H_{2}SO_{4} is a mineral acid, and NaH_{2}PO_{4} is a sodium salt. Let us venture through the chemical reaction between H_{2}SO_{4} and NaH_{2}PO_{4} in depth.

**The reaction between H _{2}SO_{4} and NaH_{2}PO_{4 }is a multistep reaction. Concentrated H_{2}SO_{4} is a highly corrosive acid. Pure Sulfuric acid is colorless and oily in nature. NaH_{2}PO_{4}, also known as Monosodium Phosphate is an industrial chemical. It is found in **

**anhydrous**

**, mono and dihydrate forms.**

In this article, we will go through some important aspects, such as the reaction type, balancing equation, reaction enthalpy, ionic equation and some other crucial points.

## What is the product of H_{2}SO_{4} and NaH_{2}PO_{4}?

**Sodium Bisulfate ( NaHSO_{4}**)

**, Sodium Sulfate (**)

**Na**_{2}SO_{4}**and Phosphoric acid (**)

**H**_{3}PO_{4}**are formed when H**.

_{2}SO_{4}reacts with NaH_{2}PO_{4}**H**_{2}SO_{4}+ NaH_{2}PO_{4}==> NaHSO_{4}+ H_{3}PO_{4}(1^{st}step)**NaHSO**_{4}+ NaH_{2}PO_{4}<==> Na_{2}SO_{4}+ H_{3}PO_{4 }(2^{nd}step)

## What type of reaction is H_{2}SO_{4} + NaH_{2}PO_{4}?

**H _{2}SO_{4} + NaH_{2}PO_{4} **is a reversible reaction, a type of stepwise reaction, since it consists of two steps.

## How to balance H_{2}SO_{4} + NaH_{2}PO_{4}?

**The reaction for H _{2}SO_{4} + NaH_{2}PO_{4} **

**is balanced using the following steps**.

**H _{2}SO_{4} + NaH_{2}PO_{4} ==> NaHSO_{4} + H_{3}PO_{4 }(1^{st} step)**

**NaHSO _{4} + NaH_{2}PO_{4} <==> Na_{2}SO_{4} + H_{3}PO_{4 }(2^{nd} step)**

**The number of atoms of reactants and products side must be noted down.**

**For the 1**,^{st}step**the no. of atoms of Na, H, S and O on LHS and RHS is same**.

Element | No. of atoms on LHS (reactant side) | Number of atoms on RHS (Product Side) |

Na | 1 | 1 |

H | 4 | 4 |

S | 1 | 1 |

O | 8 | 8 |

**Balancing chemical equation**

**For the 2nd step****also, the no. of atoms of Na, H, S and O are same.**

Element | No. of atoms on LHS (reactant side) | Number of atoms on RHS (Product Side) |

Na | 2 | 2 |

H | 3 | 3 |

S | 1 | 1 |

O | 8 | 8 |

**Balancing chemical equation**

**It is observed that the equations are already balanced since the number of atoms on LHS and RHS for both equations is the same, and****there is no need to multiply by the stoichiometric coefficient.**

**Finally, the balanced equations are:**

**H**_{2}SO_{4}+ NaH_{2}PO_{4}==> NaHSO_{4}+ H_{3}PO_{4 }

**NaHSO**_{4}+ NaH_{2}PO_{4}<==> Na_{2}SO_{4}+ H_{3}PO_{4 }

**H**_{2}SO_{4} + NaH_{2}PO_{4 }titration

_{2}SO

_{4}+ NaH

_{2}PO

_{4 }titration

**Titration is not feasible since the reaction H_{2}SO_{4} + NaH_{2}PO_{4} comprises multiple steps.**

**H**_{2}SO_{4} + NaH_{2}PO_{4} net ionic equation

_{2}SO

_{4}+ NaH

_{2}PO

_{4}net ionic equation

**The net ionic equations for** **H _{2}SO_{4} + NaH_{2}PO_{4}**

**are:**

**For 1 ^{st} step of reaction**

**2H**^{+}_{(aq)}+SO_{4}^{2-}_{(aq) }+Na^{+}_{(aq)}+ H_{2}PO_{4}^{–}_{(aq) }==> Na^{+}_{(aq) }+HSO_{4}^{–}_{(aq)}+3H^{+}_{(aq)}+ PO_{4}^{3-}_{(aq) }

**For 2 ^{nd} step of reaction**

**Na**^{+}_{(aq) }+HSO_{4}^{–}_{(aq)}+ Na^{+}_{(aq)}+ H_{2}PO_{4}^{–}_{(aq)}<==> 2Na^{+}_{(aq)}+ SO_{4}^{2-}_{(aq)}+ 3H^{+}_{(aq)}+ PO_{4}^{3-}_{(aq)}

**Following steps are used to derive the net ionic equations.**

**Firstly, write the chemical equations with the physical states of the chemical species.****H**_{2}SO_{4(aq)}+ NaH_{2}PO_{4(aq)}==> NaHSO_{4(aq)}+ H_{3}PO_{4(aq) }(1^{st}step)**2H**^{+}_{(aq)}+SO_{4}^{2-}_{(aq) }+Na^{+}_{(aq)}+ H_{2}PO_{4}^{–}_{(aq) }==> Na^{+}_{(aq) }+HSO_{4}^{–}_{(aq)}+3H^{+}_{(aq)}+ PO_{4}^{3-}_{(aq)}**NaHSO**_{4(aq)}+ NaH_{2}PO_{4(aq)}<==> Na_{2}SO_{4(aq)}+ H_{3}PO_{4(aq) }(2^{nd}step)**Na**^{+}_{(aq) }+HSO_{4}^{–}_{(aq)}+ Na^{+}_{(aq)}+ H_{2}PO_{4}^{–}_{(aq)}<==> 2Na^{+}_{(aq)}+ SO_{4}^{2-}_{(aq)}+ 3H^{+}_{(aq)}+ PO_{4}^{3-}_{(aq)}**Thus, there will not be a net ionic reaction for such type of multistep reaction since the second step is not unidirectional.**

## H_{2}SO_{4} + NaH_{2}PO_{4} conjugate pairs

**H**._{2}SO_{4}gives rise to H_{3}O^{+}(Conjugate acid) and HSO_{4}^{–}(Conjugate base) in the presence of water**NaH**_{2}PO_{4}produces H_{2}PO_{4}^{–}as its conjugate base.

## H_{2}SO_{4} and NaH_{2}PO_{4 }intermolecular forces

**In H**_{2}SO_{4 }, Van der Waals dispersion forces, dipole-dipole interactions and Hydrogen bonding are the three main intermolecular forces present.**Ionic bond is the intermolecular force present in NaH**_{2}PO_{4}.

## H_{2}SO_{4} + NaH_{2}PO_{4} reaction enthalpy

**There is no literature available about enthalpy**

**for the reaction of H**.

_{2}SO_{4}and NaH_{2}PO_{4}## Is H_{2}SO_{4} + NaH_{2}PO_{4} a buffer solution?

**H _{2}SO_{4} + NaH_{2}PO_{4 }is not a buffer solution since H_{2}SO_{4} is a strong acid**

**and**

**NaH**

_{2}PO_{4}**is salt of H**

_{3}PO_{4}with strong base NaOH**which are unable to maintain the pH.**

## Is H_{2}SO_{4} + NaH_{2}PO_{4} a complete reaction?

**H _{2}SO_{4} + NaH_{2}PO_{4 }is not a complete reaction since the reaction is not reaching equilibrium in the 2^{nd} step**:

**NaHSO _{4(aq)} + NaH_{2}PO_{4(aq)} <==> Na_{2}SO_{4(aq)} + H_{3}PO_{4(aq) }**.

## Is H_{2}SO_{4} + NaH_{2}PO_{4} an exothermic or endothermic reaction?

**There is no literature elaborating exothermic or endothermic nature for the reaction of** **H _{2}SO_{4}+NaH_{2}PO_{4}**.

## Is H_{2}SO_{4} + NaH_{2}PO_{4} a redox reaction?

**H _{2}SO_{4} + **

**NaH**

_{2}PO_{4 }is not a redox reaction because there is no change in the oxidation state of the chemical species present in the reaction.## Is H_{2}SO_{4} + NaH_{2}PO_{4} a precipitation reaction?

**H _{2}SO_{4} + NaH_{2}PO_{4}** is not a precipitation reaction because acidic pH (due to H

_{2}SO

_{4}) will increase the solubility of NaH

_{2}PO

_{4 }, whose anion dihydrogen phosphate (H

_{2}PO

_{4}

^{–}) is the conjugate base of a weak acid.

## Is H_{2}SO_{4} + NaH_{2}PO_{4} reversible or irreversible reaction?

**H _{2}SO_{4} + NaH_{2}PO_{4}** is reversible in nature because it is a multistep reaction which attains

**dynamic equilibrium**

**.**

## Is H_{2}SO_{4} + NaH_{2}PO_{4} displacement reaction?

**H _{2}SO_{4} + NaH_{2}PO_{4}**

**is not a displacement reaction because it is reversible in nature.**

**Conclusion:**

The reaction between H_{2}SO_{4} + NaH_{2}PO_{4} attains equilibrium but the forward and reverse reaction keep on going at the same rate. Sodium Sulfate is used in Kraft process of paper pulping. While Sodium Bisulfate is used in lowering the pH value and Phosphoric acid used in fertilizers.