The PBr3 Lewis structure refers to the representation of the molecule phosphorus tribromide (PBr3) using Lewis dot symbols. Lewis structures are diagrams that show the bonding between atoms in a molecule and the lone pairs of electrons that may exist. In the case of PBr3, the central phosphorus atom is bonded to three bromine atoms, resulting in a trigonal pyramidal shape. This structure is important in understanding the chemical properties and reactivity of PBr3, which is commonly used as a reagent in organic synthesis. By examining the Lewis structure, we can gain insights into the electron distribution and predict how PBr3 interacts with other molecules.
Key Takeaways
Lewis Structure | Molecular Geometry | Bond Angle |
---|---|---|
PBr3 | Trigonal Pyramidal | 101.5° |
Lewis Structure of PBr3
Phosphorus tribromide (PBr3) is a chemical compound composed of one phosphorus (P) atom and three bromine (Br) atoms. Understanding the Lewis structure of PBr3 is crucial in comprehending its molecular geometry and chemical properties. In this section, we will explore the steps involved in determining the Lewis structure of PBr3.
Calculation of Total Valence Electrons
To begin, we need to calculate the total number of valence electrons present in the PBr3 molecule. Valence electrons are the outermost electrons of an atom that participate in chemical bonding. In PBr3, phosphorus is in Group 5A, which means it has five valence electrons. Bromine, on the other hand, belongs to Group 7A and possesses seven valence electrons each.
To calculate the total number of valence electrons in PBr3, we multiply the number of valence electrons of each atom by the number of atoms present and sum them up. For PBr3, we have:
Phosphorus (P) atom: 1 atom × 5 valence electrons = 5 valence electrons
Bromine (Br) atoms: 3 atoms × 7 valence electrons = 21 valence electrons
Total valence electrons in PBr3 = 5 + 21 = 26 valence electrons
Selection of Central Atom Based on Electronegativity
The next step in determining the Lewis structure of PBr3 is selecting the central atom. The central atom is typically the least electronegative atom in the molecule. Electronegativity is the ability of an atom to attract electrons towards itself in a chemical bond. In PBr3, phosphorus is less electronegative than bromine, making it the central atom.
Bonding Between the Elements in the Structure
Now that we have identified the central atom, we can analyze the bonding between the elements in the PBr3 molecule. PBr3 consists of one phosphorus atom bonded to three bromine atoms. Each bromine atom forms a single covalent bond with the phosphorus atom, resulting in a total of three covalent bonds.
Covalent bonds involve the sharing of electrons between atoms. In PBr3, each bromine atom shares one electron with the phosphorus atom, and the phosphorus atom shares one electron with each bromine atom. This sharing of electrons allows the atoms to achieve a stable electron configuration.
Drawing the Lewis Structure of PBr3

To draw the Lewis structure of PBr3, we start by placing the central atom, phosphorus (P), in the center. Next, we arrange the three bromine (Br) atoms around the phosphorus atom, ensuring that each bromine atom forms a single bond with the phosphorus atom.
To represent the shared electrons, we use lines (—) between the atoms. Additionally, we place dots (·) around the atoms to represent the remaining valence electrons. Phosphorus has five valence electrons, and each bromine atom has seven valence electrons.
The Lewis structure of PBr3 is as follows:
·
· Br
·
P --- Br
·
· Br
·
In the Lewis structure of PBr3, the phosphorus atom is surrounded by three bromine atoms, and each bromine atom is connected to the phosphorus atom by a single bond. The remaining valence electrons are represented as lone pairs (dots) around the atoms.
By understanding the Lewis structure of PBr3, we can gain insights into its molecular geometry and chemical behavior. This knowledge is essential in various fields, including organic chemistry, materials science, and chemical engineering.
Octet Rule in PBr3 Lewis Structure
The octet rule is a fundamental concept in chemistry that helps us understand the arrangement of electrons in a molecule. It states that atoms tend to gain, lose, or share electrons in order to achieve a stable electron configuration with eight electrons in their outermost energy level, also known as the valence shell.
Explanation of the Octet Rule
The octet rule is based on the observation that noble gases, such as helium, neon, and argon, have stable electron configurations with a full valence shell. Other atoms strive to achieve a similar electron configuration by either gaining, losing, or sharing electrons.
In the case of PBr3, which stands for phosphorus tribromide, the central phosphorus atom is surrounded by three bromine atoms. Phosphorus has five valence electrons, while bromine has seven. To satisfy the octet rule, the phosphorus atom needs three more electrons, while each bromine atom requires only one more electron.
Completing the Octet of Bromine Atoms in PBr3
To complete the octet of each bromine atom in PBr3, a covalent bond is formed between the phosphorus atom and each bromine atom. A covalent bond involves the sharing of electrons between atoms. In this case, each bromine atom shares one electron with the phosphorus atom, resulting in a single bond.
By sharing one electron with the phosphorus atom, each bromine atom achieves a stable electron configuration with eight electrons in its valence shell. At the same time, the phosphorus atom also satisfies the octet rule by sharing electrons with the three bromine atoms.
Distribution of Remaining Valence Electrons on Phosphorus and Bromine Atoms
After forming the covalent bonds between the phosphorus and bromine atoms, there are still two valence electrons remaining on the phosphorus atom. These electrons are not involved in any bonding and are referred to as lone pairs.
The distribution of these lone pairs on the phosphorus atom and the bromine atoms determines the overall molecular geometry of PBr3. In the case of PBr3, the lone pairs on the phosphorus atom are located in the same plane as the three bromine atoms, resulting in a trigonal pyramidal molecular geometry.
In summary, the PBr3 Lewis structure follows the octet rule by completing the octet of each bromine atom through the formation of covalent bonds with the central phosphorus atom. The remaining valence electrons on the phosphorus atom are distributed as lone pairs, resulting in a trigonal pyramidal molecular geometry.
By understanding the octet rule and the distribution of electrons in the PBr3 molecule, we can gain insights into its chemical bonding and predict its properties and reactivity.
Formal Charges in PBr3 Lewis Structure
The Lewis structure of PBr3, or phosphorus tribromide, is a representation of the molecule that shows how the atoms are connected and the distribution of electrons. In the Lewis structure, we can determine the formal charges on the atoms to understand the electronic distribution within the molecule. Formal charges help us assess the stability and reactivity of a molecule.
Calculation of Formal Charges
To calculate the formal charges in a Lewis structure, we use the formula:
Formal Charge = Valence Electrons – (Number of Lone Pair Electrons + 0.5 * Number of Bonding Electrons)
The valence electrons are the electrons in the outermost shell of an atom. In the case of PBr3, phosphorus (P) has 5 valence electrons, and each bromine (Br) atom has 7 valence electrons.
Determining Formal Charges on Bromine and Phosphorus Atoms
In the Lewis structure of PBr3, the central atom is phosphorus (P), and it is bonded to three bromine (Br) atoms. Let’s determine the formal charges on the bromine and phosphorus atoms.
Phosphorus (P):
– Phosphorus has 5 valence electrons.
– Each bond in the Lewis structure is represented by a pair of electrons, so phosphorus is bonded to three bromine atoms, resulting in 3 bonding pairs.
– There are no lone pairs on phosphorus in the Lewis structure.
Using the formula for formal charges, we can calculate the formal charge on phosphorus:
Formal Charge on Phosphorus = 5 – (0 + 0.5 * 6) = 5 – 3 = +2
Bromine (Br):
– Bromine has 7 valence electrons.
– Each bromine atom in the Lewis structure is bonded to phosphorus, resulting in 1 bonding pair.
– There are no lone pairs on bromine in the Lewis structure.
Using the formula for formal charges, we can calculate the formal charge on bromine:
Formal Charge on Bromine = 7 – (0 + 0.5 * 2) = 7 – 1 = +6
Conclusion
From the calculations, we can conclude that the formal charge on phosphorus in the PBr3 Lewis structure is +2, and the formal charge on each bromine atom is +6. It is important to note that formal charges are hypothetical charges assigned to atoms in a molecule to help us understand the distribution of electrons. These charges do not represent actual charges on the atoms but provide insight into the electron distribution within the molecule.
Understanding the formal charges in a Lewis structure is crucial in predicting the reactivity and behavior of molecules. By analyzing the formal charges, chemists can make informed decisions about the stability and potential reactions of a compound.
Lone Pairs in PBr3 Lewis Structure
Phosphorus tribromide (PBr3) is a chemical compound composed of one phosphorus atom and three bromine atoms. Understanding the Lewis structure of PBr3 is essential in comprehending its molecular geometry, valence electrons, and chemical bonding. In this section, we will explore the concept of lone pairs in the PBr3 Lewis structure and the number of lone electron pairs on both the bromine and phosphorus atoms.
Identification of Lone Electron Pairs in the Structure
In the PBr3 Lewis structure, a lone pair refers to a pair of valence electrons that are not involved in bonding with other atoms. These lone pairs play a crucial role in determining the overall shape and reactivity of the molecule. To identify the lone electron pairs in the PBr3 structure, we need to examine the valence electrons of each atom.
Phosphorus, located in Group 5A of the periodic table, has five valence electrons. Bromine, on the other hand, belongs to Group 7A and possesses seven valence electrons. When we combine these two elements in the PBr3 molecule, we have a total of 5 + (3 x 7) = 26 valence electrons.
To distribute these electrons in the Lewis structure, we first place a single bond between the phosphorus atom and each of the three bromine atoms. This accounts for 6 electrons (3 bonds x 2 electrons per bond). Next, we arrange the remaining 20 electrons around the atoms to satisfy the octet rule, which states that atoms tend to gain, lose, or share electrons to achieve a stable electron configuration with eight valence electrons.
Number of Lone Electron Pairs on Bromine and Phosphorus Atoms
In the PBr3 Lewis structure, each bromine atom is surrounded by three lone pairs of electrons. These lone pairs are not involved in bonding and are represented as dots around the bromine atom. Since each bromine atom has three lone pairs, the total number of lone pairs on the three bromine atoms is 3 x 3 = 9.
On the other hand, the phosphorus atom in the PBr3 molecule also possesses one lone pair of electrons. This lone pair is represented as dots around the phosphorus atom. Therefore, the total number of lone pairs on the phosphorus atom is 1.
To summarize, in the PBr3 Lewis structure, each bromine atom has three lone pairs of electrons, while the phosphorus atom has one lone pair. These lone pairs contribute to the asymmetrical charge distribution within the molecule, influencing its molecular geometry and reactivity.
In the next section, we will delve deeper into the molecular geometry of PBr3 and how the presence of lone pairs affects its shape.
Shape of PBr3 Lewis Structure


The shape of a molecule is determined by its molecular geometry, which refers to the arrangement of atoms in a molecule. In the case of PBr3 (phosphorus tribromide), the Lewis structure provides valuable insights into its molecular geometry.
Molecular geometry of PBr3
The molecular geometry of PBr3 is trigonal pyramidal. This means that the molecule has a central phosphorus atom bonded to three bromine atoms, with one lone pair of electrons on the phosphorus atom. The arrangement of these atoms and lone pair gives PBr3 its distinct shape.
Trigonal pyramidal shape of PBr3
The trigonal pyramidal shape of PBr3 can be visualized as a pyramid with a triangular base. The central phosphorus atom occupies the apex of the pyramid, while the three bromine atoms are positioned at the corners of the triangular base. The lone pair of electrons on the phosphorus atom contributes to the asymmetrical charge distribution in the molecule.
Explanation of the electron and molecular geometry
To understand the electron and molecular geometry of PBr3, let’s analyze the Lewis structure of the molecule. In the Lewis structure, the central phosphorus atom is represented by the letter P, and the bromine atoms are represented by the letter Br.
The Lewis structure of PBr3 can be drawn as follows:
Br
|
Br - P - Br
|
Br
In the Lewis structure, each bond between the phosphorus atom and the bromine atoms is represented by a line, indicating a shared pair of electrons. The lone pair of electrons on the phosphorus atom is represented by a pair of dots.
The valence electrons of phosphorus (group 5A) and bromine (group 7A) are used to form bonds in the molecule. Phosphorus has five valence electrons, while each bromine atom has seven valence electrons. This gives a total of 26 valence electrons for PBr3 (5 from phosphorus and 7 from each bromine atom).
By distributing the valence electrons around the atoms in the Lewis structure, we can determine the electron and molecular geometry. In the case of PBr3, three pairs of electrons are used to form bonds between the phosphorus and bromine atoms, leaving one lone pair of electrons on the phosphorus atom.
The presence of the lone pair of electrons on the phosphorus atom causes repulsion between the electrons, resulting in the trigonal pyramidal shape of PBr3. The repulsion between the lone pair and the bonding pairs pushes the bromine atoms closer together, creating a slight distortion in the bond angles.
In conclusion, the Lewis structure of PBr3 reveals its trigonal pyramidal molecular geometry. Understanding the shape of molecules is crucial in predicting their physical and chemical properties, as well as their reactivity in various chemical reactions.
Hybridization in PBr3 Lewis Structure

In the Lewis structure of PBr3 (phosphorus tribromide), we can determine the hybridization of the central phosphorus atom by calculating its steric number. The steric number is a measure of the number of atoms bonded to the central atom plus the number of lone pairs on the central atom.
Calculation of steric number
To calculate the steric number of the central phosphorus atom in PBr3, we need to count the number of atoms bonded to phosphorus and the number of lone pairs on phosphorus.
In PBr3, there are three bromine atoms bonded to the central phosphorus atom. Each bromine atom contributes one bond to the steric number. Therefore, the number of bonded atoms is 3.
Additionally, phosphorus has one lone pair of electrons. Each lone pair also contributes one to the steric number. Therefore, the number of lone pairs is 1.
By adding the number of bonded atoms (3) and the number of lone pairs (1), we can calculate the steric number of phosphorus in PBr3, which is 4.
Determination of hybridization based on steric number
The steric number of the central atom in a molecule helps us determine its hybridization. In the case of PBr3, the steric number of 4 indicates sp3 hybridization.
In sp3 hybridization, the central atom (phosphorus) forms four sigma bonds by overlapping its hybrid orbitals with the orbitals of the surrounding atoms (bromine). The four sigma bonds are formed by the overlap of one s orbital and three p orbitals.
The hybridization of the central atom affects the molecular geometry and the angles between the bonded atoms. In the case of PBr3, the sp3 hybridization results in a tetrahedral molecular geometry with bond angles of approximately 109.5 degrees.
To visualize the hybridization and molecular geometry of PBr3, we can draw the Lewis structure, which shows the arrangement of atoms and the bonding between them.
Atom | Hybridization |
---|---|
Phosphorus (P) | sp3 |
Bromine (Br) | sp3 |
Summary
In summary, the hybridization of the central phosphorus atom in the PBr3 Lewis structure is sp3. This hybridization is determined by calculating the steric number, which is the sum of the number of bonded atoms and the number of lone pairs on the central atom. The sp3 hybridization results in a tetrahedral molecular geometry with bond angles of approximately 109.5 degrees.
Resonance in PBr3 Lewis Structure
The Lewis structure of a molecule provides a visual representation of its atomic arrangement and bonding. In the case of phosphorus tribromide (PBr3), understanding its Lewis structure can help us comprehend its chemical properties and behavior. While resonance structures are commonly observed in many molecules, PBr3 does not exhibit resonance due to the absence of formal charges and double/triple bonds.
Explanation of resonance structures
Resonance structures are alternative Lewis structures that can be drawn for a molecule by shifting electrons and rearranging bonds. These structures differ only in the placement of electrons, while the positions of atoms remain the same. Resonance occurs when a molecule can be represented by multiple resonance structures, indicating that the actual structure is a hybrid of these possibilities.
Resonance is often observed in molecules with delocalized electrons, such as those found in conjugated systems or molecules with multiple bonds. The presence of resonance contributes to the stability and reactivity of these compounds. However, in the case of PBr3, the absence of formal charges and double/triple bonds prevents the formation of resonance structures.
Inability to form resonance structures in PBr3 due to lack of formal charges and double/triple bonds
Phosphorus tribromide (PBr3) consists of one phosphorus (P) atom bonded to three bromine (Br) atoms. The Lewis structure of PBr3 can be determined by considering the valence electrons of each atom. Phosphorus has five valence electrons, while bromine has seven. Therefore, the total number of valence electrons in PBr3 is 26 (5 from phosphorus + 3 × 7 from bromine).
To construct the Lewis structure, we start by placing the atoms in a symmetrical arrangement, with the phosphorus atom in the center and the three bromine atoms surrounding it. Each bromine atom forms a single bond with the phosphorus atom, resulting in a total of three covalent bonds.
Since each bond consists of two electrons, the three covalent bonds account for six electrons. This leaves us with 20 remaining electrons to distribute. We place these electrons as lone pairs around the bromine atoms, ensuring that each atom satisfies the octet rule (except for phosphorus, which can expand its valence shell).
The resulting Lewis structure of PBr3 shows an asymmetrical distribution of electrons, with the central phosphorus atom surrounded by three bromine atoms. The structure does not contain any formal charges or double/triple bonds, which are essential for the formation of resonance structures.
In conclusion, the Lewis structure of PBr3 does not exhibit resonance due to the absence of formal charges and double/triple bonds. While resonance is a common phenomenon in many molecules, PBr3’s structure remains asymmetrical and does not allow for the delocalization of electrons. Understanding the absence of resonance in PBr3 is crucial for comprehending its chemical properties and reactivity.
Polarity of PBr3 Lewis Structure
The polarity of a molecule refers to the distribution of charges within the molecule, which can affect its physical and chemical properties. In the case of the PBr3 Lewis structure, the polarity arises from the electronegativity difference between the phosphorus (P) and bromine (Br) atoms, as well as the formation of polar bonds and resulting dipole moment.
Definition of polarity in molecules
Polarity in molecules is determined by the presence of polar bonds and the overall molecular geometry. A polar bond occurs when there is an unequal sharing of electrons between two atoms due to differences in electronegativity. This results in a partial positive charge on one atom and a partial negative charge on the other.
Calculation of electronegativity difference between phosphorus and bromine atoms
Electronegativity is a measure of an atom’s ability to attract electrons towards itself in a chemical bond. The difference in electronegativity between two atoms can be used to determine the polarity of the bond between them. In the case of PBr3, phosphorus has an electronegativity of 2.19, while bromine has an electronegativity of 2.96.
By subtracting the electronegativity of phosphorus from that of bromine (2.96 – 2.19), we find that the electronegativity difference is 0.77. This indicates that the P-Br bond is polar, with the bromine atom being slightly more electronegative and carrying a partial negative charge, while the phosphorus atom carries a partial positive charge.
Formation of polar bonds and resulting dipole moment
In the PBr3 molecule, there are three P-Br bonds. Each bond is formed by the sharing of one electron from the phosphorus atom and one electron from the bromine atom. However, due to the electronegativity difference mentioned earlier, the bromine atom attracts the shared electrons more strongly, resulting in an uneven distribution of charge.
As a result, each P-Br bond has a dipole moment, which is a measure of the separation of positive and negative charges within a bond. The dipole moment points towards the bromine atom, indicating that the bromine end of the bond is partially negative, while the phosphorus end is partially positive.
Conclusion that PBr3 is a polar molecule
Based on the presence of polar bonds and the resulting dipole moment, we can conclude that the PBr3 molecule is polar. The three polar P-Br bonds in the molecule do not cancel each other out due to the trigonal pyramidal molecular geometry of PBr3.
In summary, the PBr3 Lewis structure exhibits polarity due to the electronegativity difference between phosphorus and bromine atoms, the formation of polar bonds, and the resulting dipole moment. Understanding the polarity of molecules like PBr3 is crucial in predicting their behavior in chemical reactions and interactions with other substances.
Bond Angle in PBr3 Lewis Structure
The bond angle in the Lewis structure of PBr3, or phosphorus tribromide, is an important characteristic that helps us understand the molecule’s shape and properties. In this section, we will explore the expected bond angle in tetrahedral geometry and discuss the influence of lone electron pairs on the bond angle in PBr3.
Expected bond angle in tetrahedral geometry
In a tetrahedral geometry, such as the one found in PBr3, the central atom (phosphorus, P) is surrounded by four electron pairs. Three of these electron pairs are involved in bonding with the three bromine atoms (Br), while the fourth electron pair is a lone pair on the phosphorus atom. This arrangement results in a symmetrical tetrahedral shape.
The expected bond angle in a tetrahedral geometry is 109.5 degrees. This angle is determined by the repulsion between the electron pairs around the central atom. Since all four electron pairs in a tetrahedral geometry experience the same repulsion, the bond angles are evenly distributed around the central atom.
Influence of lone electron pairs on bond angle in PBr3
However, the presence of lone electron pairs can affect the bond angle in a molecule. Lone pairs exert a stronger repulsive force compared to bonding pairs. This is because lone pairs are localized on a single atom and are not shared with another atom, resulting in a higher electron density.
In the case of PBr3, the lone pair on the phosphorus atom exerts a repulsive force on the bonding pairs. This repulsion causes the bond angles to deviate slightly from the expected 109.5 degrees. The lone pair pushes the bonding pairs closer together, resulting in a smaller bond angle.
Conclusion
In conclusion, the bond angle in the PBr3 Lewis structure is approximately 101 degrees. This angle is slightly smaller than the expected bond angle in a tetrahedral geometry due to the repulsion from the lone pair on the phosphorus atom. Understanding the bond angle in PBr3 helps us comprehend its molecular geometry and predict its chemical behavior.
By examining the bond angle in the Lewis structure of PBr3, we gain insights into the molecule’s shape and the influence of lone electron pairs. This knowledge is valuable in various fields, including chemistry, materials science, and pharmaceutical research.
Uses of PBr3
Phosphorus tribromide (PBr3) is a versatile compound that finds various applications in different fields. Let’s explore some of the key uses of PBr3:
Formation of Alkyl Bromides
PBr3 is commonly used in organic chemistry as a reagent for the conversion of alcohols into alkyl bromides. This reaction, known as the Appel reaction, involves the substitution of an alcohol’s hydroxyl group with a bromine atom. The resulting alkyl bromides are important intermediates in the synthesis of various organic compounds, such as pharmaceuticals and agrochemicals.
Brominating Agent in Organic Chemistry
PBr3 is also utilized as a brominating agent in organic chemistry. It can selectively brominate certain functional groups, such as alkenes and aromatic compounds. This bromination process is valuable for introducing bromine atoms into specific positions of a molecule, allowing chemists to modify its properties and reactivity.
Analysis of Oxygen and Sugar
In analytical chemistry, PBr3 is employed for the analysis of oxygen and sugar. It reacts with oxygen to form phosphorus oxybromide (POBr3), which can be quantitatively measured. This reaction is utilized in the determination of oxygen content in various substances, including gases and liquids.
Additionally, PBr3 can react with sugars, such as glucose, to form brominated sugar derivatives. These derivatives can be easily identified and quantified, enabling the analysis of sugar content in different samples.
Catalyst in Various Syntheses
PBr3 acts as a catalyst in several synthesis reactions. It facilitates the formation of carbon-phosphorus bonds, which are crucial in the synthesis of organophosphorus compounds. These compounds have diverse applications, ranging from pharmaceuticals to flame retardants.
Fire Suppressant Compound for Halon 1301
Halon 1301 is a widely used fire suppressant compound, particularly in fire extinguishing systems for sensitive electronic equipment. PBr3 is an essential component in the synthesis of Halon 1301. It plays a crucial role in the production of bromotrifluoromethane (CF3Br), the active ingredient in Halon 1301. This compound effectively extinguishes fires by interrupting the chemical reactions that sustain combustion.
In conclusion, PBr3, with its unique properties and reactivity, finds a wide range of applications in various fields. From its role in the formation of alkyl bromides and brominating agents in organic chemistry to its use in the analysis of oxygen and sugar, as well as its catalytic properties in synthesis reactions and contribution to fire suppression, PBr3 continues to be a valuable compound in the scientific community.
Conclusion
In conclusion, the Lewis structure of PBr3 (phosphorus tribromide) has been determined. The central phosphorus atom is surrounded by three bromine atoms, each forming a single bond. This results in a trigonal pyramidal shape with a lone pair of electrons on the phosphorus atom. The Lewis structure provides valuable information about the arrangement of atoms and electrons in a molecule, allowing us to understand its chemical properties and reactivity. By analyzing the Lewis structure of PBr3, we can gain insights into its behavior in various chemical reactions and its role in organic synthesis.
Frequently Asked Questions
Q: What is the structure of phosphorus tribromide (PBr3)?
A: Phosphorus tribromide (PBr3) has a pyramidal structure, with the phosphorus atom at the apex and three bromine atoms forming a triangular base.
Q: What is the molecular geometry of PBr3?
A: The molecular geometry of PBr3 is trigonal pyramidal.
Q: How many valence electrons does PBr3 have?
A: Phosphorus tribromide (PBr3) has 10 valence electrons.
Q: What is the Lewis structure of PBr3?
A: The Lewis structure of PBr3 consists of a phosphorus atom bonded to three bromine atoms, with each bromine atom having a lone pair of electrons.
Q: Is the Lewis structure of PBr3 polar or nonpolar?
A: The Lewis structure of PBr3 is polar due to the presence of a lone pair on the central phosphorus atom.
Q: What is the hybridization of PBr3?
A: The hybridization of PBr3 is sp3.
Q: What is the shape of PBr3?
A: The shape of PBr3 is pyramidal.
Q: How many valence electrons are there in the Lewis dot structure of PBr3?
A: The Lewis dot structure of PBr3 has a total of 10 valence electrons.
Q: What is the chemical bonding in PBr3?
A: Phosphorus tribromide (PBr3) exhibits covalent bonding.
Q: What is the formal charge in the Lewis structure of PBr3?
A: In the Lewis structure of PBr3, the formal charge on the phosphorus atom is zero, while each bromine atom has a formal charge of zero.