In a chemical reaction chemical symbols are used to denote reactant and product. Let us discuss about the reaction of H2SO4 and CH3COONa.
Sulphuric acid or H2SO4 is a strong acid and sodium acetate, CH3COONa is a sodium salt if acetic acid. Both dissociate in water to give respective ions and are soluble in water. Sodium acetate is a colorless substance which is deliquescent in nature. It’s crystal structure is monoclinic.
Sodium acetate is a buffering agent with molar mass 82.034 g/mol. Let us discuss about H2SO4+ CH3COONa with all details.
What is the product of H2SO4 and CH3COONa
H2SO4 reacts with CH3COONa to give acetic acid and sodium hydrogen sulphate.
H2SO4 + CH3COONa ——–> CH3COOH + NaHSO4
What type of reaction is H2SO4 + CH3COONa
H2SO4 + CH3COONa is a displacement reaction. In this reaction sodium is displaced from sodium acetate by hydrogen of H2SO4 to yield the products.
How to balance H2SO4 + CH3COONa
Balancing a chemical reaction is needed and it gives information about the number of molecules reacted. Following is the reaction balancing steps.
- Assigning certain coefficients to both reactants and products
- a H2SO4 + b CH3COONa —–> c CH3COOH + d NaHSO4
- An equation is made with the above equation
- H= 2a= 3b =4c = d, S =a =d, O =4a= 2b = 2c= 4d, C =2b =2c, Na = b= d
- 2a +3b= 4c +d, a=d, 4a+ 2b=2c+ 4d, 2b=2c, b =d
- Solve the above equation using gauss elimination method
- a =1, b= 1, c= 1, d= 1
- The balanced equation of H2SO4 + CH3COONa is
- H2SO4 + CH3COONa —–> CH3COOH + NaHSO4
H2SO4 + CH3COONa titration
H2SO4 + CH3COONa titration can be performed. It is because one is strong acid and other one is a weak base. So they can be titrated against to get the endpoint sharply.
Conical flask, pipette, burette, H2SO4 and CH3COONa solution.
Methyl orange is used because we are titrating strong acid and weak base
- 20 ml of sodium acetate solution is pipetted into a conical flask and burette is filled with H2SO4.
- Methyl orange indicator is added into the solution in conical flask until it turns into a yellow color.
- Titrate the solution against sulphuric acid in burette until the color changes from yellow to red color.
- Note down the burette reading and do the respective calculations.
H2SO4 + CH3COONa net ionic equation
The net ionic equation of H2SO4 and CH3COONa is,
2H+ + SO2-4 + CH3COO– ——> 2CH3COOH + HSO–4 .
H2SO4 and CH3COONa conjugate Pairs
H2SO4 + CH3COONa reaction has the following conjugate pairs,
- The conjugate pairs of H2SO4 and CH3COONa is HSO–4 and CH3COOH respectively.
- Both are acids so one of the proton is eliminated to get its conjugate base.
H2SO4 and CH3COONa intermolecular forces
The intermolecular forces exist in between H2SO4 + CH3COONa is
- In H2SO4 there is ionic force of attraction can be seen in between H+ ion and SO42- .
- In CH3COONa ionic force between sodium and acetate, dipole dipole interaction between carbon and oxygen and pure covalent bonds between carbon and hydrogen.
H2SO4 + CH3COONa reaction enthalpy
The reaction enthalpy of H2SO4 + CH3COONa is positive. The enthalpy of formation of H2SO4, CH3COOH, and CH3COONa is -814, -491, and -24.6 kJ/mol respectively.
Is H2SO4 + CH3COONa a buffer solution
H2SO4 + CH3COONa is not a buffer solution. A buffer solution is made by mixing a weak acid or weak base with its conjugate base or acid respectively. Here H2SO4 a strong acid. But CH3COONa is a weak acid it’s buffer can be prepared by mixing with its conjugate acid like CH3COOH to get its buffer solution.
Is H2SO4 + CH3COONa a complete reaction
H2SO4 + CH3COONa is a complete reaction. The reaction takes place at room temperature to yield acetic acid and sodium hydrogen sulphate. Here sulphuric acid displaces weaker ions from its salts.
Is H2SO4 + CH3COONa an exothermic or endothermic reaction
H2SO4 + CH3COONa is an endothermic reaction. The reaction doesn’t liberate any amount of heat. So it is an endothermic reaction.
Is H2SO4 + CH3COONa a redox reaction
H2SO4 + CH3COONa is not a redox reaction as the oxidation state of all the atoms are same before and after the reaction.
Is H2SO4 + CH3COONa a precipitation reaction
H2SO4 + CH3COONa is reaction doesn’t form any precipitate. Acetic acid and sodium hydrogen sulphate is the product formed here and both are liquid like nature.
Is H2SO4 + CH3COONa reversible or irreversible reaction
H2SO4 + CH3COONa is an irreversible reaction as they cant be reversed to yield it’s reactants.
Is H2SO4 + CH3COONa a displacement reaction
H2SO4 + CH3COONa is a Displacement reaction because the weaker ion sodium from sodium acetate is replaced by hydrogen to form acetic acid.
In this article H2SO4 and CH3COONa reacts to sodium hydrogen sulphate and acetic acid. This reaction is found to be a Displacement reaction which is not redox and irreversible while it is endothermic. The reaction does not form any precipitate.