Hydrogen Chloride (HCl) and Sodium Sulfate(Na_{2}SO_{4}) both are inorganic chemicals where HCl is in liquid form and Na_{2}SO_{4} is a white solid. Let us talk about HCl and Na_{2}SO_{4} reactions.

**HCl or muriatic acid is a chemical compound present in dilute and concentric forms and is used for analyses of other chemicals. Na_{2}SO_{4} is known as the sulfate of soda and is highly soluble in water .**

In the following sections of this article, we will talk about the products of HCl and Na_{2}SO_{4} with their conjugate pairs, reaction type, titration, and net ionic products in detail.

**What is the product of HCl and ****Na**_{2}SO_{4}

**Na**

_{2}SO_{4}**The products formed are Sodium chloride (NaCl) and Sulphuric acid (H_{2}SO_{4}) by the reaction of HCl and Na_{2}SO_{4}.**

**HCl + Na_{2}SO_{4}= NaCl + H_{2}SO_{4}**

**What type of reaction is HCl + ****Na**_{2}SO_{4}

**Na**

_{2}SO_{4}**The reaction of HCl with Na_{2}SO_{4} is a double replacement type of reaction. In the reaction, the cations H^{+} and 2Na^{+} and anions Cl^{–} and SO_{4}^{–} combine to form two different products that are NaCl and H_{2}SO_{4}, and replace both reactants.**

**How to balance HCl + ****Na**_{2}SO_{4}

**Na**

_{2}SO_{4}**To balance HCl + Na_{2}SO_{4} reaction following steps must be followed**

**Step 1 – As the coefficients are 4 so label them as A, B, C, and D****– A HCl + B****Na**= C NaCl + D_{2}SO_{4}**H**_{2}SO_{4}

**Step 2 – modify the atoms with suitable numbers as the coefficients are already labeled**–**A = D = H, B = C = Na, C = A = Cl, D = B = SO**_{4}

**Step 3 – Multiply the atoms coefficient with a suitable number**–**A = D = 2, B = C = 1, C = A = 2, D = B = 1**

**Step 4 – reduce the result of the lowest integer value, the final equation is –****2 HCl + Na**_{2}SO_{4}= 2 NaCl + H_{2}SO_{4}

**HCl + Na**_{2}SO_{4} titration

_{2}SO

_{4}titration

**The titration between HCl and Na _{2}SO_{4} is not possible because they form NaCl and H_{2}SO_{4} as products and due to this acid formation it is not possible to calculate the endpoint and concentration of the unknown solution.**

**HCl + Na**_{2}SO_{4} net ionic equation

_{2}SO

_{4}net ionic equatio

**The net ionic equation is – H ^{+ }+ Cl^{–}+ Na^{+} + SO_{4}^{–} = Na^{+} + Cl^{–} + H**

^{+ }

**+**

**SO**_{4}^{–}**First, write the full equation with their respective states**

**(l) HCl + (s) Na_{2}SO_{4} = (s) NaCl + (l) H_{2}SO_{4}**

**Now, split the atoms into ions which is the net ionic reaction**

**H ^{+} + Cl^{–} + Na^{+} + SO_{4}^{–} = Na^{+} + Cl^{–} + H^{+} + SO_{4}^{–}**

**HCl + Na**_{2}SO_{4} conjugate pairs

_{2}SO

_{4}conjugate pairs

**The conjugate pair of HCl acid is Cl**.^{–}base

**The conjugate pair of the Na**_{2}SO_{4}base is H**SO**acid._{4}^{–}

**HCl and Na**_{2}SO_{4} intermolecular forces

_{2}SO

_{4}intermolecular forces

**The intermolecular forces that bind HCl are dipole-dipole interactions and the London dispersion force of attraction.**

**In Na**_{2}SO_{4}the following intermolecular forces are applied, strong electrostatic force and weak electrostatic force

**HCl + Na**_{2}SO_{4} reaction enthalpy

_{2}SO

_{4}reaction enthalpy

**The reaction enthalpy is zero for the reaction, HCl + Na _{2}SO_{4}**

**= NaCl + H**

_{2}SO_{4}because the change in energy of the reaction is positive which signifies, that no external energy is given to the reactants.**Is HCl + Na**_{2}SO_{4} a buffer solution

_{2}SO

_{4}a buffer solution

**The reaction of HCl and Na _{2}SO_{4} cannot act as a buffer solution because the products of the reaction are NaCl which is a strong base and H_{2}SO_{4} which is a strong acid, and strong acid and base together cannot be a buffer solution.**

**Is HCl + Na**_{2}SO_{4} a complete reaction

_{2}SO

_{4}a complete reaction

**HCl + Na _{2}SO_{4} is a complete reaction. The products of the reaction are NaCl and H_{2}SO_{4} one is a complete complex of salt (NaCl) and the other is a strong acid (H_{2}SO_{4}) both are complete complexes of chemical compounds.**

**Is HCl + Na**_{2}SO_{4} an exothermic or endothermic reaction

_{2}SO

_{4}an exothermic or endothermic reaction

**The reaction of HCl and Na _{2}SO_{4} is an exothermic reaction. The dissociation of bonds between HCl and Na_{2}SO_{4} heats up by releasing a good amount of energy.**

**Is HCl + Na**_{2}SO_{4} a redox reaction

_{2}SO

_{4}a redox reaction

**HCl +Na _{2}SO_{4} is a redox reaction as the product of the reaction HCl + Na_{2}SO_{4} is NaCl which is reduced whereas, H_{2}SO_{4} is oxidized at the end of the reaction.**

**Is HCl + Na**_{2}SO_{4} a precipitation reaction

_{2}SO

_{4}a precipitation reaction

**HCl + Na _{2}SO_{4} is not a precipitation reaction. The products are NaCl and H_{2}SO_{4} which is a liquid itself but NaCl is a salt that is highly soluble in liquid and no precipitation of any chemical compound takes place.**

**Is HCl + Na**_{2}SO_{4} **reversible or irreversible reaction**

_{2}SO

_{4}

**HCl + Na _{2}SO_{4} irreversible reaction. The final products are NaCl and H_{2}SO_{4} both are complete complexes of chemical compounds and cannot be reversed as reactants.**

**Is HCl + Na**_{2}SO_{4} displacement reaction

_{2}SO

_{4}displacement reaction

**HCl + Na _{2}SO_{4} is a displacement reaction. In this reaction, the Na^{2+} ion displaces the H^{+ ion to form NaCl, and the }hydrogen ion also displaces SO^{4- }to form H_{2}SO_{4} as the final product.**

**Conclusion**

The strong acid HCl is mostly used for the analysis of various organic compounds or acid-base analyses too. Na_{2}SO_{4} is used as a drying material in detergent making and in making paper pulp in the kraft process as well.