15 Facts on H2SO4 + KBr: What, How to Balance & FAQs

H₂SO₄ (Sulphuric acid) is the strong acid and KBr (Potassium bromide) is a white crystalline powder. Let us know some facts about the H₂SO₄ + KBr.

Sulphuric acid is also known as oil of vitriol. It is colorless, odorless viscous liquid. Potassium bromide composed with the elements Potassium and Bromine. It is an ionic salt also serve as bromide ions.

In this article we will discuss the reaction between Sulphuric acid and Potassium bromide, balancing of equation, type of reaction and net ionic equation of the reaction.

What is the product of H₂SO₄ and KBr

Potassium bisulfate (KHSO₄), bromine (Br₂), sulfur dioxide (SO₂) and water (H₂O) are produced in the reaction between Sulphuric acid and potassium bromide.

3H₂SO₄ + 2KBr = 2KHSO₄ +Br₂ + SO₂ + 2H₂O

What type of reaction is H₂SO₄ + KBr

H₂SO₄ + KBr is a redox reaction.

How to balance H₂SO₄ + KBr

The reaction is balanced using following steps:

H₂SO₄ + KBr = KHSO₄ + Br₂ + SO₂ + H₂O

• The number of atoms present on both sides is counted which should be the same.

• The number of Oxygen atoms of both the sides of the reaction is balanced by adding coefficient 3 to the Sulphuric acid molecule at the reactant side.
• 3H₂SO₄ + KBr = KHSO₄ + Br₂ + SO₂ + H₂O
• The number of Hydrogen atoms of both sides of the reaction is balanced by adding coefficient 2 to the Water molecule at product side.
• 3H₂SO₄ + KBr = KHSO₄ + Br₂ + SO₂ + 2H₂O
• The number of Suphur atoms of both sides of the reaction is balanced by adding coefficient 2 to the Potassium bisulfate molecule at product side.
• 3H₂SO₄ + KBr = 2KHSO₄ + Br₂ + SO₂ + 2H₂O
• The number of Bromine atoms of both sides of the reaction is balanced by adding coefficient 2 to the Potassium bromide molecule at reactant side.
• 3H₂SO₄ + 2KBr = 2KHSO₄ + Br₂ + SO₂ + 2H₂O
• So the balanced chemical reaction is:
• 3H₂SO₄ + 2KBr = 2KHSO₄ + Br₂ + SO₂ + 2H₂O

H₂SO₄ + KBr Titration

H₂SO₄ + KBr do not undergo titration because there is no equivalence point.

H₂SO₄ + KBr net ionic equation

The net ionic equation of the reaction H₂SO₄ + KBr is

6H⁺ + SO₄^2- = 2H⁺ + SO₂ + 2H₂O

The net ionic equation is derived using the steps mentioned below

• The balanced equation with phases for H₂SO₄ + Fe₃O₄

• 3H₂SO₄(aq) + 2KBr(aq) = 2KHSO₄(aq) + Br₂(aq) + SO₂(g) + 2H₂O(l)

• Then the equation written in splitting of compounds

• 6H⁺+3SO₄^2- + 2K⁺ + 2Br^– = 2K⁺ + 2H⁺ + 2SO₄^2- + 2Br^– + SO₂ + 2H₂O
• The net ionic equation is as follows by removing the spectator ions (ions those are same on reactant & product sides)
• 6H⁺ + SO₄^2- = 2H⁺ + SO₂ + 2H₂O

H₂SO₄ + KBr conjugate pairs

The conjugate pairs of H₂SO₄ + KBr are as follows:

• The conjugate base of H₂SO₄ is SO₄^2-
• The conjugate base of KBr is Br^–

H₂SO₄ and KBr Intermolecular forces

Intermolecular forces present in H₂SO₄ + KBr are as follows:

• Hydogen bonding, dipole-dipole interaction and Van der Waals dispersion are the intermolecular forces in H₂SO₄.
• Potassium bromide is ionicaly bonded to each other.

H₂SO₄ + KBr reaction enthalpy

The reaction enthalpy of H₂SO₄ + KBr is -362.07 KJ/mol.

• The standard enthalpy of a reaction is calculated using the formula:
• ΔH⁰_{f (reaction)} = ΣΔH⁰_{f (product)} – ΣΔH⁰_{f (reactants)}
• Thus, Enthalpy change =[2*(-1163.3) + 1*(30.91) + 1*(-296.9) + 2*(-285.82)] – [3*(-814.0) + 2*(-180.08)] = [(-3164.23) – (2802.16)]
• = -362.07 KJ/mol

Is H₂SO₄ + KBr a buffer solution

H₂SO₄ + KBr reaction will not form a buffer solution because Sulphuric acid is a strong acid and there can only be present a weak acid or base in buffer solution.

Is H₂SO₄ + KBr a complete reaction

H₂SO₄ + KBr is a complete reaction and the products like Potassium hydrogen sulphate, bromine, sulphur dioxide and water are formed after completion of the reaction.

Is H₂SO₄ + KBr an exothermic or endothermic reaction

H₂SO₄ + KBr is an exothermic reaction because it shows negative enthalpy -362.07 KJ/mol.

Is H₂SO₄ + KBr a redox reaction

 H₂SO₄ + KBr is a redox reaction due to change in oxidation state of sulphur and bromine ions on reactant and product side as shown below.

3H₂S⁶⁺O₄ + 2KBr^1- = 2KHSO₄ +Br₂⁰ + S⁴⁺O₂ + 2H₂O

Is H₂SO₄ + KBr a precipitation reaction

H₂SO₄ + KBr reaction is not a precipitation reaction because no precipitate is formed during the reaction.

Is H₂SO₄ + KBr a reversible or irreversible reaction

H₂SO₄ + KBr is an irreversible reaction because the products potassium bisulfate, bromine, sulphur dioxide and water are formed, which do not react to give back reactants under the same condition.

Is H₂SO₄ + KBr a displacement reaction

H₂SO₄ + KBr is a single displacement reaction, in which sulphate ion is displaced from H₂SO₄ molecule to form Potassium hydrogen sulfate.

3H₂SO₄ + 2KBr = 2KHSO₄ + Br₂ + SO₂ + 2H₂O

How to balance KBrO₃ + KBr +H₂SO₄ = K₂SO₄ + Br₂ + H₂O

The reaction is balanced using following steps.

KBrO₃ + KBr + H₂SO₄ = K₂SO₄ + Br₂ + H₂O

• The number of atoms present on both sides is counted which should be the same.

• The number of Oxygen atoms of both the sides of the reaction balance by adding coefficient 3 to the Sulphuric acid molecule at the reactant side and Dipotassium sulphate at product side.
• KBrO₃ + KBr + 3H₂SO₄ = 3K₂SO₄ + Br₂ + H₂O
• The number of Hydrogen atoms of both sides of the reaction balance by adding coefficient 3 to the Water molecule at product side.
• KBrO₃ + KBr + 3H₂SO₄ = 3K₂SO₄ + Br₂ + 3H₂O
• The number of Bromine atoms of both sides of the reaction balance by adding coefficient 5 to the Potassium bromide molecule at reactant side and 3 to the bromide molecule at product side.
• KBrO₃ + 5KBr + 3H₂SO₄ = 3K₂SO₄ + 3Br₂ + 3H₂O
• So the balanced chemical reaction is:
• KBrO₃ + 5KBr + 3H₂SO₄ = 3K₂SO₄ + 3Br₂ + 3H₂O

Conclusion

When Sulphuric acid reacted with Potassium bromide it produced Potassium bisulfate, bromine, sulfur dioxide and water. It is a single displacement reaction, also the redox reaction. It founds negative reaction enthalpy hence it is exothermic reaction.