15 Facts on H2SO4 + SrCO3: What, How To Balance & FAQs

SrCO3 (strontium carbonate) is an insoluble metal carbonate, and H2SO4 (sulfuric acid) is a strong inorganic acid. Let us study how they react in detail.

H2SO4 is highly hygroscopic and absorbs moisture from the air and is widely used as a dehydrating agent. SrCO3 is a white odorless solid and is slightly basic in nature. The solubility of SrCO3 is very low (Ksp = 5.6 X 10-10) .

In this article, we will discuss the reaction parameters like enthalpy, molecular forces, and reaction type for the reaction of H2SO4 and SrCO3.

What is the product of H2SO4 and SrCO3

SrSO4 (strontium sulfate), CO2 (carbon dioxide), and water molecules are produced in the reaction H2SO4 + SrCO3.

H2SO4 + SrCO3 → SrSO4 + CO2 + H2O

What type of reaction is H2SO4 + SrCO3

H2SO4 + SrCO3 is a displacement and neutralization reaction as H2SO4 as an acid neutralizes the base SrCO3 to form salt SrSO4. This reaction occurs in two steps,

  • The first step of the reaction is a displacement reaction.
  • H2SO4 + SrCO3 = SrSO4 + H2CO3
  • The second step is neutralization type where decomposition of carbonic acid takes place.
  • H2CO3 = CO2 + H2O
  • Thus overall reaction is
  • H2SO4 + SrCO3 → SrSO4 + CO2 + H2O

How to balance H2SO4 + SrCO3

H2SO4 + SrCO3 is balanced using the following steps-

H2SO4 + SrCO3 → SrSO4 + CO2 + H2O

  • The elements involved are counted on both sides of the reactants and the products in the first step.
Elements involvedIn the reactantsin the products
Number of elements
  • From, the table it is observed that the elements are balanced at either side of the equation.
  • Thus the balanced equation is
  • H2SO4 + SrCO3 → SrSO4 + CO2 + H2O

H2SO4 + SrCO3 titration

For insoluble salts like SrCO3 back titration is performed.


Measuring cylinder, volumetric flask, funnel, burette, beaker, conical flask, pipette


The phenolphthalein indicator is used. The color of phenolphthalein in acidic and basic medium respectively are,

H2In(colorless) → In2- (pink)


  • A known amount of SrCO3 is taken in a flask. To this, H2SO4 is added and mixed thoroughly and then the solution is transferred to a volumetric flask and is filled up to the mark with the help of distilled water.
  • 20 ml of the prepared solution is taken in a conical flask through a pipette and 3-4 drops of the indicator are added to it.
  • The standard NaOH solution is taken in the burette and is added dropwise to the resultant solution.
  • The color change is observed and the endpoint is attained when the solution turns light pink in color due to slight excess of NaOH in the solution.
  • The concordant readings are taken that are used for the calculation of the concentration of the carbonate using the formula SV1 = S2V2 .

H2SO4 + SrCO3 net ionic equation

The net ionic equation for H2SO4 + SrCO3 is

2H+(aq)+ SO42-(aq) + SrCO3(s) → SrSO4(s) + CO2(g) + H2O(l)

The net ionic equation is obtained using the following steps

  • In the first step a balanced equation is written.
  • H2SO4 + SrCO3 → SrSO4 + CO2 + H2O
  • The physical states (gas, solid, liquid, or aqueous) are indicated for the species involved in the reaction.
  • H2SO4(aq) + SrCO3(s) → SrSO4(s) + CO2(g) + H2O(l)
  • Splitting of the strong electrolytes into the ions is shown in the next step. Since SrCO3 and SrSO4 are solid and H2O is a weak electrolyte so will not split.
  • 2H+(aq)+ SO42-(aq) + SrCO3(s) → SrSO4(s) + CO2(g) + H2O(l)
  • The common ions are crossed out and thus the net ionic equation is
  • 2H+(aq)+ SO42-(aq) + SrCO3(s) → SrSO4(s) + CO2(g) + H2O(l)

H2SO4 + SrCO3 conjugate pairs

H2SO4 + SrCO3 will make a conjugate pair because,

  • SO42- will be formed as conjugate base of H2SO4 (acid).
  • H2CO3 is the conjugate acid of the base CO32.
conjugate acid-base pair

H2SO4 and SrCO3 intermolecular forces

  • Ionic interactions are present in SrCO3 molecules as the compound is ionic.
  • Dispersion forces, hydrogen bonding, and dipole-dipole interactions are found in the molecules of H2SO4.

H2SO4 + SrCO3 reaction enthalpy

H2SO4 + SrCO3 reaction enthalpy is -99.6 KJ/mol. The enthalpy is calculated using tabulated values and the formula as follows.

Compounds presententhalpy in KJ/mol
Values of enthalpy
  • ∆Hf°(reaction) = ∆Hf°(products) – ∆Hf°(reactants)
  • = -2132.4 – (-2032.8) KJ/mol
  • = -99.6 KJ/mol

Is H2SO4 + SrCO3 a buffer solution

H2SO4 + SrCO3 will not function as a buffer solution as a strong acid (H2SO4) is used and the salt (SrSO4) obtained is insoluble.

Is H2SO4 + SrCO3 a complete reaction

H2SO4 + SrCO3 is a complete reaction as the reactants are completely consumed in the reaction and the products formed will not react further.

Is H2SO4 + SrCO3 an exothermic or endothermic reaction

H2SO4 + SrCO3 is an exothermic reaction as the heat is liberated during the reaction and the enthalpy is also negative.

Is H2SO4 + SrCO3 a redox reaction

H2SO4 + SrCO3 is not a redox reaction as the oxidation states of elements are not changed throughout the reaction.

Is H2SO4 + SrCO3 a precipitation reaction

H2SO4 + SrCO is a precipitation reaction as the product SrSO4 is not soluble and precipitate is formed.

Is H2SO4 + SrCO3 reversible or irreversible reaction

H2SO4 + SrCO is an irreversible reaction due to the increase in entropy for the forward reaction attributed to the formation of CO2 gas and the products obtained will not react to give back the reactants.

Is H2SO4 + SrCO3 displacement reaction

H2SO4 + SrCO is a double displacement reaction in the initial step. Since Sr is more reactive, it displaces hydrogen from its salt and forms strontium sulfate and the H+ ion combines with CO32- ions to form carbonic acid.

H2SO4 + SrCO3 = SrSO4 + H2CO3


The reaction is exothermic with positive entropy. SrCO burns with a red flame and is thus used as a colorant in fireworks. The solid form of CO2 is called dry ice which is used in solidifying oil spills.

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