The reaction between H2SO4 and CaCl2 is a reaction that takes place in a boiling solution. Let us discuss this deeply.
H2SO4 is a very strong acid that is a major constituent in oil of vitriol and is an oxidant that acts as a dehydrating agent and helps manufacture lots of fertilizers. CaCl2 is a white-colored powder which is crystalline in nature. CaCl2 is also hygroscopic and helps in road surfacing.
With the help of a completely balanced chemical equation of both reactants, a few facts will be discussed in the article below.
What is the product of H2SO4 and CaCl2
CaSO4(Calcium Sulphate) and HCl (Hydrochloric Acid) are the products which are formed by the reaction of H2SO4 and CaCl2 .
H2SO4 +CaCl2→CaSO4+HCl
What type of reaction is H2SO4 + CaCl2
The reaction of H2SO4 and CaCl2 is a double displacement reaction as a mutual exchange of ions takes place.
How to balance H2SO4 + CaCl2
The equation is balanced using the following steps:
H2SO4 +CaCl2→CaSO4+HCl
- Write the different elements present in the reaction.
- Write the number of atoms of each element on both sides ( reactant and product side)
- Equalise the number of atoms on both sides.
Elements | Number of atoms on reactant side | Number of atoms on reactant side |
H | 2 | 1 |
S | 1 | 1 |
O | 4 | 4 |
Ca | 1 | 1 |
Cl | 2 | 1 |
- The balanced chemical equation is,
- H2SO4 +CaCl2→CaSO4+2HCl
H2SO4 +CaCl2 titration
The titration of H2SO4 + CaCl2 is not possible because the product formed, CaSO4 is insoluble.
H2SO4 + CaCl2 net ionic equation
The net ionic equation for H2SO4 + CaCl2 is
Ca2+(aq) +SO42-(aq)→ CaSO4 (s).
The net ionic equation is deduced using the following steps:
- Write the balanced chemical equation.
- H2SO4+CaCl2→CaSO4+2HCl
- Write the physical state of each compound along with them.
- H2SO4(aq) +CaCl2(aq)→CaSO4(s)+HCl(aq)
- Dissociate the strong electrolytes into their respective ions.
- H2SO4→ 2H ++ SO42-
- CaCl2→Ca2++2Cl–
- 2HCl→2H+ +2Cl–
- Remove the spectator ions.
- Ca2+(aq) +SO42-(aq)→ CaSO4 (s)
- Thus the net ionic equation is-
- Ca2+(aq) +SO42-(aq)→ CaSO4 (s).
H2SO4 + CaCl2 conjugate pairs
- H2SO4 has conjugate base pair H2SO4– as it is a strong acid.
- CaCl2 does not have any conjugate pair as it is a salt.
H2SO4 and CaCl2 intermolecular forces
- CaCl2 forms an ionic bond by donating two electrons to chlorine atoms from Calcium atoms.
- H2SO4 has van der Waals dispersion forces, dipole-dipole interactions and hydrogen bonding as intermolecular forces.
H2SO4 + CaCl2 reaction enthalpy
The reaction enthalpy of H2SO4 + CaCl2 is -0.0499 kJ which is very high.
Is H2SO4 +CaCl2 a buffer solution
H2SO4 +CaCl2 is not a buffer solution because H2SO4 is a strong acid whereas a buffer solution always contains a weak acid and its conjugate base or a weak base and its conjugate acid.
Is H2SO4 + CaCl2 a complete reaction
H2SO4 + CaCl2 is a complete reaction because two products exchange their ions to form two different products.
Is H2SO4 + CaCl2 an exothermic or endothermic reaction
H2SO4 + CaCl2 is highly exothermic in nature because ΣΔH°f(reactants) > ΣΔH°f(products), hence a lot of heat energy is released.
Is H2SO4 +CaCl2 a redox reaction
H2SO4 + CaCl2 is not a redox reaction, as oxidation states do not change during the reaction.
Is H2SO4 + CaCl2 a precipitation reaction
H2SO4 + CaCl2 is a precipitation reaction because the product formed- CaSO4 (Calcium Sulphate) is white colored precipitate.
Is H2SO4 + CaCl2 reversible or irreversible reaction
H2SO4 + CaCl2 is an irreversible reaction because the products formed do not go back to the reactant state.
Is H2SO4 + CaCl2 displacement reaction
H2SO4 + CaCl2 is a single displacement reaction precisely because one highly reactive metal- Ca displaces the less reactive element-hydrogen in this reaction.
Conclusion
The products formed, CaSO4 is usually found in gypsum form, and the chemical formula of gypsum is CaSO4.2H2O. It occurs naturally in nature, whereas HCl, also known as muriatic acid, is a very strong acid and has a pungent smell.
Hi….I am Deepali Arora and presently working as a Subject Matter Expert in Chemistry. I have henceforth completed my graduation and post-graduation in life sciences and chemistry respectively. I am highly inquisitive as far as learning and experimental aspects are concerned. I am looking forward to strengthening my career in the same field. I am good at troubleshooting and have a good critical thinking and analytical approach.
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