H_{2}SO_{4} is an inorganic acid and NaH is a strong base. Let us go through the chemical reaction between H_{2}SO_{4} and NaH in detail.

**The reaction between H _{2}SO_{4} and NaH is a oxidation-reduction type reaction.**

**H**

_{2}SO_{4}is odorless, colorless, hygroscopic in nature. NaH is an alkali metal hydride , it is a strong, odorless, and combustible base used in Organic Synthesis. The Molar Mass of H_{2}SO_{4}is 98.079 g/mol and of NaH is 23.998 g/mol.H_{2}SO_{4} is made by Contact process & NaH by reacting H_{2} & liquid Na, the reactions with NaH occur at solid’s surface. In this article we will learn about the reaction between them.

**What is the product of H**_{2}SO_{4} and NaH?

_{2}SO

_{4}and NaH?

**Sodium Sulfate and Hydrogen gas is evolved when Pure Sulfuric acid reacts with Sodium Hydride**.

**2NaH + H**_{2}SO_{4 }==> Na_{2}SO_{4 }+ 2H_{2}

**What type of reaction is H**_{2}SO_{4} + NaH?

_{2}SO

_{4}+ NaH?

**The reaction NaH + H_{2}SO_{4}**

**is a Double Displacement reaction and exothermic reaction.**

**How to balance H**_{2}SO_{4} + NaH?

_{2}SO

_{4}+ NaH?

**The Unbalanced equation for H _{2}SO_{4} + NaH is as follows**

**NaH + H**_{2}SO_{4}==> Na_{2}SO_{4}+ H_{2}

**To balance the equation following steps are followed:**

**Count the number of atoms on reactant side and product side, which should be same.****If it is not then Stoichiometric coefficient should be added to make them equal.**

Element | No. of atoms on LHS (reactant side) | Number of atoms on RHS (Product Side) |

Na | 1 | 2 |

H | 3 | 4 |

S | 1 | 1 |

O | 4 | 4 |

**Balancing Chemical equation**

**To balance the equation multiply NaH by stoichiometric coefficient 2 on the LHS and on RHS multiply H**_{2}by 2.**Thus the balanced equation is-**

**2NaH + H**_{2}SO4 ==> Na_{2}SO_{4 }+ 2H_{2}

**H**_{2}SO_{4} + NaH titration

_{2}SO

_{4}+ NaH titration

**Titration is not possible in H _{2}SO_{4} + NaH since NaH is a superbase deprotonating various carbon acids. Also, because the reaction need to be carried out in inert atmosphere since it ignites spontaneously in air and reacts vigorously with water.**

**H**_{2}SO_{4} + NaH net ionic equation

_{2}SO

_{4}+ NaH net ionic equation

**The net Ionic equation is****2Na**^{+}_{(aq)}+ 2H^{–}_{(hypothetical)}+ SO_{4}^{2-}_{(aq)}+ 2H^{+}_{(aq)}=**=>**2Na^{+}+SO_{4}^{2-}_{(aq)}+4H^{+}

**To derive the net ionic equation follow below steps-**

**First write chemical equations along with the physical states of the chemical entities**

**2NaH**_{(aq)}+ H_{2}SO_{4 (aq)}==> Na_{2}SO_{4(aq) }+ 2H_{2(g)}

**2Na**^{+}_{(aq)}+ 2H^{–}_{(hypothetical) }+ SO_{4}^{2-}_{(aq) }+ 2H^{+}_{(aq)}=**=>**2Na^{+}+ SO_{4}^{2-}_{(aq)}+ 4H^{+}

**There is no net ionic reaction for such reaction since H**^{– }ions do not exist in the form of a solution and also all the ions are considered to be spectator ions.

**H**_{2}SO_{4} + NaH conjugate pairs

_{2}SO

_{4}+ NaH conjugate pairs

**H**_{2}SO_{4}and water gives rise to H_{3}O^{+}(Conjugate Acid) and HSO_{4}^{–}(Conjugate Base)**NaH gives rise to H**^{–}which is the conjugate base.

**H**_{2}SO_{4} and NaH intermolecular forces

_{2}SO

_{4}and NaH intermolecular forces

**In H**_{2}SO_{4 }, van der Waals dispersion forces, dipole-dipole interactions and hydrogen bonding are present as**intermolecular force**.**For NaH, Electrostatic force such as ionic bond is present as****intermolecular force**. Since Na^{+}and H^{–}are the two ionic species involved.

**H**_{2}SO_{4} + NaH reaction Enthalpy

_{2}SO

_{4}+ NaH reaction Enthalpy

**The enthalpy involved in the reaction between H _{2}SO_{4} and NaH is yet to be studied in detail.**

**Is H**_{2}SO_{4} + NaH a buffer solution?

_{2}SO

_{4}+ NaH a buffer solution?

**H _{2}SO_{4 }+ NaH is not a buffer solution as H_{2}SO_{4} is a strong acid and no conjugate acid or base exists to keep the pH of the solution at approximate constant value.**

**Is H**_{2}SO_{4} + NaH a complete reaction?

_{2}SO

_{4}+ NaH a complete reaction?

**H _{2}SO_{4 }+ NaH**

**is a complete reaction since the reaction achieves equilibrium and the concentration of the chemical species on both the reactant and products side is stable and equal.**

**Is H**_{2}SO_{4} + NaH an exothermic or endothermic reaction?

_{2}SO

_{4}+ NaH an exothermic or endothermic reaction?

**The reaction H_{2}SO_{4 }+ NaH is exothermic in nature since NaH reacts spontaneously with water giving rise to generation of energy in the form of heat.**

**Is H**_{2}SO_{4} + NaH a redox reaction?

_{2}SO

_{4}+ NaH a redox reaction?

**H _{2}SO_{4 }+ NaH** is considered as a redox reaction since H

^{–}changed its oxidation state from -1 to +1.

**Is H**_{2}SO_{4} + NaH a precipitation reaction?

_{2}SO

_{4}+ NaH a precipitation reaction?

**H _{2}SO_{4 }+ NaH** is not a precipitation reaction since all the products formed in aqueous form and are soluble in water.

**Is H**_{2}SO_{4} + NaH reversible or irreversible reaction?

_{2}SO

_{4}+ NaH reversible or irreversible reaction?

**H _{2}SO_{4 }+ NaH** is an irreversible reaction because the reaction is unidirectional.

**Is H**_{2}SO_{4 }+ NaH displacement reaction?

_{2}SO

_{4 }+ NaH displacement reaction?

**H _{2}SO_{4 }+ NaH** is a double displacement reaction because

**in this reaction Na**

^{+}ions from NaH displace H^{+}ions from H_{2}SO_{4}and SO_{4}^{2-}displaces H^{–}from NaH forming Na_{2}SO_{4 }(Sodium Sulfate) and Hydrogen gas.**Conclusion**:

The reaction between H_{2}SO_{4 }and NaH is very abrupt reaction due to the highly reactive nature of NaH. The product formed which is Na_{2}SO_{4 }(Sodium Sulfate) is highly soluble in water has various applications such as diluent in food colors, thermal storage, in commodity industries and as drying agent in organic synthesis.