H_{2}SO_{4} + Zn(NO_{3})_{2} displays how the reaction between H_{2}SO_{4} and Zn(NO_{3})_{2} is happening. Let us discuss how Zn(NO_{3})_{2} reacts with H_{2}SO_{4} in this article.

**Zinc Nitrate [Zn(NO _{3})_{2}] reacts with Sulphuric acid [H_{2}SO_{4}] to form salt and an acid. H_{2}SO_{4} is an acid and a strong dehydrating agent common in organic chemistry as a dehydrator. Zn(NO_{3})_{2} is a colourless, crystalline inorganic compound that is soluble in both alcohol and water. It is found in its Zn(NO_{3})_{2}.6H_{2}O form.**

This article will help you to learn about interesting facts of H_{2}SO_{4} + Zn(NO_{3})_{2}, like reaction enthalpy, intermolecular forces and chemical equation as follows:

**What is the product of H**_{2}SO_{4 }and Zn(NO_{3})_{2}

_{2}SO

_{4 }and Zn(NO

_{3})

_{2}

**Zinc Sulphate (ZnSO _{4}) and Nitric acid (HNO_{3}) are the products formed in the H_{2}SO_{4} + Zn(NO_{3})_{2} reaction. The chemical equation for the reaction is,**

**Zn(NO _{3})_{2} + H_{2}SO_{4} = ZnSO_{4} + HNO_{3}**

**What type of reaction is H**_{2}SO_{4} + Zn(NO_{3})_{2}

_{2}SO

_{4} + Zn(NO

_{3})

_{2}

**H _{2}SO_{4} + Zn(NO_{3})_{2} is a double displacement reaction.**

**How to balance H**_{2}SO_{4} + Zn(NO_{3})_{2}

_{2}SO

_{4} + Zn(NO

_{3})

_{2}

**H _{2}SO_{4} + Zn(NO_{3})_{2} balanced chemical equation is,**

**Zn(NO _{3})_{2} + H_{2}SO_{4} = ZnSO_{4} + 2HNO_{3}**

**The unbalanced chemical equation for the given reaction is**

**Zn(NO**_{3})_{2}+ H_{2}SO_{4} = ZnSO_{4}+ HNO_{3}

**To check whether the number of atoms present on the both sides of the chemical equation is equal or not.**

**Hydrogen, nitrogen and oxygen atom are not balanced, which can be corrected by multiplying a coefficient of 2 with HNO**_{3}.

**Thus, the balanced chemical equation for H**_{2}SO_{4}+ Zn(NO_{3})_{2}is,

**Zn(NO**_{3})_{2}+ H_{2}SO_{4} = ZnSO_{4}+ 2HNO_{3}

**H**_{2}SO_{4} + Zn(NO_{3})_{2 }titration

_{2}SO

_{4} + Zn(NO

_{3})

_{2 }titration

**Titration of H _{2}SO_{4} and Zn(NO_{3})_{2} is not feasible as H_{2}SO_{4} is an acid but Zn(NO_{3})_{2} is not a base and thus can not be titrated against sulphuric acid.**

**H**_{2}SO_{4} + Zn(NO_{3})_{2} net ionic equation

_{2}SO

_{4} + Zn(NO

_{3})

_{2}net ionic equation

**H _{2}SO_{4} + Zn(NO_{3})_{2} net ionic equation is as follows;**

**No Re Zn^{2+} (aq.) + 2NO_{3}^{–} (aq.) + 2H^{+} (aq.) + SO_{4}^{2-} (aq.) = Zn^{2+} (aq.) + SO_{4}^{2-} (aq.) + 2H^{+ }(aq.) + 2NO_{3}^{–} (aq.)action**

**To obtain the net ionic equation, following steps should be obeyed:**

**Write down the general balanced molecular equation.**

**Zn(NO**_{3})_{2}+ H_{2}SO_{4} = ZnSO_{4}+ 2HNO_{3}

**Specify each compound with its chemical state like solid, liquid or gas.**

**Zn(NO**_{3})_{2}(aq.) + H_{2}SO_{4} (aq.) = ZnSO_{4}(aq.) + 2HNO_{3}(aq.)

**Break the electrolytic compounds into their ionic forms**.

**Eliminate the spectator ions present on the both sides of chemical equation. In our case, all the ions are spectator ions; therefore, this is a case of No Reaction.**

**H**_{2}SO_{4} + Zn(NO_{3})_{2} conjugate pairs

_{2}SO

_{4} + Zn(NO

_{3})

_{2}conjugate pairs

**The H _{2}SO_{4} + Zn(NO_{3})_{2} does not form a conjugate pair**,

**The conjugate pair of HNO**_{3}is its conjugate base NO_{3}^{–}.

**Conjugate pair of H**_{2}SO_{4 }consists H_{2}SO_{4 }and its conjugate base HSO_{4}^{–}.

**H**_{2}SO_{4} + Zn(NO_{3})_{2} intermolecular forces

_{2}SO

_{4} + Zn(NO

_{3})

_{2}intermolecular forces

**H _{2}SO_{4} + Zn(NO_{3})_{2} reaction has the following intermolecular forces,**

**The intermolecular forces between ZnSO**_{4}are ionic bonds.

**H**_{2}SO_{4}molecules contain hydrogen bonding between their molecules.

**Dipole-dipole and London dispersion forces are present in between HNO**_{3}molecules.

**H**_{2}SO_{4} + Zn(NO_{3})_{2} reaction enthalpy

_{2}SO

_{4} + Zn(NO

_{3})

_{2}reaction enthalpy

**H _{2}SO_{4} + Zn(NO_{3})_{2} reaction enthalpy is -4.27 kJ/mol. The standard enthalpy of formation for reactants and products is as follows:**

Molecules | Reaction enthalpy (in kJ/mol) |
---|---|

H_{2}SO_{4} | -909.27 |

Zn(NO_{3})_{2} | -563.89 |

ZnSO_{4} | -1063.16 |

HNO_{3} | -207.36 |

**Reaction enthalpy of compounds**

**Therefore, Δ _{f}H: (Standard enthalpy of formation of products) – (Standard enthalpy of formation of reactants)**

**Δ _{f}H: [ -1063.16 – 207.36] – [-909.27 – 563.89]**

**Δ _{f}H: -4.27 kJ/mol**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2 }a buffer solution

_{2}SO

_{4} + Zn(NO

_{3})

_{2 }a buffer solution

**H _{2}SO_{4} + Zn(NO_{3})_{2} is not a buffer solution because a buffer solution contains weak acid with its conjugate base but here, H_{2}SO_{4} is a strong acid.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2} a complete reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2}a complete reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is a complete reaction and no further process is left.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2} an exothermic or endothermic reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2}an exothermic or endothermic reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is an exothermic reaction because its reaction enthalpy has slight but negative value.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2} a redox reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2}a redox reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is not a redox reaction. The oxidation states of compounds did not change during reaction progression.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2 }a precipitation reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2 }a precipitation reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is not a precipitation reaction. All the products formed are in an aqueous state.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2} reversible or irreversible reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2}reversible or irreversible reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is an irreversible reaction under normal conditions of temperature and pressure.**

**Is H**_{2}SO_{4} + Zn(NO_{3})_{2} displacement reaction

_{2}SO

_{4} + Zn(NO

_{3})

_{2}displacement reaction

**H _{2}SO_{4} + Zn(NO_{3})_{2} is a double displacement or salt metathesis reaction. H_{2} and Zn displace each other from their respective compounds to form new products.**

**Conclusion**

This article concludes that ZnSO_{4} is an ionic compound formed during the reaction of H_{2}SO_{4} and Zn(NO_{3})_{2}. The ionic equation of H_{2}SO_{4} + Zn(NO_{3})_{2} does not exist as all the components are in an aqueous state. Nitric acid formed in the end should be separated out carefully.