be delocalized, so in the SCl6 lewis structure, there is no resonance.

SCl6 hybridization

In the SCl6 lewis structure, both S and Cl atoms undergo sp3d2 hybridization involving the d orbital to form a new hybrid orbital. There will be differences in the energy of different orbitals so they undergo hybridization to form equivalent hybrid orbitals.

There will be a specific formula to calculate the hybridization of a molecule and that is,

H = 0.5(V+M-C+A),

where H= hybridization value, V is the number of valence electrons in the central atom, M = monovalent atoms surrounded, C=no. of cation, A=no. of the anion.

In the SCl6 lewis structure, the number of valence electrons for S is 6 which are directly involved in the bond formation. There are 6 Cl atoms are present in the octahedral geometry.

So, the hybridization of the SCl6 molecule is, ½(6+6+0+0)= 6 (sp3d2)

Structure     Hybridization value  State of hybridization of central atom      Bond angle
Linear            2 sp /sd / pd      1800
Planner trigonal   3 sp2            1200
Tetrahedral       4 sd3/ sp3       109.50
Trigonal bipyramidal   5 sp3d/dsp3                900 (axial), 1200(equatorial)
Octahedral          6 sp3d2/ d2sp3     900
Pentagonal bipyramidal 7 sp3d3/d3sp3        900,720

                From the above table we can say that if the number of orbitals contributed in hybridization is equal to six then the molecule will be sp3d2 hybridized.

image 146
SCl6 Box Diagram

From the box diagram of S in the SCl6 lewis structure, we can see that there is a total of six orbitals are involved in the hybridization. All the six orbitals of S undergo hybridization to form an sp3d2 hybrid orbital of equivalent energy.

S has a vacant d orbital in its electronic configuration. Due to the presence of six electronegative atoms Cl the energy of the d orbital somewhat decreases and accessible for hybridization.

S has six electrons in its ground state and is it also confirmed by its electronic configuration. In the ground state, two electrons are paired in s orbitals and 4 electrons are in the p orbital. When the system will be energized the electrons are no longer stable in their position and one electron from the s orbital and one electron from the p orbital are promoted to the vacant d orbital. Now S has six unpaired electrons (one in s, three in p, and two in d orbitals). These six unpaired electrons can easily form six single bonds with six Cl atoms undergoing mixing of the three orbitals.

Here one s, three p, and two d orbitals are get mixed to form a new hybrid orbital and the hybridization will be sp3d2.

For the consequences of sp3d2 hybridization, the SCl6 lewis structure is octahedral geometry and the bond angle will be 900.

According to the Bent’s rule, we can predict the bond angle via hybridization using the formula,

COSθ =s/s-1, where s is the % of s character in hybridization and θ is the bond angle.

In the SCl6 lewis structure, the hybridization is sp3d2, so the % of s character is 1/6th.

So, applying the bent’s rule we get θ = 900.

Again, from VSEPR theory if the molecule is AX6 type of molecule having no lone pairs over central atom always adopt octahedral geometry, and bond angle will be 900.

So, we can comment that if a molecule is sp3d2 hybridized then the geometry will be octahedral and the bond angle will be 900 or vice versa.

So, from the hybridization, we can predict the geometry as well as the bond angle of the molecule.

SF6 is exist but SCl6 is not. Why?

In the SF6 there are six F atoms around the S atom. To form a hexacoordinated molecule the central atom should undergo sp3d2 hybridization. S has an energetically unaccessible d orbital. But in the presence of the six most electronegative F atoms the energy of the d orbital decreases and it can undergo sp3d2 hybridization and form a stable molecule.

But when F atoms are replaced with Cl atoms, they are less electronegative and the energy of d orbitals remains high so it cannot form proper hybridization.

Again, the size of F is very small so six f can adjust in octahedral geometry but the size of Cl is large and there will be steric repulsion in the octahedral moiety.

Conclusion

SCl6 lewis structure cannot be synthesized in the laboratory or it cannot exist in reality due to the above reasons. So, all the data is given in this article based on theory. Hexacoordinated S compound is not going typical type of hybridization rather it can be described as the 3C-4e model.

Also Read:

Complete Facts on CO2 + H2O: With Several Elements Reaction

image 107

CO2 is the molecular formula of carbon dioxide. In this article, we should discuss CO2+ H2O in detailed facts with some other elements’ reactions.

Carbon dioxide (CO2) is a gaseous molecule. It is an odorless gaseous molecule. But at high concentrations, the smell is sharp and acidic. The density of carbon dioxide is almost 1.5 times of air. The density is 1.98 kg/ m3. The molecular weight is 44.009 g/mol. As it is a gaseous molecule so it has certain vapor pressure having a value of 5.72 MPa at 300 C temperature.

The reactivity of carbon dioxide is a highly reactive molecule as it contains a double bond and that double bond can easily be cleaved by the proper attack of nucleophile-like water (H20). The pka value of carbon dioxide is 6.53 so it is slightly acidic and it reacts with base or nucleophile.

CO2 + H2O
Molecular Structure of Carbon Dioxide

What is CO2 + H2O?

CO2 + H2O both are chemical or molecular formulas. CO2 is the molecular formula of carbon dioxide and H2O is the molecular formula of water.

Carbon dioxide can be rapidly soluble in water by the adsorption process and it ionizes slowly in the aqueous medium. As it is a slightly acidic character so it can form acid in an aqueous solution. Carbon dioxide is not ionized like C+ or O2. It gets dissolved in water solution and forms the whole solution acidic and then that acidic solution gets ionized.

This reaction is a simple addition reaction or combination reaction so it does not require any kind of catalyst to forward the whole reaction. The reaction can carry forward by itself only. Water acts as a medium here, where the carbon dioxide can be dissolved and ionized or make any acid or acidic solution.

What happens when CO2 reacts with H2O?

When any slightly acidic molecule gets dissolved in water or reacts with water generally the whole solution turns acidic, because water is a neutral molecule. Depending on the nature of the acidity of that particular molecule, the acidity of the whole solution of the new product is getting determined.

In this CO2 + H20 reaction it is expected that the formation of the acidic compound will occur.

Carbon dioxide is slightly acidic in nature, having a pka value is 6.53. whereas water is the neutral molecule on the pk scale. So, when carbon dioxide gets reacts with water or dissolves in water the whole solution becomes acidic or the formation of an acidic compound occurs. Carbon dioxide cannot ionize in the aqueous medium, it reacts with water, and then ionizes slowly.

Water acts as a solution medium or reaction medium. The reaction mechanism can be thought that the lone pairs of water molecules over O atoms are available and they attack the double between carbon and oxygen in carbon dioxide. Then there is a cleaved of the double bond occurred and the hydroxide group incorporated in between the double bond between carbon and oxygen in carbon dioxide.

Water is an ambident molecule and it can behave as an acid or basic both depending on the nature of the reaction. Water can ionize H+ and OH. We know that hydroxide is a strong nucleophile and base also.

But here carbon dioxide is less acidic but C=O is the best electrophilic center. So, any kind of nucleophile can attack there. Hydroxide is one of the best nucleophilic centers so it can attack that electrophilic center and the double bond can be cleaved and the OH group incorporated and the remaining H+ ion is also added to the other O site of carbon dioxide.

What kind of reaction is CO2 + H2O?

CO2 + H2O is a combination type of reaction or it can say simply be an addition reaction.

We cannot say that CO2 + H2O is the typical acid-base reaction because carbon dioxide gets dissolved in water and then form the acidic compound carbonic acid. Water is not a base here it acts as a medium here. But the mechanism can be thought that hydroxide ion attack the electrophilic center of carbon dioxide and breaks the double bond and OH group incorporated and H+ ion coordinated with O- to form H2CO3. So, in another way, this reaction can be named a nucleophilic addition reaction.

image 108
Mechanistic Pathway of CO2 + H2O Reaction

How to balance CO2 + H2O?

Every chemical reaction should be balanced properly by its stoichiometric value. Without proper balancing a reaction is not valid, because we cannot understand how many reactions are needed to react how many other reactants, and how many the product we will get.

Let us balance the equation of CO2 + H2O,

CO2 + H2O = H2CO3, we can see that this equation is already balanced. The left-hand side and right-hand side should be equal here.

So, the CO2 + H2O reaction should be balanced by the actual method. There are many steps we should follow to balance a chemical reaction.

Step 1- Every individual molecule or compound is labeled as a, b, c, or x,y, or z depending on the number of molecules present in a reaction.

We use those labeled as the coefficient of every individual molecule with that variable to identify the unidentified coefficient of the molecule.

(A)CO2 + (B) H2O = (C) H2CO3

Step 2- We make some equations for the number system

This equation is created by using suitable numbers of that coefficient for every element present in the reactant and product like carbon, hydrogen, and oxygen.

C = A = B

H = 2B = 2C

O = 2A + B = 3C

Step 3-  All the variables in the coefficient should be solved in various methods.

Solve all the variables of that coefficient via the Gauss elimination method or determination method.

Using Gauss elimination or substitution

A – B = 0

2B – 2C = 0

2A + B – 3C = 0

Thus, the result shows the lowest integer value of those variables.

A = 1 (CO2)

B = 1 (H2O)

C = 1 (H2CO3)

Step 4 – In the final step substitute the coefficients and verify the result of L.H.S. and R.H.S.

1 CO2 + 1 H20 = 1 H2CO3

Atoms        L.H.S.         R.H.S.
C11
H22
O33

                                   

So, CO2 + H2O = H2CO3 is the balanced equation and L.H.S. is equal to R.H.S.

How to balance CO2+H2O = C6H12O6 + O2 ?

CO2 + H2O = C6H12O6 + O2 reaction is not balanced properly, so we have to balance this equation properly.

So, we just start solving the balance equation by using labeling the individual molecules.

(A)CO2 + (B)H2O = (C) C6H12O6 + (D)O2

Now we created the number equation for the coefficient for every atom.

C = A = 6C

H = 2B = 12C

O = 2A + B = 6C + 2D

Now using the gauss elimination, we get,

A – 6C = 0

2B – 12C = 0

2A + B – 6C – 2D = 0

Now the result which shows the lowest integer,

A = 6 (CO2)

B = 6 (H2O)

C = 1 (C6H12O6)

D = 6 (O2)

In the final step, we substitute the coefficient and verify the result of L.H.S. and R.H.S.

6 CO2 + 6 H2O = C6H12O6 + 6 O2

Atoms                          L.H.S.                          R.H.S.

C                                 6                                  6

H                                 12                                12

O                                 18                                18

So, 6CO2 + 6H2O = C6H12O6 + 6O2 is the balanced equation now and L.H.S. is equal to R.H.S.

So, 6CO2 + 6H2O = C6H12O6 + 6O2 balanced properly.

How do balance CO2+H2O=C2H2+O2?

CO2 + H2O = C2H2 + O2 reaction is not properly balanced and we have to balance it properly.

By labeling every individual molecule we get,

(A)CO2 + (B)H2O = (C)C2H2 + (D)O2

Now we created the number equation for the coefficient for every atom

C = A = 2C

H = 2B = 2C

O = 2A + B = 2D

Now using the gauss elimination, we get,

A – 2C = 0

2B – 2C = 0

2A + B – 2D = 0

On calculation we get values of,

A = 4 (CO2)

B = 2 (H2O)

C = 2 (C2H2)

D = 5 (O2)

In the final step, we substitute the coefficient and verify the result of L.H.S. and R.H.S.

4 CO2 +2 H2O = 2 C2H2 + 5 O2

Atoms                          L.H.S.                          R.H.S.

C                                 4                                  4

H                                 4                                  4

O                                 10                                10

So, 4CO2 +2H2O = 2C2H2 + 5O2 is the balanced equation now and L.H.S. is equal to R.H.S.

How to balance CO2 + H2O = C2H6 + O2?

CO2 + H2O = C2H6 + O2 reaction is not balanced properly, so we have to balance this equation properly.

So, we just start solving the balance equation by using labeling the individual molecules.

(A)CO2 + (B)H2O = (C)C2H6 + (D)O2

Now we created the number equation for the coefficient for every atom.

C = A = 2C

H = 2B = 2C

O = 2A + B = 2D

Now using the gauss elimination, we get,

A – 2C = 0

2B – 2C = 0

2A + B – 2D = 0

Now the result which shows the lowest integer,

A = 4 (CO2)

B = 6 (H2O)

C = 2 (C2H6)

D = 7 (O2)

In the final step, we substitute the coefficient and verify the result of L.H.S. and R.H.S.

4 CO2 + 6 H2O = 2 C2H6 + 7 O2

Atoms                          L.H.S.                          R.H.S.

C                                 4                                  4

H                                 12                                12

O                                 14                                14

So, 4CO2 + 6H2O = 2C2H6 + 7O2 is the balanced equation now and L.H.S. is equal to R.H.S.

How to balance CH3OH + O2 = CO2 + H2O?

CH3OH + O2 = CO2 + H2O reaction is not balanced properly, so we have to balance this equation properly .

So, we just start solving the balance equation by using labeling the individual molecules.

(A)CH3OH + (B)O2 = (C)CO2 + (D)H2O

Now we created the number equation for the coefficient for every atom.

C = A = C

H = 4A = 2D

O = A + 2B = 2C + D

So, in this reaction numbers of H and O are not balanced so we have to balance the whole equation but the top priority is to balance H and O along with C.

Now using the gauss elimination, we get,

A – C = 0

4A – 2D = 0

A + 2B -2C -D = 0

Now the result which shows the lowest integer,

A = 4 (CH3OH)

B = 6 (O2)

C = 4 (CO2)

D = 8 (H2O)

In the final step, we substitute the coefficient and verify the result of L.H.S. and R.H.S.

4 CH3OH + 6 O2 = 4 CO2 + 8 H2O

Atoms                          L.H.S.                          R.H.S.

C                                 4                                  4

H                                 16                                16                   

O                                 16                                16

So, 4CH3OH + 6O2 = 4CO2 + 8H2O is the balanced equation now and L.H.S. is equal to R.H.S.

Conclusion

The reaction CO2 + H2O is an example of an addition reaction or we can say that in a particular nucleophilic addition reaction. Hydroxide ion from water molecule acts as nucleophile here. To balance the CO2 + H2O reaction we need to know how many reluctant will react to produce how many products and according to that stoichiometric calculation, the weight of the reactants will be measured. Even with an unknown reaction, we can know how many reactants will be required so balancing an equation is very important.