H_{2}SO_{4} is categorized as a strong acid. Let us discuss what will happen when H_{2}SO_{4 }reacts with Li_{2}CO_{3}.

**H _{2}SO_{4}, also known as sulphuric acid, has a molecular mass of 98 g/mol and is a colorless, odorless liquid that is miscible with water. A soft alkali metal with antimanic characteristics is Li_{2}CO_{3}. It looks like a white powder. **

Let us discuss the product formed when H_{2}SO_{4 }reacts with Li_{2}CO_{3}, the type of reaction, the net ionic equation and many other related topics in this article.

## What is the product of H_{2}SO_{4} and Li_{2}CO_{3}?

**Sulphuric acid reacts with lithium carbonate to give lithium sulphate, carbon dioxide and water.**

**H _{2}SO_{4} + Li_{2}CO_{3} = Li_{2}SO_{4} + CO_{2} +H_{2}O**

## What type of reaction is H_{2}SO_{4} + Li_{2}CO_{3}?

**H _{2}SO_{4} + Li_{2}CO_{3} is an acid-base reaction because salt and water are produced when strong acid and weak base interact.**

## How to balance H_{2}SO_{4} + Li_{2}CO_{3}?

**The following steps need to be followed while balancing a chemical equation.**

**Given below is an unbalanced chemical reaction of H**,_{2}SO_{4 }and Li_{2}CO_{3}

**H _{2}SO_{4} + Li_{2}CO_{3} = Li_{2}SO_{4} + CO_{2} +H_{2}O**

**Record the moles of each element on the reactant and product sides.**

Element | Reactant | Product |

Li | 2 | 2 |

S | 1 | 1 |

O | 7 | 7 |

C | 1 | 1 |

H | 2 | 2 |

**No. of moles of reactant and product**

**Now, the number of moles present on each side of the reactant and product must be equal in order to balance the chemical equation. In this case, the number of moles in each element is same.****Finally, the balanced chemical equation is**,

**H _{2}SO_{4} + Li_{2}CO_{3} = Li_{2}SO_{4} + CO_{2} +H_{2}O**

## H_{2}SO_{4 }+ Li_{2}CO_{3} titration

**The information below will provide a general idea of the titration of H _{2}SO_{4} and Li_{2}CO_{3}.**

### Apparatus Used

**Volumetric flask, conical flask, measuring jar, wash bottle, pipette, burette, burette stand, and watch glass.**

### Indicator

**The phenolphthalein or methyl orange indicator can be used because it is a strong acid versus weak base reaction, and its endpoint is pink to colorless.**

### Procedure

**Standardized H _{2}SO_{4 }is added to the burette, and Li_{2}CO_{3} is placed in a conical flask. Titration is then started by adding drops of H_{2}SO_{4} one at a time, and an indicator is added in the middle. Titration is continued until the solution turns colorless. **

It is the equivalence point; record the readings, and use the formula V_{1}S_{1}=V_{2}S_{2} to calculate the volume of Li_{2}CO_{3}.

## H_{2}SO_{4} + Li_{2}CO_{3 }net ionic equation

**The net ionic equation for the reaction of H _{2}SO_{4} + Li_{2}CO_{3}**

**is:**

**CO _{3}^{2-} + 2H^{+} = CO_{2} + H_{2}O**

## H_{2}SO_{4} + Li_{2}CO_{3 }conjugate pairs

**The conjugate acid-base pairs** **of H _{2}SO_{4} + Li_{2}CO_{3} are**:

**H**_{2}SO_{4}(Conjugate base) = HSO_{4}^{–}**H**_{2}O (Conjugate base) = OH^{–}

## Is H_{2}SO_{4 }+ Li_{2}CO_{3} a buffer solution?

**H _{2}SO_{4} + Li_{2}CO_{3} is not a buffer solution due to the presence of the strong acid H_{2}SO_{4}. **

## Is H_{2}SO_{4} + Li_{2}CO_{3} a complete reaction?

**H _{2}SO_{4} + Li_{2}CO_{3 }is a complete reaction**

**since all of the reactant’s moles are completely converted and consumed by the product at equilibrium**.

## Is H_{2}SO_{4} + Li_{2}CO_{3} an exothermic or endothermic reaction?

**The reaction between H _{2}SO_{4 }and Li_{2}CO_{3} is exothermic as the energy generated during the reaction is sufficient to carry out the entire reaction. There is no requirement for extra energy.**

## Is H_{2}SO_{4} + Li_{2}CO_{3} a redox reaction?

**H _{2}SO_{4} + Li_{2}CO_{3} is not a redox reaction because there is no change in the oxidation state of any element either in the reactant or product side.**

**2H ^{+} + SO_{4}^{2-} + 2Li^{+ }+ CO_{3}^{2-} = 2Li^{+} + SO_{4}^{2-} + CO_{2} + H_{2}O**

## Is H_{2}SO_{4 }+ Li_{2}CO_{3} a precipitation reaction?

** H _{2}SO_{4} + Li_{2}CO_{3} is a precipitation reaction as the reaction involves the formation of a salt. **

## Is H_{2}SO_{4} + Li_{2}CO_{3 }reversible or irreversible reaction?

**H _{2}SO_{4} + Li_{2}CO_{3} is irreversible because the products no longer undergo backward reactions to form reactants under the same conditions.**

## Is H_{2}SO_{4} + Li_{2}CO_{3} displacement reaction

** H_{2}SO_{4} and Li_{2}CO_{3} is a double displacement reaction because the sulfate ion is transferred from H_{2}SO_{4} to Li_{2}SO_{4} and the carbonate ion is transferred from Li_{2}CO_{3} to CO_{2}.**

#### Conclusion

One of the processes that produces Li_{2}SO_{4}, which has a variety of uses in labs, is the reaction between Li_{2}CO_{3} and H_{2}SO_{4}.