Adsorption vs Absorption: A Comprehensive Guide for Science Students

adsorption vs absorption

Adsorption and absorption are two distinct physical and chemical processes that involve the attachment of one substance to another. While absorption is the process of mass transfer of particles into another material, adsorption is the adhesion of particles onto the surface of a substance. Understanding the nuances between these two phenomena is crucial for science … Read more

Entropy Explained for Beginners: A Comprehensive Guide

entropy explained for beginners

Entropy is a fundamental concept in various fields, including thermodynamics, information theory, and machine learning. It is a quantifiable and measurable physical attribute that is often associated with disorder, unpredictability, or uncertainty. This comprehensive guide will delve into the intricacies of entropy, providing a detailed explanation for beginners. Understanding Entropy Entropy is a measure of … Read more

Quotient Rule Demystified: A Comprehensive Guide for Science Students

quotient rule demystified

The quotient rule is a fundamental concept in calculus that allows us to find the derivative of a function that is the ratio of two other functions. This rule is essential for understanding and solving a wide range of problems in various scientific disciplines, including physics, chemistry, and biology. In this comprehensive guide, we will … Read more

Freud’s Theory Explored: A Comprehensive Guide for Science Students

freud theory

Freud’s theory, known as psychoanalysis, is a theory of personality that emphasizes the influence of unconscious thoughts, feelings, and memories on behavior. While many of the concepts proposed by psychoanalytic theorists are difficult to measure and quantify, there are still some quantifiable data points related to Freud’s theory and its influence. Freud’s Influence in the … Read more

The Fascinating World of Halogens: A Comprehensive Guide

halogens

Halogens are a group of highly reactive non-metallic elements in the periodic table, specifically Group 17, that are known for their unique properties and diverse applications. These elements, which include fluorine (F), chlorine (Cl), bromine (Br), iodine (I), and astatine (At), are characterized by their diatomic nature, meaning they form molecules with two atoms, and … Read more

HCN Hybridization: Drawing, Structure And Detailed Explanations

Sp hybridization 300x119 1

In this article, “HCN hybridization” , hybridization, Lewis structure, bond connectivity of hydrogen cyanide with detailed explanation are discussed briefly.

Hydrogen cyanide known as prussic acid and it is a volatile, colorless and extremely toxic flammable liquid having a linear structure with a bond angle 1800. In this chemical species, carbon is sp hybridized having bond connectivity with hydrogen and nitrogen by two sigma and two pi bonds.

Few questions about the structure and hybridization of hydrogen cyanide are answered precisely below.

HCN Hybridization Structure

Hybridization of hydrogen cyanide can be easily explained by valance bond theory (VBT). Chemical bonding between the atoms can be determined by VBT. Like molecular orbital theory or MO theory, VBT also involved quantum mechanics.

According to this theory, bonding in any chemical species is the outcome of overlapping between the hybrid orbital of the consisting atoms. Two atoms share their half filled orbitals for overlapping to generate the hybrid orbitals.  The two bond forming atoms have one unpaired electron and after overlapping between the orbitals two unpaired electron from each of the atom get paired up.

In HCN, carbon is connected with nitrogen by triple bond and hydrogen with a single or sigma bond. From this bond connectivity it is clear that carbon is sp hybridized and as a result hydrogen cyanide has a linear structure with a bond angle 1800. 2s and one 2p orbital of carbon atom participates in this hybridization. One sp hybrid orbital from carbon atom combines with the 1s orbital of hydrogen atom and another sp hybrid orbital overlaps with one of the p orbitals among three p orbitals of nitrogen atom which are left as unhybridized or pure p-orbital.

Sp hybridization
SP Hybridization.
Image Credit: Wikimedia Commons

Hybridization of HCN can be calculated using the following formula.

  • Hybridization= = GA + [VE – V – C]/2
  • Hybridization of HCN = 2+ (4-4-0)/2 = 2
  • GA= Groups of atoms attached to the central atom
  • VE= Valance electrons of central atom
  • V= Valency of central atom
  • C= Positive or negative charge of the molecule.

To know more please check: 7 Tetrahedral Molecule Examples : Explanation And Detailed Facts

HCN Lewis Structure

Lewis structure or lewis dot structure helps to figure out the valance electrons or hybridization of any compound.

To determine the lewis structure of HCN, valance electrons of carbon, nitrogen and hydrogen should be counted from their electron configuration. Valance electron of hydrogen, carbon and nitrogen are 1, 4 and 5 respectively.

Central atom, carbon uses its three valance electrons to form triple bond with nitrogen and last valance electron for the single bond formation with hydrogen atom. Similarly, nitrogen uses its three valance electrons among the five outer most shell electrons to form the triple bond with carbon and rest of the two valance electrons remain as nonbonded electron pair. Hydrogen participates in the single bond formation with carbon by its one and only valance electrons.

HCN hybridization
Hydrogen Cyanide Lewis Structure

 To know more please follow: Is O2 a triple bond: Why, How, Characteristics and Detailed Facts

HCN Sigma and Pi bonds

From the point of hybridization the bond connectivity of central atom with each of the atom is clear. Central atom is carbon and it is sp hybridized with a linear structure. <HCN bond angle is 1800. Any covalent bonds is basically consisted of two electrons from each of the bond forming atoms.

Carbon is attached with nitrogen atom by three covalent bonds. Among these three bonds, one is sigma bond and another two is pi bonds. Carbon is also bonded with one hydrogen atoms by one sigma bond.

Sigma bond is the outcome of head on overlap of two atomic orbitals and pi bond is formed due to the lateral overlap of two atomic orbitals. Thus, sigma bond is much stronger than pi bond. The two pi bonds between carbon and nitrogen are formed due to the lateral overlap of two p orbitals (may be px and py or px and pz or py and pz). Rest of the p orbital (pz or py or px) participates in sigma bond formation with carbon.

image 16
HCN sigma and pi bonds

 To know more please check: 8+ Intermolecular Forces Examples: Detailed Explanations

HCN Polar or Nonpolar

Polarity of any molecule depends on the electronegativity difference of the atoms and the orientation of the respective atoms in that particular molecule.

We can consider the polarity of and direction of dipole moment of each of the bond. For the sigma bond between carbon and hydrogen, carbon is more polar than hydrogen (electronegativity of carbon is 2.55 and electronegativity of hydrogen is 2.2 in pauling scale). Thus, the direction of dipole moment is from hydrogen to carbon. If we consider the triple bond between carbon and nitrogen, we can see that the direction of dipole moment from carbon to nitrogen as nitrogen is more polar than carbon (electronegativity of nitrogen is 3.04 in pauling scale).

From the above explanation it is clear that HCN is definitely a polar molecule and its dipole moment is 2.9D.

HCN POLARITY
Polarity of HCN.
Image Credit: Wikimedia Commons

To know more please go through: CH2CL2 Lewis Structure Why, How, When And Detailed Facts

Frequently Asked Questions (FAQ)

Is HCN soluble in water?

Answer: Yes, HCN is soluble in water because HCN is a polar molecule and water is also a polar solvent. Thus, HCN is soluble in water due to polar-polar interaction.

Is HCN covalent compound or ionic compound?

Answer: HCN is a covalent compound. Hydrogen is connected with cyanide ion by a single covalent bond and in CN carbon is attached with nitrogen by three covalent bonds (1 sigma and 2 pi bonds).

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Lithosphere 2: A Comprehensive Guide for Science Students

lithosphere 2

Summary The concept of Lithosphere 2 is a hypothetical construct that has not been realized in the physical world. However, the study of the Earth’s lithosphere, the rigid outer layer that includes the crust and uppermost mantle, provides valuable insights into the planet’s structure, composition, and dynamic processes. This comprehensive guide delves into the intricacies … Read more

15 Limiting Reactant Problems: And Solutions

rxn 1 300x132 1

A limiting reactant problem is where in the stoichiometric ratio of the reactants is not given.

In this limiting reactant problems what we determine is, there is a reactant (the limiting) which limits the amount of product that can be obtained or produced.

We can solve the limiting reactant problem very easily by following the below steps:

  • First, write a balanced complete reaction.
  • The reactants should be converted to moles.
  • Then divide by coefficient.
  • The reactant obtained with a smaller number is the limiting reactant.

1. 100g of sucrose combusts with 10.0g of oxygen forming carbon dioxide and water. Which is the limiting reactant?

                    Solution

                    Step 1: Obtaining a balanced chemical equation:

                    C12H22O11 + 12 O2 12 CO2 + 11 H2O

                    Step 2: Converting reactants to moles

So, in the above problem O2 is the limiting reactant (because limiting reactant = reactant that produces least ml of product).

 2. Find the limiting reactant when 4.687g of SF4 reacts with 6.281g of I2O5 to produceIF5 and SO2

Solution

Step 1: Obtaining a balanced chemical equation

5SF4 + 2I2O5 → 4IF5 + 5SO2

Step 2: Converting reactants to mole then dividing by coefficient

rxn 2

So, 0.0094 mol (I2O5) is the limiting reactant as it has the lower value as compared to SF4 (0.00867 mol).

3. 4.5 moles of antimony reacts with 5.5 moles of oxygen according to the balanced equation, what is the limiting reactants? (Antimony →1 × 121.8 = 121.8 g/mol, oxygen (O2) → 2 × 16.0 = 32.0g/mol)

Solution

Step 1: Obtaining a balanced chemical equation

4Sb + 302 → Sb4O6

Step 2: Already given in moles so divide by coefficient

rxn 3

So, Sb (1.125 mol) is the limiting reactant as it has the lower value as compared to O2 (1.83 mol).

4. 6.7 moles of iron react with 8.4 moles of oxygen, what is the limiting reactant? (Iron →1 × 55.9 = 55.9g/mol, oxygen → 2 × 16.0 = 32.0g/mol)

Solution

Step 1: Obtaining a balanced chemical equation

4Fe + 3O2 → 2Fe2 O3

Step 2: already given in moles so divide by coefficient

rxn 4

So, Fe (3.35 mol) is the limiting reactant as it has the lower value as compared to O2 (5.6 mol).

5. 13 moles of phosphorus (P4) reacts with 194 grams of water (H2O). What is the limiting reactant? (P4→4 x 31.0 = 124.0g/mol, H2O→ 2 x 1.0 + 1 x 16.0 = 18.0 g/mol.

Solution

Step 1: Obtaining a balanced chemical equation

P4 + 16H2O →4H3PO4 + 10H2

Step 2: already given in moles so divide by coefficient

rxn 5

So, H2O (6.7 mol) is the limiting reactant as it has the lower value as compared to P4 (130 mol).

6. 17 grams of bismuth (III) nitrate [Bi(NO3)3] reacts with 19 grams of hydrogen sulfide (H2S) according to the balanced equation, what is the limiting reactant? (Bismuth (III) nitrate [Bi(NO3)3] →1 × 209.0 + 3 × 14.0 + 3 × 3 × 16.0 = 395.0g/mol)

Solution

Step 1: Obtaining a balanced Chemical equation

2Bi (NO3)3 + 3H2S → BiS3 + 6HNO3

Step 2: Converting reactants to moles then divide y coefficient

rxn 6 1

So, O2 (0.004 mol) is the limiting reactant as it has the lower value as compared to NH3 (0.105 mol).

7. 0.07 moles of ammonia reacts with 0.11 grams of oxygen, what is the limiting reactant? (ammonia × 1 × 4 + 3 × 1 = 17.0g/ mol, oxygen → 2 × 16 =  32g/mol )

Solution

Step 1: Obtaining a balanced chemical equation

4NH3 + 5O2 → 4NO + 6H2O

Step 2: Converting reactants to moles then divide by coefficient.

rxn 7

So, O2 (0.004 mol) is the limiting reactant as it has the lower value as compared to NH3 (0.105 mol).

8. What mass in grams of aluminium hydroxide could be made from 30g Al2S3 and 20g H2O, What is the limiting agent ?

Solution

Step 1: Obtaining a balanced chemical equation.

Al2S3 + 6H2O → 2Al(OH)3 + 3H2S

Step 2: Converting reactants to moles then divide by coefficient.

rxn 8

So, H2O (28.8g) is the limiting reactant as it has the lower value as compared to Al2S3 (31.17g).

Read more about: 10+ Covalent Bond Types Of Elements: Detailed Insights And Facts

9. What mass in grams of P4O6 could be made from 8.75g P4 and 12.50g O2 ?

Solution

Step 1: Obtaining a balanced chemical equation.

P4 + 3O2 → P4O6                                          

Step 2: Converting reactants to moles then divide by coefficient.

rxn 9

So, P4 (15.5g) is the limiting reactant as it has the lower value as compared to O2 (28.63g).

10. What mass in grams of TiCl4 could be made from 25g TiO2 , 10g Carbon and 40g Cl2 ?

Solution

Step 1: Obtaining a balanced chemical equation.

3TiO2 + 4C + 6Cl2 → 3TiCl4 + 2CO2 + 2CO

Step 2: Converting reactants to moles then divide by coefficient.

rxn 10

 So, Cl2 (53.5g) is the limiting reactant as it has the lower value as compared to TiO2 (59.4g) and C (118g).

11. How many grams of water can be produced from 5.55 grams hydrogen and 4.44 grams oxygen ?

Solution

Step 1: Obtaining a balanced chemical equation.

2H2 + O2 → 2H2O

Step 2: Converting reactants to moles then divide by coefficient.

rxn 11

 So, O2 (0.139 mol) is the limiting reactant as it has the lower value as compared to H2 (2.75 mol).

12. If 3.22 moles of Al reacts with 4.96 moles of HBr, what will be the limiting reactant in this limiting reactant problem ?

Solution

Step 1: Obtaining a balanced chemical equation.

2Al + 6HBr → 2AlBr3 + 3H2

Step 2: Converting reactants to moles then divide by coefficient.

rxn 12

 So, HBr (4.99g) is the limiting reactant as it has the lower value as compared to Al (9.737g).

Read more about: Disulfide reduction: How, What, Methods and Several Facts

13. If 21.44 moles of Si reacts with 17.62 moles of N2, what is the limiting reactant ?

Solution

Step 1: Obtaining a balanced chemical equation.

3Si + 2N2 → Si3N4

Step 2: Already in moles of so divide by coefficient.

rxn 13

So, Si (7.146 mol) is the limiting reactant as it has the lower value as compared to N2 (8.81 mol).

14. Methane gas (CH4) reacts with oxygen by combustion. How many grams of methane are needed to produce 25 grams of water?

Solution

Step 1: Obtaining a balanced chemical equation

CH4 + 2O2 → CO2 + 2H2O

Step 2: Converting reactants to moles then divide by coefficient.

rxn 14

Therefore 11.13g of methane is needed to produce 25 grams of water.

15. Consider the reaction NH3 + O2 → NO + H2O. In an experiment 3.25 g of NH3 are allowed to react with 3.50g of O2. What will be the limiting reactant?

Solution

Step 1: Obtaining a balanced chemical equation

4NH3 + 5O2 → 4NO + 6H2O

Step 2: Converting into moles and then dividing by coefficient.

rxn 15 1

So, O2 (0.0219) is the limiting reactant as it has lower value as compared to NH3 (0.0477).

16. If 75 grams of iron (III) chloride reacts with 125 grams of magnesium oxide. What will be the limiting reactant?

Solution

Step 1: Obtaining a balanced chemical equation

2FeCl3 + 3MgO → Fe2O3 + 3MgCl2

Step 2: Converting into moles and then dividing by coefficient.

rxn 16

So, FeCl3 (37.267g) is the limiting reactant as it has lower value as compared to MgO (166.667g).

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Vision Statement: Everything You Need to Know

vision statement everything you need to know

Summary A vision statement is a powerful tool that can help organizations, individuals, and communities define their aspirations and chart a course towards a desired future state. It serves as a guiding light, inspiring and motivating people to work towards a common goal. Crafting an effective vision statement requires a deep understanding of the concept, … Read more