15 Facts on HCl + XeF2: What, How To Balance & FAQs

XeF2 is a halogenated molecule of inert element and it can react with strong acids like hydrochloric. Let us see the mechanism and reaction pathway of the HCl and XeF2.

Xenon difluoride is basic due to presence the of lone pairs over the Xe and for this reason, it reacts with acid and forms the corresponding salt. The reaction between XeF2 and HCl does not require any type of catalyst because both are reactive enough that they can react together without temperature and pressure.

By this reaction, we can find the amount of chlorine and strength of the acid. In this article, we will learn more about reactions like enthalpy, redox reaction, intermolecular force, conjugate pairs, etc with an explanation in the following part of the article.

1. What is the product of HCl and XeF2?

Hydrofluoric acid along with chlorine and some amount of Xe will be produced when HCl reacts with XeF2 at normal conditions.

Products of the Reaction
Between HCl and XeF2

2. What type of reaction is HCl + XeF2?

The reaction between HCl + XeF2 is generally an acid-base reaction, along with some redox reaction and also a displacement reaction mechanism observed.

3. How to balance HCl + XeF2?

HCl + XeF2 = Xe + HF + Cl2 this reaction is not balanced yet because the L.H.S of the reaction is not equal to the R.H.S., so we have to balance the equation in a few steps,

Step 1 – Labelling all the reactants and products by the required number of alphabets

We labeled all the molecules in the part of the reactant as well as the product side by A, B, C, D, and E as there is a total of five molecules present unbalanced. Now the reaction reduces to,

A HCl + B XeF2 = C HF + D Xe + E Cl2

Step 2 – Equating all the Coefficients for all the same type of elements by rearranging them

Arranging all the same elements by their stoichiometric proportion and coefficients we get,

H = A = C, Cl = A = 2E, Xe = B = D, F = 2B = D,

Step 3 – Using Gaussian elimination to determine the coefficient values

Using the Gaussian elimination and equating all the equations we get, A = 2, B = 1, C = 2, D = 1

Step 4- Now write the whole equation in the balanced form

The overall balanced equation will be,

2HCl + XeF2 = 2 HF + Xe + Cl2

4. HCl + XeF2 titration

To estimate the quantity of Cl as well as the strength of acid we can perform a titration between XeF2 and HCl in the following way,

Apparatus used

We need a burette, conical flask, burette holder, volumetric flask, and beakers for this titration.

Titre and titrant

HCl versus XeF2, HCl acts as titrant which is taken in the burette and the molecule to be analyzed is XeF2 which is taken in a conical flask.


The whole titration is done in an acidic medium or acidic pH so the best suitable indicator will be phenolphthalein which gives perfect results for this titration at given pH.


The burette was filled with standardized HCl and XeF2 was taken in a conical flask along with the respective indicator. Then the titration was started by adding HCl dropwise to the conical flask and the flask was shaking constantly. After a certain time when the endpoint arrived indicator changes its color.

We repeat the titration several times for better results and then we estimate the strength of HCl by the formula V1S1 = V2S2.

5. HCl+ XeF2 net ionic equation

The reaction HCl + XeF2 give several ions are and some molecules are dissociated into ions, like chloride, and Fluoride along with proton but Xe cannot be dissociated.

H+ + Cl + XeF2 = H+ + F + Xe + Cl2

6. HCl+ XeF2 conjugate pairs

In the reaction between HCl + XeF2 the Conjugate part is the counter part of the acid molecule without protonic form which are listed below,

  • Conjugate pair of HCl = Cl
  • Conjugate pair of F = HF

7. HCl and XeF2 intermolecular forces

The ionic and electrostatic forces are present in HCl as also dipole interaction and for the XeF2. There are ionic forces along with covalent interaction present In chlorine. Also H-bonding present in HF there is covalent interaction along with van der waal’s interaction present.

Van der waal’s, and
dipole interaction
XeF2covalent, van der waal’s
HFIonic, Strong electrostatic,
XeNo force
Intermolecualr Forces

8.     HCl + XeF2 reaction enthalpy

The reaction enthalpy for the above reaction HCl + XeF2 is, -150.13 KJ/mol which can be obtained by the formula enthalpy of products – enthalpy of reactants, and here the change in enthalpy is negative.

Reaction Enthaply of

9.     Is HCl + XeF2 a buffer solution?

The reaction between HCl + XeF2 gives a buffer solution of Xe and Chlorine which can control the pH of the solution as it has both acidic as well as basic characteristics at certain pH.

10. Is HCl + XeF2 a complete reaction?

The reaction between HCl + XeF2 is a complete reaction as it gives two complete products HF, Cl2, and Xe.

11. Is HCl + XeF2 an exothermic or endothermic reaction?

The reaction of HCl + XeF2 indicates it is an exothermic process based on thermodynamics. Because The change of enthalpy for the reaction is negative. On the other hand, the reactant released heat in the course of the reaction or we can say δH = HProducts-Hreactans < 0.

12. Is HCl + XeF2 a redox reaction?

The reaction HCl + XeF2 is a redox reaction where Cl gets oxidized and Xe is reduced. The oxidation number of F also got changed.

Redox Schematic of reaction
between HCl and XeF2

13. Is HCl + XeF2 a precipitation reaction

The reaction between HCl + XeF2 is a precipitation reaction, where Cl precipitated and HF can be soluble in water, and Xe remains insoluble in the medium.

14. Is HCl + XeF2 reversible or irreversible reaction?

The reaction between HCl + XeF2 is always irreversible in nature, the reaction can only proceed in the forward direction. Because due to the reduction potential of Cl it cannot react with HF.

Irreversible Reaction
Between HCl and XeF2

15. Is HCl + XeF2 displacement reaction?

The reaction between HCl + XeF2 is a displacement reaction where F gets displaced from XeF2 to H site.


To estimate the quantity of F we can use the titration between XeF2 and HCl because XeF2 is the raw form where F is stored. By this reaction, we also estimate the strength of Xe. The reaction does not require any catalyst air temperature because it is an exothermic reaction.

Biswarup Chandra Dey

Hi......I am Biswarup Chandra Dey, I have completed my Master's in Chemistry from the Central University of Punjab. My area of specialization is Inorganic Chemistry. Chemistry is not all about reading line by line and memorizing, it is a concept to understand in an easy way and here I am sharing with you the concept about chemistry which I learn because knowledge is worth to share it.

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