HBr and SrCO3 are inorganic compounds with chemical names hydrogen bromide and strontium carbonate. Let us understand more about their reaction in this article.
HBr exists as a colorless gas at room temperature and forms a strong acid when dissolved in water. SrCO3 is a white or grey-appearing, odorless solid. It is a weak base and hence reacts with acids. The reaction of HBr + SrCO3 is a strong acid-weak base reaction.
In this article, we will be looking into important properties and characteristics of HBr + SrCO3 reaction like the type of reaction, product, intermolecular forces, titration, etc.
What is the product of HBr and SrCO3?
Strontium bromide(SrBr2), carbon dioxide(CO2), and water(H2O) are formed when HBr reacts with SrCO3.
SrCO3 + 2HBr –> SrBr2 + CO2 + H2O
What type of reaction is HBr + SrCO3?
HBr + SrCO3 is considered as a neutralization reaction. Here, the weak base SrCO3 neutralizes the strong acid HBr, giving salt and water.
How to balance HBr + SrCO3?
The reaction of HBr + SrCO3 can be balanced by following the steps given below.
- Write the equation such that reactants are on the left side and the products are on the right side.
SrCO3 + HBr –> SrBr2 + CO2 + H2O
- To balance the equation, the total number of atoms on the left side must be equal to the number of atoms on the right side
- Tabulate the number of atoms of each element on both sides.
| Elements | Reactants side | Products side |
|---|---|---|
| Strontium (Sr) | 1 | 1 |
| Carbon (C) | 1 | 1 |
| Oxygen (O) | 3 | 3 |
| Hydrogen (H) | 1 | 2 |
| Bromine (Br) | 1 | 2 |
- We see which elements have an imbalanced number of atoms on each side. In this case, hydrogen and bromine are in imbalance.
- Now start by balancing the element that has the higher atomic number. Here it is bromine, among bromine and hydrogen.
- To balance the number of bromines on each side, we can put 2 as the stoichiometric coefficient of HBr.
SrCO3 + 2HBr –> SrBr2 + CO2 + H2O
- Now tabulate the number of atoms of each element on both the reactant and product sides.
| Elements | Reactants side | Products side |
|---|---|---|
| Strontium (Sr) | 1 | 1 |
| Carbon (C) | 1 | 1 |
| Oxygen (O) | 3 | 3 |
| Hydrogen (H) | 2 | 2 |
| Bromine (Br) | 2 | 2 |
We can see that all the elements are now balanced on both sides, and is now a balanced equation.
HBr + SrCO3 titration
HBr and SrCO3 can be titrated in the following way to estimate the strength of the HBr solution.
Apparatus
Burette, burette holder, conical flask, spatula, glass rod, wash bottle, measuring cylinder
Indicator
Methyl orange is the indicator used for this titration. It is a good indicator for titrations involving strong acid and weak base.
Procedure
- Prepare 0.1 N SrCO3 solution in a conical flask by weighing out 0.147 g of SrCO3, and mixing it with 10 mL water.
- Add 2-3 drops of methyl orange into the SrCO3 solution.
- Load the HBr solution into the burette. Open the knob such that the solution falls drop-wise.
- Swirl and stir the conical flask continuously, and when the color of the solution becomes red, close the burette knob immediately.
- Note down the volume readings and continue the process until three consistent readings are obtained.
- The strength of the HBr solution can be obtained by using the formula
NHBr x VHBr = NSrCO3 x VSrCO3
Where N is the normality, which is also the strength in this case, and V is the volume.
HBr + SrCO3 net ionic equation
The net ionic equation of HBr + SrCO3 is as follows:
SrCO3 (s) + 2H+ (aq) + 2Br– (aq) –> Sr2+ (aq) + 2Br– (aq) + H2O (l)+ CO2(g)
The ionic equation can be written for this reaction by the following method:
- Write down the balanced equation of HBr + SrCO3 reaction
SrCO3 + 2HBr –> SrBr2 + CO2 + H2O
- Now write the ionic form of each compound in an aqueous solution.
- SrCO3 is almost insoluble and remains a solid, while HBr readily dissociates into H+ and Br–. On the product side, SrBr2 dissociates into Sr2+ ions and Br– ions, while H2O stays liquid and CO2 remains as gas.
- The resulting equation is the net ionic equation
HBr + SrCO3 conjugate pairs
HBr + SrCO3 has the following conjugate pairs,
- HBr and SrBr2 is one conjugate acid-base pair, where HBr is the Bronsted acid, and SrBr2 is its conjugate base.
- SrCO3 and H2O is the other conjugate acid-base pair, where SrCO3 is the Bronsted base, and H2O is its conjugate acid.
HBr and SrCO3 intermolecular forces
HBr + SrCO3 has the following intermolecular forces,
- The intermolecular forces holding HBr are dipole-dipole forces.
- In SrCO3, the intermolecular forces are electrostatic forces of attraction.
HBr + SrCO3 reaction enthalpy
The standard reaction enthalpy for HBr + SrCO3 reaction is -104.0 kJ/mol
ΔrH˚ = -104.0 kJ/mol
Is HBr + SrCO3 a buffer solution?
HBr + SrCO3 is a buffer solution. A weak base and strong acid will form a buffer solution.
Is HBr + SrCO3 a complete reaction?
HBr + SrCO3 reaction is a complete reaction as all reactants get converted into products.
Is HBr + SrCO3 an exothermic or endothermic reaction?
HBr + SrCO3 reaction is exothermic, as the reaction enthalpy is negative.
Is HBr + SrCO3 a redox reaction?
HBr + SrCO3 reaction is not a redox reaction as neither oxidation nor reduction of atoms occur.
Is HBr + SrCO3 a precipitation reaction?
HBr + SrCO3 reaction is not a precipitation reaction as no precipitation of products occurs. H2O is a liquid, CO2 is a gas, and SrBr2 is a solid that is soluble in water.
Is HBr + SrCO3 reversible or irreversible reaction?
HBr + SrCO3 reaction is an irreversible reaction under normal conditions as CO2 gas escapes.
Is HBr + SrCO3 displacement reaction?
HBr + SrCO3 reaction is a double displacement reaction. Here Sr2+ and H+ displace each other during this reaction to form the products SrBr2, CO2, and H2O.
Conclusion
In this article, we have seen the answers to some common questions on the HBr + SrCO3 reaction. The product of the reaction, SrBr2, has multiple industrial applications.
Hi….My name is Hariny Rajadurai. I am a graduate of IISER,
Thiruvananthapuram with an Integrated Master’s in Science. I did my major in Chemistry and minor in Biology. During my degree, I worked in supramolecular chemistry and polymer chemistry. I have worked as a Research Associate at a startup where I worked with polymers. I like to write and explain difficult topics in a simplistic way for my readers.