Iodine bromide or ibr lewis structure and some of its interesting and known characteristics are going to be discussed in this article with all details.
Iodine monobromide is an interhalogen compound formed when iodine reacts with bromine. It’s chemical formula is IBr. It is a dark red colored solid that gets melted in room temperature. It can be also called iodine bromide.
It’s molar mass is about 206.904g/mol. It’s melting point and boiling point is 420C and 1160C respectively. It gets completely miscible in water, ethanol, carbon disulphide, glacial acetic acid and ether. It is a source of I and can form charge transfer complexes when reacts with Lewis acids.
It is used in iodometric titrations, medical fields for heart imaging, as a powerful iodinating agent. Sometimes it is used for the generating electrophile for polyketide synthesis.
How To Draw IBr Lewis Structure?
The Lewis structure of an atom can be used to represent the bonds and electrons in it in the most basic way. Any compound’s Lewis structure can be easily drawn through a few steps. The steps for drawing Lewis structure of iodine bromide is as follows
- Calculate the sum of valence electrons in IBr. We know that halogens has seven electrons in their valence shell. So the total there is 14 electrons in iodine and bromine.
- Draw the symbol of both iodine and bromine. Then denote their seven valence electrons around them.
- In the next step make a bond in between them using a pair of electron. Calculate the formal charge, if it is zero then that will be the stable Lewis structure. Therefore the most appropriate Lewis structure of iodine bromide is as follows
IBr Lewis Structure Resonance
There is no resonance seen in iodine bromide.
IBr Lewis Structure Shape
The shape of iodine bromide is linear with a bond angle of 1800. It’s bond length is found to be 249 pm.
IBr Lewis Structure Formal Charge
The equation used for calculating the formal charge of any compound is
Formal charge = Valence electrons – No. of non bonded electrons – No. of bonds
Formal charge of iodine = 7-6-1 =0
Formal charge of bromine =7-6-1 =0
So the formal charge of iodine bromide is zero.
IBr Lewis Structure Angle
The bond angle of iodine bromide is 1800.
IBr Lewis Structure Lone Pairs
The electrons which don’t involve in bond making is called lone pair of electrons or non bonded electrons. There is three lone pairs are found in both iodine and bromine. So in total 6 lone pairs or 12 non bonded electrons are seen in iodine bromide.
IBr Lewis Structure Valence Electrons
The term “valence electrons” refers to the total number of electrons that make up an atom’s outer shell. Iodine and bromine have seven electrons in their valence shells since they are both halogens.
IBr Lewis Structure Octet Rule
According to the octet rule, an atom should have eight electrons in its outer shell when it forms a strong chemical connection. When we look upon iodine bromide both has seven electrons in the outer shell and after bond making both get one electron to make its octet fulfilled. So we can easily say that iodine bromide follows octet rule.
IBr Lewis Structure Hybridisation
The hybridisation is the process of formation of new set of orbitals with same energy from atomic orbitals of different energy to make more stable bond. The hybridisation of compound can be different. It can be sp3 ,sp2 , sp. The hybridisation of iodine bromide is sp3.
Is IBr Polar or Non Polar ?
Iodine bromide is a polar compound. Since both are halogens there is slight electronegativity difference can be seen in between them. The electronegativity of iodine and bromine is 2.66 and 2.96 respectively.
Also bromine is more electronegative than iodine. So iodine bromide is found to be polar in nature.
Is IBr Ionic or Covalent ?
The exchange of electrons between iodine and bromine results in the formation of iodine monobromide. Therefore, it is an entirely covalent compound.
IBr Electronic Geometry
The electronic and molecular geometry of iodine bromide is same. It is a linear shaped compound.
IBr Oxidation State
An atom’s charge after forming a bond is its oxidation state. There are certain rules for finding the oxidation state of an atom. Usually halogens are assigned with -1 .
Oxidation state of a compound is found in such a way that the sum of oxidation state of all the atoms present in a compound should be 0.Here in iodine bromide bromine has -1 and iodine has +1 charge. So in total it is 0.
IBr Dipole Moment
Iodine bromide or iodine monobromide is a polar compound with dipole moment value is about 1.21 D.
This article explains that iodine bromide is polar covalent compound with solubility in water. It’s Lewis structure is drawn and its lone pairs, valence electrons were found out. The uses of iodine bromide also described in this article. Exposure to iodine bromide cause irritation to both skin and eyes and sometimes cause eye damages too.