Manganese (II) carbonate (MnCO_{3}) is a mineral compound but is usually produced through an industrial process. Let us take a look at the reaction of H_{2}SO_{4} and MnCO_{3}.

**H _{2}SO_{4} and MnCO_{3}**

_{ }

**on reaction produce sulphates and water. Sulphuric acid (H**

_{2}SO_{4}) is a strong dehydrating agent and an acid. H_{2}SO_{4}is also known as the oil of vitriol. Manganese (II) carbonate is a faint pink mineral compound insoluble in water under normal conditions. MnCO_{3}adopts octahedral molecular geometry.This article will discuss important facts about H_{2}SO_{4} + MnCO_{3} reactions like products, intermolecular forces, reaction type and balanced chemical equation.

**What is the product of H**_{2}SO_{4} and MnCO_{3}

_{2}SO

_{4}and MnCO

_{3}

**Manganese (II) sulphate (MnSO _{4}), carbon dioxide (CO_{2}) and water are the products of**

**H**

_{2}SO_{4}+ MnCO_{3}reaction.**MnCO _{3} + H_{2}SO_{4} = MnSO_{4} + CO_{2} + H_{2}O**

**What type of reaction is H**_{2}SO_{4} + MnCO_{3}

_{2}SO

_{4}+ MnCO

_{3}

**H _{2}SO_{4} + MnCO_{3} reaction**

**can be considered as an acid-base reaction. Here salt of a weak acid (MnCO**

_{3}) reacts with a strong acid (H_{2}SO_{4}) to generate weak acid (H_{2}CO_{3}) and release water.**How to balance H**_{2}SO_{4} + MnCO_{3}

_{2}SO

_{4}+ MnCO

_{3}

**The balanced chemical equation for the given reaction is:**

**MnCO _{3} + H_{2}SO_{4} = MnSO_{4} + CO_{2} + H_{2}O**

**Calculate the number of atoms present on the products and reactant side.****In our case, the atoms are already equal, therefore the balanced chemical equation is****MnCO**_{3}+ H_{2}SO_{4}= MnSO_{4}+ CO_{2}+ H_{2}O

**H**_{2}SO_{4} + MnCO_{3 }titration

_{2}SO

_{4}+ MnCO

_{3 }titration

**H _{2}SO_{4} + MnCO_{3} titration is an acid-base titration. Following steps are involved during the titration,**

**Apparatus:**

**Conical flask, burette, dropper, funnel, volumetric flask and measuring cylinder.**

**Indicator:**

**Phenolphthalein is used as an indicator since its acid versus base titration.**

**Procedure:**

**Prepare a standardized solution of H**_{2}SO_{4 }and then fill the burette with it.**Take MnCO**_{3}in a conical flask and add 2-3 drops of phenolphthalein to it.**Titrate the solution by adding H**_{2}SO_{4}to the conical flask in a dropwise manner.**Note the reading of the burette when colour of the solution changes from pink to colourless.****Repeat the experiment to get more concurrent readings.**

**H**_{2}SO_{4} + MnCO_{3} net ionic equation

_{2}SO

_{4}+ MnCO

_{3}net ionic equation

**H _{2}SO_{4} + MnCO_{3} reaction net ionic equation is**

**MnCO _{3} (s) + 2H^{+ }(aq.) = Mn^{2+} (aq.) + CO_{2} (g) + H_{2}O (l)**

**Write the general balanced chemical equation for the given reaction****MnCO**_{3}+ H_{2}SO_{4}= MnSO_{4}+ CO_{2}+ H_{2}O**Mention the chemical state of each compound involved in the equation****MnCO**_{3}(s) + H_{2}SO_{4}(aq.) = MnSO_{4}(aq.) + CO_{2}(g) + H_{2}O (l)**Split strong electrolytes into their ions into both sides of chemical equation****MnCO**_{3}(s) + 2H^{+ }(aq.) + SO_{4}^{–}(aq.) = Mn^{2+}(aq.) + SO_{4}^{–}(aq.) + CO_{2}(g) + H_{2}O (l)**Cancel out the spectator ions, which in our case is SO**_{4}^{–}to obtain the net ionic equation**MnCO**_{3}(s) + 2H^{+ }(aq.) = Mn^{2+}(aq.) + CO_{2}(g) + H_{2}O (l)

**H**_{2}SO_{4} + MnCO_{3} conjugate pairs

_{2}SO

_{4}+ MnCO

_{3}conjugate pairs

**The conjugate pairs of H _{2}SO_{4} + MnCO_{3} reaction are**,

**H**_{2}SO_{4}and its conjugate base HSO_{4}^{–}.**H**_{2}O and its conjugate base OH_{}^{–}.

**H**_{2}SO_{4} + MnCO_{3} intermolecular forces

_{2}SO

_{4}+ MnCO

_{3}intermolecular forces

**H _{2}SO_{4} + MnCO_{3} reaction has the following intermolecular forces,**

**The intermolecular force present in H**_{2}SO_{4}is hydrogen bonding. That is why sulphuric acid is readily soluble in water.**H**_{2}O also contains intermolecular and intramolecular hydrogen bonding.**London dispersion forces are present in CO**_{2}molecules.

**H**_{2}SO_{4} + MnCO_{3} reaction enthalpy

_{2}SO

_{4}+ MnCO

_{3}reaction enthalpy

**H _{2}SO_{4} + MnCO_{3} reaction enthalpy is 260.54 kJ/mol. Standard enthalpy of formation of compounds involved in the reaction are:**

Molecules | Reaction enthalpy (in kJ/mol) |
---|---|

H_{2}SO_{4} | -909.27 |

MnCO_{3} | -1095.8 |

MnSO_{4} | -1065.2 |

H_{2}O | -285.8 |

CO_{2} | -393.5 |

**Reaction enthalpy of compounds**

**Δ _{f}H: Standard enthalpy of formation of products – Standard enthalpy of formation of reactants**

**Δ _{f}H: -1065.2 -285.8 -393.5 – (-1095.8 -909.27)**

**Δ _{f}H: 260.54 kJ/mol.**

**Is H**_{2}SO_{4} + MnCO_{3} a buffer solution

_{2}SO

_{4}+ MnCO

_{3}a buffer solution

**H _{2}SO_{4} + MnCO_{3} reaction is not a buffer solution because H_{2}SO_{4 }is a strong acid and there can only be present a weak acid or base in a buffer solution.**

**Is H**_{2}SO_{4} + MnCO_{3} a complete reaction

_{2}SO

_{4}+ MnCO

_{3}a complete reaction

**H _{2}SO_{4} + MnCO_{3} reaction is a complete reaction and products like manganese (II) sulphate (MnSO_{4}), carbon dioxide (CO_{2}) and water are formed after the completion of the reaction.**

**Is H**_{2}SO_{4} + MnCO_{3} an exothermic or endothermic reaction

_{2}SO

_{4}+ MnCO

_{3}an exothermic or endothermic reaction

**The H _{2}SO_{4} + MnCO_{3} reaction is an endothermic reaction because reaction enthalpy has a positive value here.**

**Is H**_{2}SO_{4} + MnCO_{3} a redox reaction

_{2}SO

_{4}+ MnCO

_{3}a redox reaction

**H _{2}SO_{4} + MnCO_{3} reaction is not a redox reaction because there is no change in the oxidation states of atoms involved during the reaction.**

**Is H**_{2}SO_{4} + MnCO_{3} a precipitation reaction

_{2}SO

_{4}+ MnCO

_{3}a precipitation reaction

**H _{2}SO_{4} + MnCO_{3} reaction is not a precipitation reaction as no precipitates are formed during the progression of the reaction.**

**Is H**_{2}SO_{4} + MnCO_{3} reversible or irreversible reaction

_{2}SO

_{4}+ MnCO

_{3}reversible or irreversible reaction

**H _{2}SO_{4} + MnCO_{3} reaction is an irreversible reaction because the CO_{2} gas evolved can not be added back into the reaction mixture.**

**Is H**_{2}SO_{4} + MnCO_{3} displacement reaction

_{2}SO

_{4}+ MnCO

_{3}displacement reaction

**H _{2}SO_{4} + MnCO_{3} reaction is a double displacement reaction followed by dissociation reaction.**

**Conclusion**

In the end, we can conclude that H_{2}SO_{4} is a strong dehydrating agent that removes water from reactants and acts as a strong acid. The manganese sulphate produced has several practical uses.The reaction follows double displacement to attain its products.