CsOH is an alkali hydroxide with pKa of 15.76 that shows its strong basic nature. H2SO4 is oily liquid soluble in H2O with the release of heat. Let us see how it reacts with H2SO4.
CsOH is water soluble and very reactive as it donates OH–easily. It acts as a base (pH=10.86) and reacts with acid at a high reaction rate. CsOH is used in fuel cells as an electrolyte. H2SO4, an oxidizing agent, is known as the oil of vitriol. It is a strong acid due to its ease of H+ emit.
We will discuss here some important facts about the H2SO4 + CsOH reaction, like the products of the reaction, the enthalpy, intermolecular forces between their compounds, and the mechanism behind the reaction.
What is the product of H2SO4 + CsOH?
Cesium sulfate (Cs2SO4) and water (H2O) are formed in the reaction CsOH + H2SO4 in which CsSO4 is the major product.
2CsOH + H2SO4 → Cs2SO4 + 2H2O
What type of reaction is H2SO4 + CsOH
H2SO4 + CsOH is precipitation, Acid-base, Double displacement (Metathesis), and Endothermic Reaction.
How to balance H2SO4 + CsOH
The unbalanced molecular equation for H2SO4 + CsOH is.
CsOH (aq) + H2SO4 (aq) = Cs2SO4 (aq) + H2O (l)
To balance this equation, we should follow the steps given below:
- Here, the number of Cs and H atoms is not the same on both sides of the reaction. So we will multiply these atoms with some coefficients so that they become equal.
- The total number of Cs and H atoms, on the reactant side is 1 and 3 respectively while on the product side is 2 and 2 respectively.
- So, we multiply the CsOH with a coefficient of 2 on the reactant side and H2O with a coefficient of 2 also on the product side. So the number of Cs and H atoms becomes 2 and 4 on both sides of the reaction, respectively.
- Finally, the balanced equation is
- 2CsOH (aq) + H2SO4 (aq) = Cs2SO4 (aq) + 2H2O (l)
H2SO4 + CsOH titration
Quantitative estimation of H2SO4 is done by performing the titration of the H2SO4 solution against a basic solution of CsOH. For titration, the following procedure is carried out.
Apparatus used
A burette, Pipette, measuring flask, glass funnel, clamp stand, measuring cylinder, volumetric flask, and beakers are required for this titration.
Indicator
Phenolphthalein is used as an indicator for this titration because this reaction is an acid-base reaction.
Procedure
- A standard amount of CsOH solution is filled into the burette and ensures that the interior portion of the burette is coated with a thin layer of CsOH solution.
- The dilute solution of H2SO4 is taken into a conical flask with the help of a pipette and a few drops of phenolphthalein are added to this acidic solution.
- CsOH is released very carefully in a dropwise manner into the conical flask and keeps constant shaking of the flask gently as CsOH starts reacting with the acid solution.
- Add CsOH into the H2SO4 solution until the pink color comes. The procedure is repeated at least three times until a constant endpoint comes.
- After the successful titration, the strength of sulfuric acid and the quantity of sulfate ions will be measured by the formula V1N1 = V2N2.
H2SO4 + CsOH net ionic equation
The net chemical ionic equation of H2SO4 + CsOH is:
2H+(aq) + 2OH– (aq) = H2O (l)
To get this ionic equation we should follow the steps given below.
- Write the solubility equation for CsOH + H2SO4 by labeling the state or phase (s, l, g or aq) of each substance in the balanced equation of H2SO4 + CsOH
- 2CsOH (aq) + H2SO4 (aq) = Cs2SO4 (aq) + 2H2O (l)
- Break all aquatic soluble ionic substances into their corresponding ions to get the complete ionic equation
- 2Cs+(aq) +2OH– (aq) + 2H+ (aq) + SO42- (aq) = H2O (l) + 2Cs+ (aq) + SO42- (aq)
- Then remove spectator ions (SO42- and Cs+) from L.H.S and R.H.S of the complete ionic equation.
- Finally, the net ionic equation is:
- 2H+(aq) + 2OH– (aq) = H2O (l)
H2SO4 + CsOH conjugate pairs
The conjugate pairs of reactant and product in the H2SO4 + CsOH reaction is as follows:
- The conjugate base of H2SO4 is HSO4–
- The conjugate base of H2O is OH–
- Cs2SO4 and CsOH do not have any conjugate pairs (acid and base) because hydrogen is not present in both these elements so it can release in the proton form.
H2SO4 + CsOH intermolecular forces
The reactants and products in H2SO4 + CsOH reaction are held with each other by following intermolecular forces.
- Van der Waals dispersion forces, dipole-dipole interactions, and hydrogen bonding are exhibited in the H2SO4 molecules as H2SO4 molecules are highly polar with a 2.725 D dipole moment.
- Electrostatic force or Coulomb force is present in the Cs2SO4 molecules due to their ionic nature.
- Hydrogen bonding exists in the H2O molecules.
H2SO4 + CsOH reaction enthalpy
The total enthalpy for the reaction H2SO4 + CsOH is 368.66 kJ/mol. The enthalpy of the formation is calculated using the values given below.
| Compound | Standard Formation Enthalpy (ΔfH°(Kj/mol) ) |
|---|---|
| CsOH | -416 |
| H2SO4 | -814 |
| Cs2SO4 | -1443 |
| H2O | -285.83 |
- ΔH°f = ΣΔH°f (products) – ΣΔH°f (reactants) (kJ/mol)
- ΔHf = [2*(-416) – 814) – (-1443 – 2*(285.83)) kJ/mol
- ΔHf = 368.66 kJ/mol
H2SO4 + CsOH a buffer solution
The reaction H2SO4 + CsOH provides a buffer solution of Cs2SO4 and water which resist the change in its pH value if we add acid or base to it.
Is H2SO4 + CsOH a complete reaction
H2SO4 + CsOH is a complete reaction because in this reaction H2SO4 completely neutralizes CsOH molecules in its corresponding salt Cs2SO4.
Is H2SO4 + CsOH an exothermic or endothermic reaction
H2SO4 + CsOH is an endothermic reaction as the total enthalpy change for the reaction is 368.66 kJ/mol which is positive, where the positive sign explains the following facts about the reaction.
- The reactants H2SO4 and CsOH absorb the heat from the surrounding atmosphere which lowers the temperature of the surroundings and ultimately the reaction system gets cool.
- Products ( CsSO4 and H2O ) exhibit higher energy than reactants and become unstable during the reaction.
Is H2SO4 + CsOH a redox reaction
H2SO4 + CsOH is not a redox reaction because the oxidation states of each element remain the same even after the completion of the reaction.
Cs +1 O -2 H +1 + H2+1 S +6 O4 -2 → Cs2 +1 S +6 O4 -2 + 2 H2+1 O -2
Is H2SO4 + CsOH a precipitation reaction
H2SO4 + CsOH is not a precipitation reaction because all the products (H2O and Cs2SO4) formed are in liquid and aqueous states.
Is H2SO4 + CsOH reversible or irreversible reaction
H2SO4 + CsOH is an irreversible reaction because, at the same reaction conditions, it is not possible to get reactants back from the products.
Is H2SO4 + CsOH displacement reaction
H2SO4 + CsOH is a double displacement reaction because Cs from Cs(OH) and H from H2SO4 displace each other’s positions to form different products- Cs2SO4 and H2O.
Conclusion
H2SO4 + CsOH is an acid-base reaction in which H2SO4 acts as a strong acid and CsOH as a base. In this reaction, 368.66 kJ/mol energy is consumed by the reactants to form cesium hydroxide. During this reaction, the transfer of electrons does not take place, hence this reaction does not follow to redox process.
Hi, I am Kavita Singhal, Ph.D. in Chemical Sciences. My subject area of interest is Physical and Inorganic Chemistry with special emphasis on Electrochemistry, Polymer Chemistry, Nano Chemistry, Corrosion Study, Cyclic voltammetry, Supercapacitance, and Organometallic Chemistry.
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