Chemical reaction takes place on combination of inorganic compound Pb(NO3)2 to strong acid HBr, in following manner:
HBr is strong brominated derivative hydrohalic acid. Lead (II) Nitrate show face centered cubic system, used for various purposes like heat stabilizer in nylon, gold cyanidation process and calico paintings. HBr reacts with Pb(NO3)2 to give corresponding salts.
In this article let us see, how the reaction between acid and base takes place in consideration with its product formation, conjugate pairs.
What is the product of HBr and Pb(NO3)2
HBr reacts with Pb(NO3)2 to give salt PbBr2 ( lead (II) Bromide ) and HNO3 ( nitic acid ).
HBr + Pb (NO3)2 → PbBr2 + HNO3
What type of reaction is HBr + Pb(NO3)2
HBr + Pb(NO3)2 shows double displacement reaction.
How to balance HBr + Pb(NO3)2
For the given HBr + Pb(NO3) reaction,
HBr + Pb(NO3)2 → PbBr2 + HNO3
- The alphanumeric factors must be assigned to both sides of reactions.
- A HBr + B Pb(NO3)2 → C PbBr2 + D HNO3
- To construct an equation for each of the elements (Pb, N, O, H, and Br).
- In which each term denotes the number of atoms of that element present in either the reactant or the product.
| Sr No. | Molecules | A | B | C | D |
|---|---|---|---|---|---|
| 1 | Pb | 0 | 1 | 1 | 0 |
| 2 | H | 1 | 0 | 0 | 1 |
| 3 | Br | 1 | 0 | 2 | 0 |
| 4 | N | 0 | 2 | 0 | 1 |
| 5 | O | 0 | 6 | 0 | 3 |
- Enter the coefficient values into the elimination method for estimation.
- Get the smallest, whole integer values from the result by simplifying it.
- A = 2, B= 1, C= 1, D=2
- The balanced equation is
- 2 HBr + Pb(NO3)2 → PbBr2 + 2HNO3
HBr + Pb(NO3)2 titration
HBr + Pb(NO3)2 do not give titration. HBr generally undergoes reaction to give acid base titration, but lead (II) nitrate is Acidic salt because of PH ranging less than 7, it contradicts to show acid base titration.
HBr + Pb(NO3)2 net ionic equation
Net ionic equation, for given the HBr + Pb(NO3) reaction is,
Pb+2 (Aq) + 2Br– (Aq) → PbBr2 (S)
- Every compound’s phase should be written into a balanced molecular equation.
- 2 HBr (Aq) + Pb (NO3)2 (Aq) → PbBr2 (Aq) + 2 HNO3 (Aq)
- The aqueous salts or compounds present in the equation must be converted to ions.
- Only the strong electrolytes should be broken down because they totally dissociate.
- 2 H+ + 2Br– + Pb+2 + 2NO3– → 2H+ + 2 NO3– + PbBr2
- The spectator ions must be cancelled out in order to show species, actually involved in reaction.
- The remaining substance is net ionic equation.
- Pb+2 (Aq) + 2 Br– (Aq) → PbBr2 (S)
HBr + Pb(NO3)2 conjugate pairs
HBr + Pb(NO3)2 has the following conjugate pairs:
- Conjugate pair of HBr arrives by undergoing deprotonation to give Br-.
- However, there are no accessible protons available to take or donate, the salt Pb(NO3)2 does not form a conjugate pair.
- PbBr2 being salt, do not constitute any conjugate pairs.
- HNO3 deprotonates to give NO3– as conjugate base.
HBr + Pb(NO3)2 intermolecular forces
HBr + Pb(NO3)2 has the following intermolecular forces,
- HBr is polar molecule with covalent bonding generally show dipole-dipole forces and dispersion forces due to presence of H+ and Br- polar dipole.
- Pb(NO3)2 constitute of both van der Waals and strong electrostatic forces of attraction, because of presence of covalent character by N and O non-metals and ionic character between N,O and Pb.
- PbBr2 show van der Waals forces of attraction because of presence of crystalline arrangement in space constituting coordinate bond within molecule.
- HNO3 have hydrogen bonding, dipole-dipole attraction along with London dispersion forces of attraction.
HBr + Pb(NO3)2 reaction enthalpy
Reaction enthalpy between HBr + Pb(NO3)2 is – 351.72 KJ/Mol. The enthalpy of corresponding molecules in reaction are given below
- The enthalpy of formation of HBr is 72.46 KJ/Mol
- The enthalpy of formation of Pb(NO3)2 is -452 KJ/Mol
- The enthalpy of formation of PbBr2 is -244.8 KJ/Mol
- The enthalpy of formation of HNO3 is -207 KJ/Mol
- Enthalpy of reaction = [ ( -244.8 ) + 2( -207 )] – [ 2( 72.46 ) + ( -452 )]
Is HBr + Pb(NO3)2 a buffer solution
HBr + Pb(NO3)2 do not give buffer solution because a buffer is comprised of a weak acid and salt of its conjugate base, and since HBr is strong acid and lead (II) nitrate is acidic salt, so it does not fit in buffer solution criteria.
Is HBr + Pb(NO3)2 a complete reaction
HBr + Pb(NO3)2 is a complete reaction as formation of lead (II) nitrate salt takes place on completion of reaction.
Is HBr + Pb(NO3)2 an exothermic or endothermic reaction
HBr + Pb(NO3)2 is exothermic in nature, as reaction enthalpy of particular reaction is negative value, that shows heat is released during the course of reaction.
Is HBr + Pb(NO3)2 a redox reaction
HBr + Pb(NO3)2 is not redox reaction because there is no change in oxidation state of elements on both side of reaction.
Is HBr + Pb(NO3)2 a precipitation reaction
HBr + Pb(NO3)2 give precipitation reaction by forming white solid precipitate of lead (II) bromide, which is insoluble in water, dilute acid but soluble in hot water.
Is HBr + Pb(NO3)2 reversible or irreversible reaction
HBr + Pb(NO3)2 is irreversible reaction because of formation of white solid precipitate and strong acidic behavior of HBr to go 100% dissociation.
Is HBr + Pb(NO3)2 displacement reaction
HBr + Pb(NO3)2 is double displacement reaction. Here swapping of bonds takes place by lead with hydrobromide to give lead (II) bromide and hydrogen adds up with nitro group to give nitric acid.
Conclusion
Heat is evolved when HBr reacts with crystalline white salt lead (II) nitrate, to give lead (II) bromide along with nitric acid. Formation of precipitate takes place for instance, then get dissolve in presence of strong nitric acid.
Hello ….I am Sana Khan. A master’s student in organic chemistry from Nagpur University. I want to share my knowledge by publishing articles.