15 Facts on H2SO4 + KI: What, How to Balance & FAQs

H2SO4 (Sulphuric acid) is the strong acid and KI (Potassium iodide) is a white crystalline powder. Let us know some facts about the H2SO4 + KI.

Sulphuric acid is also known as oil of vitriol. It is colorless, odorless viscous liquid. Potassium iodide composed with the elements Potassium and Iodine. It is an ionic compound.

In this article we will discuss about the reaction between Sulphuric acid and Potassium Iodide, balancing of equation, type of reaction and net ionic equation of the reaction.

What is the product of H2SO4 and KI

Potassium bisulfate (KHSO4), Iodine (I2), Sulfur dioxide (SO2) and Water (H2O) are produced in the reaction between Sulphuric acid and potassium iodide.

3H2SO4 + 2KI = 2KHSO4 + I2 + SO2 + 2H2O

What type of reaction is H2SO4 + KI

H2SO4 + KI is a redox reaction.

How to balance H2SO4 + KI

The reaction H2SO4 + KI is balanced using following steps-

H2SO4 + KI = KHSO4 + I2 + SO2 + H2O

  • The number of atoms present on both sides is counted which should be the same.
Reactant SideProduct Side
2-Hydrogen atom3-Hydrogen atom
4-Oxygen atom7-Oxygen atom
1-Sulphur atom2-Sulphur atom
1-Iodine atom2-Iodine atom
1-Potasium atom1-Potasium atom
Table representing number of atoms present in reactant side and product side
  • The number of Oxygen atoms of both the sides of the reaction balance by adding coefficient 3 to the Sulphuric acid molecule at the reactant side.
  • 3H2SO4 + KI = KHSO4 + I2 + SO2 + H2O
  • The number of Hydrogen atoms of both sides of the reaction balance by adding coefficient 2 to the Water molecule at product side.
  • 3H2SO4 + KI = KHSO4 +I2 + SO2 + 2H2O
  • The number of Suphur atoms of both sides of the reaction balance by adding coefficient 2 to the Potassium bisulfate molecule at product side.
  • 3H2SO4 + KI = 2KHSO4 + I2 + SO2 + 2H2O
  • The number of Iodine atoms of both sides of the reaction balance by adding coefficient 2 to the Potassium iodide molecule at reactant side.
  • 3H2SO4 + 2KI = 2KHSO4 + I2 + SO2 + 2H2O
  • So the balanced chemical reaction is:
  • 3H2SO4 + 2KI = 2KHSO4 + I2 + SO2 + 2H2O

H2SO4 + KI Titration

H2SO4 + KI do not undergo titration because there is no equivalence point.

H2SO4 + KI net ionic equation

The net ionic equation for the reaction H2SO4 + KI is

6H+ + SO42- = 2H+ + SO2 + 2H2O

This net ionic equation is derived using the steps mentioned below

  • The balanced equation with phases for H2SO4 + KI
  • 3H2SO4(aq) + 2KI(aq) = 2KHSO4(aq) + I2(aq) + SO2(g) + 2H2O(l)
  • Then the equation written in splitting of compounds
  • 6H++3SO42- + 2K+ + 2I = 2K+ + 2H+ + 2SO42- +  2I + SO2 + 2H2O
  • The net ionic equation is as follows by removing the spectator ions (ions that are same both on reactant and product sides)
  • 6H+ + SO42- = 2H+ + SO2 + 2H2O

H2SO4 + KI conjugate pairs

The conjugate pairs of H2SO4 + KI are as follows:

  • The conjugate base of H2SO4 is SO42-
  • The conjugate base of KI is I

H2SO4 and KI Intermolecular forces

Intermolecular forces present in H2SO4 + KBr are as follows:

  • Hydogen bonding, dipole-dipole interaction and Van der Waals dispersion are the intermolecular forces in H2SO4.
  • Potassium iodide is ionicaly bonded to each other.

H2SO4 + KI reaction enthalpy

The reaction enthalpy of H2SO4 + KI is -439.68 KJ/mol.

CompoundsMolesEnthalpy of formation, ΔH0f (KJ/mol)
H2SO43-814
KI2-125.52
KHSO42-1163.3
I2162.42
SO21-296.9
H2O2-285.82
Bond enthalpy values
  • The standard enthalpy of a reaction is calculated using the formula:
  • ΔH0f (reaction) = ΣΔH0f (product) – ΣΔH0f (reactants)
  • Thus, Enthalpy change = [2*(-1163.3) + 1*(62.42) + 1*(-296.9) + 2*(-285.82)] – [3*(-814.0) + 2*(-125.52)]
  • = [(-3132.72) – (-2693.04)] KJ/mol
  • = -439.68 KJ/mol

Is H2SO4 + KI a buffer solution

H2SO4 + KI reaction will not form a buffer solution because Sulphuric acid (H2SO4) is a strong acid and there can only be present a weak acid or base in buffer solution.

Is H2SO4 + KI a complete reaction

H2SO4 + KI is a complete reaction and the products like Potassium hydrogen sulphate, Iodine, sulphur dioxide and water are formed after completion of the reaction.

Is H2SO4 + KI an exothermic or endothermic reaction

H2SO4 + KI is an exothermic reaction because it shows negative enthalpy -439.68 KJ/mol.

Is H2SO4 + KI a redox reaction

H2SO4 + KI is a redox reaction due to change in oxidation state of sulphur and Iodine ions on reactant and product side.

3H2S6+O4 + 2KI1- = 2KHSO4 +I20 + S4+O2 + 2H2O

Is H2SO4 + KI a precipitation reaction

H2SO4 + KI reaction is not a precipitation reaction because no precipitate is formed during the reaction.

Is H2SO4 + KI a reversible or irreversible reaction

H2SO4 + KI is an irreversible reaction because the products formed do not react to give back reactants under the same condition.

Is H2SO4 + KI a displacement reaction

H2SO4 + KI is a Single displacement reaction, in which sulphate ion is displaced from H2SO4 molecule to form Potassium hydrogen sulfate.

3H2SO4 + 2KI = 2KHSO4 + I2 + SO2 + 2H2O

webp displacement
Displacement of ion

Conclusion

When Sulphuric acid reacts with Potassium iodide it produces Potassium bisulfate, Iodine, sulfur dioxide and water. It is a single displacement reaction, also the redox reaction. It has negative reaction enthalpy hence it is exothermic reaction.